Syllabus Edition

First teaching 2023

First exams 2025

|

Ideal Gas Equation (SL IB Physics)

Revision Note

Test Yourself
Ashika

Author

Ashika

Expertise

Physics Project Lead

Ideal Gas Equation

  • The empirical gas laws can be combined with Avogadro's law to give a single constant, known as the ideal gas constant, R
  Boyle's Law Charles' Law Pressure Law
relationship P V space equals space c o n s t a n t V space proportional to space T P space proportional to space T
constants T comma space n P comma space n V comma space n

 

  • An ideal gas is defined as:

A gas which obeys the ideal gas equation at all pressures, volumes and temperatures

  • Combining the gas laws leads to the equation of state of an ideal gas:

P V space equals space n R T

  • Where:
    • P = pressure (Pa)
    • V = volume (m3)
    • n = number of moles (mol)
    • R = 8.31 J K–1 mol–1 (ideal gas constant)
    • T = temperature (K)

Constants

  • The ideal gas constant R is the macroscopic equivalent of the Boltzmann constant k subscript B
    • The Boltzmann constant is associated with the thermal energy of microscopic particles
  • The Boltzmann constant is defined as the ratio of the ideal gas constant R and Avogadro's constant NA:

k subscript B space equals space R over N subscript A

  • Recall from the Amount of Substance revision note that N subscript A space equals space N over n
  • This gives another form of the equation of state of an ideal gas:

P V thin space equals space N k subscript B T

  • Where:
    • N = number of molecules
    • kB = 1.38 × 10−23 J K−1 (Boltzmann constant)

Worked example

A gas has a temperature of –55°C and a pressure of 0.5 MPa. It occupies a volume of 0.02 m3.

Calculate the number of gas particles.

Answer:

Step 1: Write down the known quantities

  • Temperature, T = –55°C = 218 K
  • Pressure, p = 0.5 MPa = 0.5 × 106 Pa
  • Volume, V = 0.02 m3

Step 2: Write down the equation of state of ideal gases

P V space equals space n R T

Step 3: Rearrange the above equation to calculate the number of moles n

n space equals fraction numerator space P V over denominator R T end fraction

Step 4: Substitute numbers into the equation

  • From the data booklet, R = 8.31 J K–1 mol–1

n space space equals space fraction numerator open parentheses 0.5 space cross times space 10 to the power of 6 close parentheses space cross times space 0.02 space over denominator 8.31 space cross times space 218 end fraction space equals space 5.5 space moles

Step 5: Calculate the number of particles N

n space equals fraction numerator space N over denominator N subscript A end fraction space space space rightwards double arrow space space space N space equals space n N subscript A

N space equals space 5.5 space cross times space open parentheses 6.02 space cross times space 10 to the power of 23 close parentheses space equals space 3.3 space cross times space 10 to the power of 24

Exam Tip

The values for the gas constant, Avogadro constant and Boltzmann constant are all given in your data booklet.

Always make sure that temperature is in kelvin for this topic. You must convert this from °C if not using the following conversion

theta space divided by space degree C space equals space T space divided by space K space minus space 273
T space divided by space K space equals space theta space divided by space degree C space plus space 273

You've read 0 of your 0 free revision notes

Get unlimited access

to absolutely everything:

  • Downloadable PDFs
  • Unlimited Revision Notes
  • Topic Questions
  • Past Papers
  • Model Answers
  • Videos (Maths and Science)

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Ashika

Author: Ashika

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.