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Effect of Ligand Exchange on Stability Constant (CIE A Level Chemistry)

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Effect of Ligand Exchange on Stability Constant

  • The stability constants (Kstab) of ligands are often given on a log10 scale so that it becomes easier to compare them with each other
  • Ligand exchange in a complex occurs to form a more stable complex with a larger Kstab
  • The stability constants can be used to explain the substitution of ligands in a copper complex

Ligand substitution in a Co(II) complex

  • When excess ammonia is added to the [CoCl4]2- complex a blue solution is obtained

Ligand exchange of the [CoCl4]2- complex by ammonia

Chemistry of Transition Elements - Formation of Ammonia Complex, downloadable AS & A Level Chemistry revision notes

The chloride ligands are substituted by the ammonia ligands to form the more stable ammonia complex 

  • The formation of the ammonia complex could be explained by comparing the stability of the chloride and ammonia ligands

Stability of chloride and ammonia ligands table

Ligand Stability (log10 Kstab)
Cl 5.6
NH3 13.1

  • The stability constant of the ammonia ligand is greater than that of the chloride ligands
  • The blue ammonia complex is therefore more stable
  • As a result, the position of the equilibrium is shifted to the right

Worked example

The numerical values for the stability constants, Kstab, of three silver(I) complexes are given.

Silver(I) complex Numerical value of Kstab
[Ag(S2O3)2]3– 2.9 x 1013
[Ag(CN)2] 5.3 x 1018
[Ag(NH3)2]+ 1.6 x 107

 
An aqueous solution of Ag+ is added to a solution containing equal concentrations of S2O32– (aq), CN (aq) and NH3 (aq). The mixture is left to reach equilibrium.

Deduce the relative concentrations of [Ag(S2O3)2]3–, [Ag(CN)2] and [Ag(NH3)2]+ present in the equilibrium mixture. Explain your answer.

Answer

  • The highest concentration will be [Ag(CN)2]
    • This is because the Kstab value for [Ag(CN)2] is the largest value
      OR
    • [Ag(CN)2] is the most stable
  • The lowest concentration will be [Ag(NH3)2]+
    • This is because the Kstab value for [Ag(NH3)2]+ is the smallest value
      OR
    • [Ag(NH3)2]+ is the least stable
  • An alternative explanation could be to state that higher Kstab values form a more stable complex

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Richard

Author: Richard

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.