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First teaching 2023

First exams 2025

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Superposition of Waves (SL IB Physics)

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Superposition of Waves

  • The principle of superposition states that:

When two or more waves meet, the resultant displacement is the vector sum of the displacements of the individual waves 

  • The principle of superposition applies to both transverse and longitudinal waves
  • Interference occurs whenever two or more waves superpose
  • For a clear stationary interference pattern, the waves must be of the same:
    • Type
    • Amplitude
    • Frequency
  • They must also have a constant phase difference

Constructive & Destructive Interference

  • Constructive interference occurs when
    • Two or more waves superpose and have displacements in the same direction (both positive or both negative)
  • Destructive interference occurs when
    • Two or more waves superimpose and have displacements in opposite directions (one positive and one negative)
  • When two waves with the same amplitude meet at a point, they can:
    • Be in phase and interfere constructively, so that the displacement of the resultant wave is double the displacement of each individual wave
    • Be in anti-phase and interfere destructively, so that the displacement of the resultant wave is equal to zero

Constructive and destructive, downloadable AS & A Level Physics revision notes

Waves in superposition can undergo constructive or destructive interference

  • Superposition occurs for any two waves or pulses that overlap and can result in a combination of both constructive and destructive interference
    • For example, the peak of one wave superposes with the peak of another wave with a smaller displacement
    • The resultant peak will have a displacement that is in the middle of the displacement of both waves
  • Superposition can also be demonstrated with two pulses
    • When the pulses meet, the resultant displacement is the algebraic sum of the displacement of the individual pulses
    • After the pulses have interacted, they then carry on as normal

4-3-3-superposition-of-pulses_sl-physics-rn

Worked example

Two overlapping waves of the same types travel in the same direction. The variation with x and y displacement of the wave is shown in the figure below.

Use the principle of superposition to sketch the resultant wave.

Answer:

Worked example - superposition (2), downloadable AS & A Level Physics revision notes

Constructive & Destructive Interference

  • Interference occurs whenever two or more waves combine to produce a resultant wave with a new resultant displacement
    • The waves combine according to the principle of superposition
  • When constructive interference occurs:

Two coherent waves combine by adding their displacements to create a resultant wave with a larger amplitude

  • When destructive interference occurs:

Two coherent waves combine by cancel out their displacements to create a resultant wave with a smaller amplitude

  • The type of interference occurring at a given point (i.e. constructive or destructive) depends on the path difference of the overlapping waves

Path Difference

  • Path difference is defined as:

The difference in distance travelled by two waves from their sources to the point where they meet

  • Path difference is generally expressed in multiples of wavelength

Path Difference, downloadable AS & A Level Physics revision notes

At point P2 the waves have a path difference of a whole number of wavelengths resulting in constructive interference. At point P1 the waves have a path difference of an odd number of half wavelengths resulting in destructive interference 

  • In the diagram above, the number of wavelengths between:
    • S1 ➜ P1 = 6λ
    • S2 ➜ P1 = 6.5λ
    • S1 ➜ P2 = 7λ
    • S2 ➜ P2 = 6λ
  • The path difference is:
    • (6.5λ – 6λ) = lambda over 2 at point P1
    • (7λ – 6λ) = λ at point P2
  • Hence:
    • Destructive interference occurs at point P1
    • Constructive interference occurs at point P2

Conditions for Constructive and Destructive Interference

  • In general, for waves emitted by two coherent sources very close together:
  • The condition for constructive interference is:

path difference = n lambda

  • The condition for destructive interference is:

path difference = open parentheses n space plus thin space 1 half close parentheses lambda

  • Where:
    • λ = wavelength of the waves in metres (m)
    • n = 0, 1, 2, 3... (any other integer)

  • The same conditions apply to waves emitted by a single coherent source and diffracted by two narrow slits very close together

Path Difference and Wavefronts

Path Difference & Interference Pattern, downloadable AS & A Level Physics revision notes

At point P the waves have a path difference of a whole number of wavelengths resulting in constructive interference

  • Another way to represent waves spreading out from two sources is shown in the diagram above
  • At point P, the number of crests from:
    • Source S1 = 4λ
    • Source S2 = 6λ

  • The path difference at P is (6λ – 4λ) =
  • This is a whole number of wavelengths (n = 2), hence constructive interference occurs at point P

Worked example

The diagram below is a snapshot of overlapping wavefronts resulting from the interference of coherent waves diffracted by two narrow slits S1 and S2.  

4-4-6-we-path-difference-question

For each of the points A, B, C, D and E, determine:

  • The path difference from the sources
  • The value of n in the path difference formula
  • Whether they are locations of constructive or destructive interference

Answer:

Step 1: Count the number of wavelengths between each source and the desired point 

  • For example, the number of wavelengths between:
    • S1 ➜ A = 5λ
    • S2 ➜ A = 6.5λ

Step 2: Determine the path difference by subtracting the distances of the point from the two sources 

  • For example, path difference at A = (6.5λ – 5λ) = 1.5λ

Step 3: Compare the path difference calculated in Step 2 with the condition for constructive or destructive interference and give the value of n 

  • For example, path difference at A = 1.5λ = (n + ½)λ  ➜  n = 1

Step 4: Decide whether the point is a location of constructive or destructive interference 

  • For example, at A, destructive interference occurs
  • Point A:
    • Path difference = (6.5λ – 5λ) = 1.5λ
    • n = 1
    • Destructive interference
  • Point B:
    • Path difference = (5λ – 4λ) = λ
    • n = 1
    • Constructive interference
  • Point C:
    • Path difference = (2λ – 2λ) = 0
    • n = 0
    • Constructive interference
  • Point D:
    • Path difference = (5λ – 4.5λ) = 0.5λ
    • n = 0
    • Destructive interference
  • Point E:
    • Path difference = (4λ – 3λ) = λ
    • n = 1
    • Constructive interference

Exam Tip

You are not required to memorise the conditions for constructive and destructive interference, as these are given in the data booklet.

You must be able to determine the path difference of waves from two sources (or two narrow slits) at a given point. You can then compare this with the given conditions for constructive and destructive interference, in order to decide which type of interference occurs at the point you are considering.

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Ashika

Author: Ashika

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.