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Electric Potential Energy Equation (HL) (HL IB Physics)

Revision Note

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Work Done on a Charge

  • When a mass with charge moves through an electric field, work is done
  • The work done in moving a charge q is given by:

W = qV

  • Where:
    • W = change in work done (J)
    • q = charge (C)
    • Vchange in electric potential (J C-1)

  • This change in work done is equal to the change in electric potential energy (E.P.E)
    • When V = 0, then the E.P.E = 0

  • The change in E.P.E, or work done, for a point charge q at a distance r1 from the centre of a larger charge Q, to a distance of r2 further away can be written as:

Change in electric potential energy equation

  • Where:
    • Q = charge that is producing the electric field (C)
    • q = charge that is moving in the electric field (C)
    • r1first distance of q from the centre of Q (m)
    • r2 = second distance of q from the centre of Q (m)

Change in Electric Potential Energy, downloadable AS & A Level Physics revision notes

Work is done when moving a point charge away from another charge

  • Work is done when a positive charge in an electric field moves against the electric field lines or when a negative charge moves with the electric field lines

Worked example

The potentials at points R and S due to the +7.0 nC charge are 675 V and 850 V respectively.Work Done Electric Field Worked Example, downloadable AS & A Level Physics revision notesCalculate how much work is done when a +3.0 nC charge is moved from R to S.

Answer:

Step 1: Write down the known quantities

  • p.d. at R, V1 = 675 V
  • p.d. at S, V2 = 850 V
  • Charge, q = +3.0 nC = +3.0 × 10-9 C

Step 2: Write down the work done equation

W = qΔV

Step 3: Substitute in the values into the equation

W = (3.0 × 10-9) × (850 - 675) = 5.3 × 10-7 J

Exam Tip

Remember that q in the work done equation is the charge that is being moved, whilst Q is the charge which is producing the potential. Make sure not to get these two mixed up, as both could be given in the question (like the worked example) and you will be expected to choose the correct one

Electric Potential Energy Equation

Electrical Potential Difference

  • Two points at different distances from a charge will have different electric potentials
    • This is because the electric potential increases with distance from a negative charge and decreases with distance from a positive charge

  • Therefore, there will be an electric potential difference between the two points
    • This is represented by the symbol ΔV

  • Δis normally given as the equation

ΔV = Vf – Vi

  • Where:
    • Vf = final electric potential (J C-1)
    • Vi = initial electric potential (J C-1)

Electrical Potential Energy

  • The electric potential energy Ep at point in an electric field is defined as:

The work done in bringing a charge from infinity to that point

  • The electric potential energy of a pair of point charges Q1 and Q2 is defined by:

 

bold italic E subscript bold p bold space bold equals bold space bold italic k fraction numerator bold Q subscript bold 1 bold Q subscript bold 2 over denominator bold r end fraction

  • Where:
    • Ep = electric potential energy (J)
    • k space equals space fraction numerator 1 over denominator 4 pi epsilon subscript 0 end fraction
    • r = separation of the charges Q1 and Q2 (m)
    • ε0 = permittivity of free space (F m-1)

  • The potential energy equation is defined by the work done in moving point charge Q2 from infinity towards a point charge Q1

Worked example

An alpha particle He presubscript 2 presuperscript 4 is moving directly towards a stationary gold nucleus Au presubscript 79 presuperscript 197.

At a distance of 4.7 × 10−15 m, the alpha particle momentarily comes to rest.

Calculate the electric potential energy of the particles at this instant. 

Answer:

Step 1: Write down the known quantities

  • Distance, r = 4.7 × 10-15 m
  • The charge of one proton = +1.60 × 10-19 C

An alpha particle (helium nucleus) has 2 protons

    • Charge of alpha particle, Q1 = 2 × 1.60 × 10-19 = +3.2 × 10-19 C

   The gold nucleus has 79 protons

    • Charge of gold nucleus, Q2 = 79 × 1.60 × 10-19 = +1.264 × 10-17 C

Step 2: Write down the equation for electric potential energy

Electric Potential Energy of Two Point Charges equation 1a

Step 3: Substitute values into the equation

Electric Potential Energy of Two Point Charges Worked Example equation

Exam Tip

When calculating electric potential energy, make sure you do not square the distance!

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Ann H

Author: Ann H

Ann obtained her Maths and Physics degree from the University of Bath before completing her PGCE in Science and Maths teaching. She spent ten years teaching Maths and Physics to wonderful students from all around the world whilst living in China, Ethiopia and Nepal. Now based in beautiful Devon she is thrilled to be creating awesome Physics resources to make Physics more accessible and understandable for all students no matter their schooling or background.