Speed-Time Graphs (Cambridge (CIE) O Level Physics): Revision Note
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Speed-Time Graphs
A speed-time graph shows how the speed of a moving object varies with time
The red line represents an object with increasing speed
The green line represents an object with decreasing speed
Increasing and decreasing speed
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Increasing and decreasing speed represented on a speed-time graph
Acceleration on a Speed-Time Graph
Speed-time graphs also show the following information:
If the object is moving with a constant acceleration or deceleration
The magnitude of the acceleration or deceleration
A straight line represents constant acceleration
The slope of the line represents the magnitude of acceleration
A steep slope means large acceleration (or deceleration) - i.e. the object's speed changes very quickly
A gentle slope means small acceleration (or deceleration) - i.e. the object's speed changes very gradually
A flat line means the acceleration is zero - i.e. the object is moving with a constant speed
Acceleration, deceleration and constant speed
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This image shows how to interpret the slope of a speed-time graph
Using Speed-Time Graphs
The distance travelled by an object can be found by determining the area beneath the graph
Area under a velocity-time graph
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The distance travelled can be found from the area beneath the graph
If the area beneath the graph forms a triangle (the object is accelerating or decelerating) then the area can be determined using the formula:
If the area beneath the graph is a rectangle (constant velocity) then the area can be determined using the formula:
Worked Example
The speed-time graph below shows a car journey which lasts for 160 seconds.
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Calculate the total distance travelled by the car on this journey.
Answer:
Step 1: Recall that the area under a velocity-time graph represents the distance travelled
In order to calculate the total distance travelled, the total area underneath the line must be determined
Step 2: Identify each enclosed area
In this example, there are five enclosed areas under the line
These can be labelled as areas 1, 2, 3, 4 and 5, as shown in the image below:
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Step 3: Calculate the area of each enclosed shape under the line
Area 1 = area of a triangle = ½ × base × height = ½ × 40 × 17.5 = 350 m
Area 2 = area of a rectangle = base × height = 30 × 17.5 = 525 m
Area 3 = area of a triangle = ½ × base × height = ½ × 20 × 7.5 = 75 m
Area 4 = area of a rectangle = base × height = 20 × 17.5 = 350 m
Area 5 = area of a triangle = ½ × base × height = ½ × 70 × 25 = 875 m
Step 4: Calculate the total distance travelled by finding the total area under the line
Add up each of the five areas enclosed:
total distance = 350 + 525 + 75 + 350 + 875
total distance = 2175 m
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