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Solubility Product (CIE A Level Chemistry)

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The Solubility Product, Ksp

  • Solubility is defined as the number of grams or moles of compound needed to saturate 100 g of water, or it can also be defined in terms of 1 kg of water, at a given temperature
    • For example, sodium chloride (NaCl) is considered to be a soluble salt as a saturated solution contains 36 g of NaCl per 100 g of water
    • Lead chloride (PbCl2) on the other hand is an insoluble salt as a saturated solution only contains 0.99 g of PbCl2 per 100 g of water

Solubility product

  • The solubility product (Ksp) is:
    • The product of the concentrations of each ion in a saturated solution of a relatively soluble salt
    • At 298 K
    • Raised to the power of their relative concentrations

C (s) ⇌ aAx+ (aq) + bBy- (aq)

Ksp = [Ax+ (aq)]a [By- (aq)]b

  • When an undissolved ionic compound is in contact with a saturated solution of its ions, an equilibrium is established
  • The ions move from the solid to the saturated solution at the same rate as they move from the solution to the solid
    • For example, the undissolved magnesium chloride (MgCl2) is in equilibrium with a saturated solution of its ions

MgCl2 (s) ⇌ Mg2+ (aq) + 2Cl- (aq)

Ions in a saturated solution

Equilibria - Equilibrium between Ionic Compound and Saturated Solution, downloadable AS & A Level Chemistry revision notes

When the undissolved MgCl2 salt comes in contact with its ions in a saturated solution, an equilibrium between the salt and ions is established

    • The solubility product for this equilibrium is:

Ksp = [Mg2+ (aq)] [Cl- (aq)]2

  • The Ksp is only useful for sparingly soluble salts
  • The smaller the value of Ksp, the lower the solubility of the salt

Ksp Expressions

  • The general equilibrium expression for the solubility product (Ksp) is:

C (s) ⇌ aAx+ (aq) + bBy- (aq)

Ksp = [Ax+ (aq)]a [By- (aq)]b

Worked example

Expressing Ksp of ionic compounds

  • Give the equilibrium expressions, including units, for the solubility products of the following ionic compounds:
    1. Ca(OH)2 
    2. Fe2O3 
    3. SnCO3

Answer 1 - Ca(OH)2:

  • Step 1 - Write the balanced chemical equation:
    • Ca(OH)2 (s) rightwards harpoon over leftwards harpoon Ca2+ (aq) + 2OH (aq)
  • Step 2 - Write the Ksp expression:
    • Ksp = [Ca2+ (aq)] [OH (aq)]2
  • Step 3 - Deduce the units:
    • Ksp = [mol dm-3] x [mol dm-3]2
    • Ksp = [mol dm-3]3
    • Ksp = mol3 dm-9 

Answer 2 - Fe2O3:

  • Step 1 - Write the balanced chemical equation:
    • Fe2O3 (s) rightwards harpoon over leftwards harpoon 2Fe3+ (aq) + 3O2– (aq)
  • Step 2 - Write the Ksp expression:
    • Ksp = [Fe3+ (aq)]2 [O2 (aq)]3
  • Step 3 - Deduce the units:
    • Ksp = [mol dm-3]2 x [mol dm-3]3
    • Ksp = [mol dm-3]5
    • Ksp = mol5 dm-15 

Answer 3 - SnCO3:

  • Step 1 - Write the balanced chemical equation:
    • SnCO3 (s) rightwards harpoon over leftwards harpoon Sn2+ (aq) + CO32– (aq)
  • Step 2 - Write the Ksp expression:
    • Ksp = [Sn2+ (aq)] [CO32 (aq)]
  • Step 3 - Deduce the units:
    • Ksp = [mol dm-3] x [mol dm-3]
    • Ksp = [mol dm-3]2
    • Ksp = mol2 dm-6 

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Philippa

Author: Philippa

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener.