Speed-Time Graphs (Cambridge O Level Physics)

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Speed-Time Graphs

  • A speed-time graph shows how the speed of a moving object varies with time
    • The red line represents an object with increasing speed
    • The green line represents an object with decreasing speed

Increasing and decreasing speed

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Increasing and decreasing speed represented on a speed-time graph

Acceleration on a Speed-Time Graph

  • Speed-time graphs also show the following information:
    • If the object is moving with a constant acceleration or deceleration
    • The magnitude of the acceleration or deceleration

  • A straight line represents constant acceleration
  • The slope of the line represents the magnitude of acceleration
    • A steep slope means large acceleration (or deceleration) - i.e. the object's speed changes very quickly
    • A gentle slope means small acceleration (or deceleration) - i.e. the object's speed changes very gradually
    • A flat line means the acceleration is zero - i.e. the object is moving with a constant speed

    Acceleration, deceleration and constant speed


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This image shows how to interpret the slope of a speed-time graph

Using Speed-Time Graphs

  • The distance travelled by an object can be found by determining the area beneath the graph

 Area under a velocity-time graph

velocity-time-graphs-3, IGCSE & GCSE Chemistry revision notes

The distance travelled can be found from the area beneath the graph

 

  • If the area beneath the graph forms a triangle (the object is accelerating or decelerating) then the area can be determined using the formula:

 area space equals space 1 half cross times space base space cross times space height

  • If the area beneath the graph is a rectangle (constant velocity) then the area can be determined using the formula:

 area space equals space base space cross times space height

Worked example

The speed-time graph below shows a car journey which lasts for 160 seconds.

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Calculate the total distance travelled by the car on this journey.

Answer:

Step 1: Recall that the area under a velocity-time graph represents the distance travelled

  • In order to calculate the total distance travelled, the total area underneath the line must be determined

Step 2: Identify each enclosed area

  • In this example, there are five enclosed areas under the line
  • These can be labelled as areas 1, 2, 3, 4 and 5, as shown in the image below:

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Step 3: Calculate the area of each enclosed shape under the line

  • Area 1 = area of a triangle = ½ × base × height = ½ × 40 × 17.5 = 350 m
  • Area 2 = area of a rectangle = base × height = 30 × 17.5 = 525 m
  • Area 3 = area of a triangle = ½ × base × height = ½ × 20 × 7.5 = 75 m
  • Area 4 = area of a rectangle = base × height = 20 × 17.5 = 350 m
  • Area 5 = area of a triangle = ½ × base × height = ½ × 70 × 25 = 875 m

Step 4: Calculate the total distance travelled by finding the total area under the line

  • Add up each of the five areas enclosed:

total distance = 350 + 525 + 75 + 350 + 875

total distance = 2175 m

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Ashika

Author: Ashika

Expertise: Physics Project Lead

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.