Solving by Completing the Square (Edexcel IGCSE Maths A (Modular))
Revision Note
Written by: Mark Curtis
Reviewed by: Dan Finlay
Solving by Completing the Square
How do I solve a quadratic equation by completing the square?
To solve x2 + bx + c = 0
replace the first two terms, x2 + bx, with (x + p)2 - p2 where p is half of b
This is completing the square
x2 + bx + c = 0 becomes (x + p)2 - p2 + c = 0
(where p is half of b)
rearrange this equation to make x the subject (using ±√)
For example, solve x2 + 10x + 9 = 0 by completing the square
x2 + 10x becomes (x + 5)2 - 52
so x2 + 10x + 9 = 0 becomes (x + 5)2 - 52 + 9 = 0
make x the subject (using ±√)
(x + 5)2 - 25 + 9 = 0
(x + 5)2 = 16
x + 5 = ±√16
x + 5 = ±4
x = -5 ±4
x = -1 or x = -9
It also works with numbers that lead to surds
The answers found will be in exact (surd) form
Examiner Tips and Tricks
When making x the subject to find the solutions, don't expand the squared bracket back out again!
Remember to use ±√ to get two solutions
How do I solve by completing the square when there is a coefficient in front of the x2 term?
If the equation is ax2 + bx + c = 0 with a number (other than 1) in front of x2
you can divide both sides by a first (before completing the square)
For example 3x2 + 12x + 9 = 0
Divide both sides by 3
x2 + 4x + 3 = 0
Complete the square on this easier equation
This trick only works when completing the square to solve a quadratic equation
i.e. it has an "=0" on the right-hand side
Don't do this when using completing the square to rewrite a quadratic expression in a new form
i.e. when there is no "=0"
For that, you must factorise out the a (but not divide by it)
and so on
How does completing the square link to the quadratic formula?
The quadratic formula actually comes from completing the square to solve ax2 + bx + c = 0
a, b and c are left as letters when completing the square
This makes it as general as possible
You can see hints of this when you solve quadratics
For example, solving x2 + 10x + 9 = 0
by completing the square, (x + 5)2 = 16 so x = -5 ± 4 (as above)
by the quadratic formula, = -5 ± 4 (the same structure)
Worked Example
Solve by completing the square.
Divide both sides by 2 to make the quadratic start with x2
Halve the middle number, -4, to get -2
Replace the first two terms, x2 - 4x, with (x - 2)2 - (-2)2
Simplify the numbers
Add 16 to both sides
Take the square root of both sides
Include the ± sign to get two solutions
Add 2 to both sides
Work out each solution separately
x = 6 or x = -2
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