The Mole & the Avogadro Constant (Cambridge O Level Chemistry)

Exam Questions

4 hours47 questions
1a2 marks

Ethanol is manufactured from glucose, C6H12O6, by fermentation according to the following equation.

C6H12O6 → 2C2H5OH + 2CO2

State the conditions required for this reaction.

1b
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5 marks

In an experiment, 30.0 g of glucose was fermented.

i)
Calculate the number of moles of glucose in 30.0 g.

[2]

ii)
Calculate the maximum mass of ethanol that could be obtained from 30.0 g of glucose.

[2]

iii)
Calculate the volume of carbon dioxide at room temperature and pressure that can be obtained from 30.0 g of glucose.

[1]

1c
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2 marks

Ethanol can also be manufactured from ethene.

i)
Name the raw material which is the source of ethene.

[1]

ii)
Write a balanced equation for the manufacture of ethanol from ethene.

[1]

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2a1 mark

Calcium carbonate is an important raw material.

Name a rock which is made up of calcium carbonate.

2b
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4 marks

When calcium carbonate is heated strongly, it decomposes.

CaCO3 → CaO + CO2
i)
Calculate the relative formula mass of:
   CaCO3
   CaO

[2]

ii)
7.00 kg of calcium oxide was formed. What mass of calcium carbonate was heated?

[2]

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3a
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1 mark

Table 1.1 shows the mass of ions present in a 100 cm3 sample of milk.

Table 1.1

ion formula of ion mass of ion in
100 cm3 milk / mg
calcium Ca2+ 125
chloride Cl− 120
magnesium Mg2+ 12
negative ions of organic acids   160
phosphate PO subscript 4 superscript 3 minus end superscript 95
potassium K+ 140
sodium Na+ 58
sulfate begin mathsize 16px style S O subscript 4 to the power of 2 minus sign end style 30

Calculate the mass of calcium ions present in a 20 cm3 sample of this milk.

mass of calcium ions: .................................... mg

3b1 mark

Identify the positive ion present in the highest concentration in the 100 cm3 sample of milk.

3c1 mark

A solution is obtained by filtering a mixture of soil and water. The table shows the mass of some of the ions in 1000 cm3 of this solution.

name of ion formula of ion mass of ion in 1000 cm3
of soil solution / mg
aluminium Al 3+ 0.2
ammonium NH subscript 4 superscript plus 22.0
calcium Ca2+ 0.2
iron(II) Fe2+ 79.0
magnesium Mg2+ 0.1
nitrate begin mathsize 16px style N O subscript 3 to the power of minus sign end style 28.0
phosphate PO subscript 4 superscript 3 minus end superscript 14.0
potassium K+ 39.0
sulfate begin mathsize 16px style S O subscript 4 to the power of 2 minus sign end style 5.1

Answer this question using the information in the table.

Which negative ion has the lowest concentration?

3d
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1 mark

A solution is obtained by filtering a mixture of soil and water. The table shows the mass of some of the ions in 1000 cm3 of this solution.

name of ion formula of ion mass of ion in 1000 cm3
of soil solution / mg
aluminium Al 3+ 0.2
ammonium begin mathsize 16px style N H subscript 4 to the power of plus sign end style 22.0
calcium Ca2+ 0.2
iron(II) Fe2+ 79.0
magnesium Mg2+ 0.1
nitrate begin mathsize 16px style N O subscript 3 to the power of minus sign end style 28.0
phosphate PO subscript 4 superscript 3 minus end superscript 14.0
potassium K+ 39.0
sulfate begin mathsize 16px style S O subscript 4 to the power of 2 minus sign end style 5.1

Answer this question using the information in the table.

Calculate the mass of nitrate ions in 200 cm3 of this solution.

mass = .............................. mg

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4a4 marks

This question is about the yield of chemical reactions.

In practice, scientists aim for a 100% yield but this is rarely achieved.

Complete the sentences to explain why a 100% yield is not achieved using words from the list. 

side reactions transfer complete incomplete
purification reversible irreversible mixing
 

Reactants and products can be left behind during _______________ from one container to another.

_______________ reactions can never have a 100% yield because the products are forming reactants.

A reaction might not go to completion because of _______________ or the presence of an impurity. These reactions are described as _______________ .

4b2 marks

There are different types of yield.

The percentage yield compares the actual yield to the theoretical yield.

Draw one line from each yield to its description.

aqa-gcse-3-3e-q1b-yield-definitions-
4c
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1 mark

A student completed an experiment using magnesium to displace copper from copper(II) sulfate.

Mg + CuSO4 → Cu + MgSO4

The student added 4.8 g of magnesium to a solution of copper(II) sulfate.

Calculate the number of moles of magnesium that the student used.

Relative atomic mass (Ar):     Mg = 24

Use the equation:

moles equals mass over M subscript straight r

4d
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2 marks

Using your answer to part (c), calculate the theoretical yield of copper.

Relative atomic mass (Ar):     Cu = 63.5

Theoretical yield of copper = ________ g

4e
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2 marks

Another student completes the same experiment using 4.8 g of magnesium.

They obtain 10.16 g of copper.

What is the percentage yield of this student's experiment? 

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1a1 mark

Dilute hydrochloric acid reacts with sodium carbonate solution.

2HCl (aq) + Na2CO3 (aq) → 2NaCl (aq) + H2O (l) + CO2 (g)

Explain why effervescence is seen during the reaction.

1b
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5 marks

Dilute hydrochloric acid was titrated with sodium carbonate solution.

  • 10.0 cm3 of 0.100 mol / dm3 hydrochloric acid were placed in a conical flask.
  • A few drops of methyl orange indicator were added to the dilute hydrochloric acid
  • The mixture was titrated with sodium carbonate solution.
  • 16.2 cm3 of sodium carbonate solution were required to react completely with the acid.
i)
What colour would the methyl orange indicator be in the hydrochloric acid?

[1]

ii)
Calculate how many moles of hydrochloric acid were used.

[1]

iii)
Use your answer to (b)(ii) and the equation for the reaction to calculate the number of moles of sodium carbonate that reacted.

[1]

iv)
Use your answer to (b)(iii) to calculate the concentration of the sodium carbonate solution in mol / dm3.

[2]

1c
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3 marks

In another experiment, 0.020 mol of sodium carbonate were reacted with excess hydrochloric acid.

Calculate the maximum volume (at r.t.p.) of carbon dioxide gas that could be made in this reaction.

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2a
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3 marks

Two salts can be made from potassium hydroxide and sulfuric acid. They are potassium sulfate, K2SO4, and the acid salt potassium hydrogen sulfate, KHSO4. They are both made by titration.

titration-h2so4-koh

25.0 cm3 of potassium hydroxide, concentration of 2.53 mol / dm3, was neutralised by 28.2 cm3 of dilute sulfuric acid.

2KOH (aq) + H2SO4 (aq) → K2SO4 (aq) + 2H2O (l)

Calculate the concentration of the sulfuric acid.

number of moles of KOH used = ............................

number of moles of H2SO4 needed to neutralise the KOH = ............................

concentration of dilute sulfuric acid = ............................ mol / dm3

2b4 marks

In the conical flask there is a neutral solution of potassium sulfate which still contains the indicator used in the titration.

i)
Describe how you could obtain a solution of potassium sulfate without the indicator.

[2]

ii)
Potassium hydrogen sulfate can be made by the following reaction.

KOH (aq) + H2SO4 (aq) → KHSO4 (aq) + H2O (l)

Suggest how you could make a solution of potassium hydrogen sulfate without using an indicator.

[2]

2c2 marks

Describe a test which would distinguish between aqueous solutions of potassium sulfate and sulfuric acid.

   Test:

   Result:

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3a2 marks

Define the following

i)
The mole

[1]

ii)
The Avogadro constant

[1]

3b
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2 marks

Which two of the following contain the same number of molecules?
Show how you arrived at your answer.

   2.0 g of methane, CH4
   8.0 g of oxygen, O2
   2.0 g of ozone, O3
   8.0 g of sulfur dioxide, SO2

3c
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4 marks

4.8 g of calcium is added to 3.6 g of water. The following reaction occurs.

Ca + 2H2O → Ca(OH)2 + H2

i)
The number of moles of Ca = ....................

The number of moles of H2O = ....................

[1]

ii)
Which reagent is in excess? Explain your choice.

[2]

iii)
Calculate the mass of the reagent named in (ii) which remained at the end of the experiment.

[1]

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4a1 mark

Chemists use the concept of the mole to calculate the amounts of chemicals involved in a reaction.

Define mole.

4b
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6 marks

3.0 g of magnesium was added to 12.0 g of ethanoic acid.

Mg + 2CH3COOH → (CH3COO)2Mg + H2

The mass of one mole of Mg is 24 g.

The mass of one mole of CH3COOH is 60 g.

i)
Which one, magnesium or ethanoic acid, is in excess? You must show your reasoning.

[3]

ii)
How many moles of hydrogen were formed?

[1]

iii)
Calculate the volume of hydrogen formed, measured at r.t.p.

[2]

4c
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4 marks

In an experiment, 25.0 cm3 of aqueous sodium hydroxide, 0.4 mol / dm3, was neutralised by 20.0 cm3 of aqueous oxalic acid, H2C2O4.

2NaOH + H2C2O4 → Na2C2O4 +2H2O

i)
Calculate the number of moles of NaOH in 25.0 cm3 of 0.4 mol / dm3 solution.

[1]

ii)
Use your answer to (i) and the mole ratio in the equation to find out the number of moles of H2C2O4 in 20 cm3 of solution.

[1]

iii)
Calculate the concentration, mol / dm3, of the aqueous oxalic acid.

[2]

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5
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5 marks
Iron(III) sulphate decomposes when heated. Calculate the mass of iron(III) oxide formed and the volume of sulphur trioxide produced when 10.0 g of iron(III) sulphate was heated. 

Mass of one mole of Fe2(SO4)3 is 400 g.

Fe2(SO4)3 (s)→ Fe2O3 (s) + 3SO3 (g)

Number of moles of Fe2(SO4)3 =

Number of moles of Fe2O3 formed = 

Mass of iron(III) oxide formed in g =

Number of moles of SO3 produced = 

Volume of sulphur trioxide at r.t.p. in dm3 =

[5]

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6a4 marks

Sulphur trioxide can be made from sulphur dioxide.

i)
Why is this reaction important industrially?

[1]

ii)
Complete the word equation.

sulphur dioxide + .............................................. → sulphur trioxide

[1]

iii)
What are the conditions for this reaction?

[2]

6b2 marks

Sulphur dioxide is easily oxidised in the presence of water.

SO2 + 2H2O – 2e– → SO42- + 4H+

What colour change would be observed when an excess of aqueous sulphur dioxide is added to an acidic solution of potassium manganate(VII)?

6c
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5 marks

Sulphur dioxide reacts with chlorine in an addition reaction to form sulphuryl chloride.

SO2 + Cl2 → SO2Cl2

8.0 g of sulphur dioxide was mixed with 14.2 g of chlorine. The mass of one mole of SO2Cl2 is 135 g.

Calculate the mass of sulphuryl chloride formed by this mixture.

Calculate the number of moles of SO2 in the mixture = 

Calculate the number of moles of Cl2 in the mixture = 

Which reagent was not in excess? 

How many moles of SO2Cl2 were formed =

Calculate the mass of sulphuryl chloride formed in g =

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7a2 marks

The food additive E220 is sulfur dioxide. It is a preservative for a variety of foods and drinks.

Sulfur dioxide is a reductant (reducing agent). Describe what you would see when aqueous sulfur dioxide is added to acidified potassium manganate(VII).

7b
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3 marks

Sulfur dioxide can also be made by the reaction between a sulfite and an acid.

Na2SO3 + 2HCl → 2NaCl + SO2 + H2O

Excess hydrochloric acid was added to 3.15 g of sodium sulfite. Calculate the maximum volume, measured at r.t.p., of sulfur dioxide which could be formed.
The mass of one mole of Na2SO3 is 126 g.

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8a2 marks

The alkanes are a family of saturated hydrocarbons. Their reactions include combustion, cracking and substitution. 

i)
What is meant by the term hydrocarbon?
[1]
ii)
What is meant by the term saturated?
[1]
8b3 marks
i)
What is the general formula for the homologous series of alkanes?
[1]
ii)
Calculate the mass of one mole of an alkane with 14 carbon atoms.
[2]
8c
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5 marks

The complete combustion of hydrocarbons produces carbon dioxide and water only.

i)
Write the equation for the complete combustion of nonane, C9H20.
[2]
 
ii)
20cm3 of a gaseous hydrocarbon was mixed with an excess of oxygen, 200 cm3. The mixture was ignited. After cooling, 40 cm3 of oxygen and 100 cm3 of carbon dioxide remained. Deduce the formula of the hydrocarbon and the equation for its combustion. All volumes were measured at r.t.p..
[3]
8d4 marks

Cracking is used to obtain short-chain alkanes, alkenes and hydrogen from long-chain alkanes.

i)
Give a use for each of the three products listed above.
 
short-chain alkanes ..................................................
 
alkenes ..................................................
 
hydrogen ..................................................
[3]
 
ii)
Write an equation for the cracking of decane, C10H22, which produces two different alkenes and hydrogen as the only products.
[1]
8e2 marks

Chlorine reacts with propane in a substitution reaction to form 1-chloropropane.

 CH3–CH2–CH3 + Cl2 → CH3–CH2–CH2–Cl + HCl

i)
What is the essential condition for the above reaction?
[1]
 
ii)
There is more than one possible substitution reaction between chlorine and propane.
Suggest the structural formula of a different product.
[1]

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9a1 mark
In a titration, a student added 25.0 cm3 of 0.200 mol/dm3 aqueous sodium hydroxide to a conical flask. The student then added a few drops of methyl orange to the solution in the conical flask.

Dilute sulfuric acid is then added from a burette to the conical flask. The volume of dilute sulfuric acid needed to neutralise the aqueous sodium hydroxide was 20.0 cm3

The reaction is shown by the equation.

2NaOH + H2SO4 → Na2SO4 + 2H2O

State the colour of methyl orange in aqueous sodium hydroxide.

9b
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4 marks

Determine the concentration of the dilute sulfuric acid in g/dm3 using the following steps.

  • Calculate the number of moles of aqueous sodium hydroxide added to the conical flask.

..................... mol

  • Calculate the number of moles of dilute sulfuric acid added from the burette.

...................... mol

  • Calculate the concentration of the dilute sulfuric acid in mol/dm3.

............ mol/dm3

  • Calculate the concentration of the dilute sulfuric acid in g/dm3.

............... g/dm3

9c
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4 marks

Ethanoic acid is a weak acid and hydrochloric acid is a strong acid.
Both ethanoic acid and hydrochloric acid dissociate in aqueous solution.

Hydrochloric acid produces salts called chlorides.
Magnesium carbonate reacts with hydrochloric acid to produce magnesium chloride.

MgCO3 + 2HCl→ MgCl2 + H2O + CO2

A student used 50.00 cm3 of 2.00 mol/dm3 hydrochloric acid in an experiment to produce magnesium chloride.

Calculate the mass, in g, of magnesium carbonate needed to react exactly with 50.00 cm3 of 2.00 mol/dm3 hydrochloric acid using the following steps.

  • Calculate the number of moles of HCl present in 50.00 cm3 of 2.00 mol/dm3 HCl.

.............................. mol

  • Determine the number of moles of MgCO3 which would react with 50.00 cm3 of 2.00 mol/dm3 HCl.


.............................. mol

  • Calculate the relative formula mass, Mr, of MgCO3.


Mr of MgCO3 = ..............................

  • Calculate the mass of MgCO3 needed to react exactly with 50.00 cm3 of 2.00 mol/dm3 HCl.


mass = .............................. g

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10a
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3 marks

When copper(II) oxide is heated at 800 °C it undergoes the reaction shown by the equation.

4CuO → 2Cu2O + O2

Calculate the volume of oxygen, measured at r.t.p., which is formed when 1.60 g of CuO reacts as shown in the equation.

10b
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3 marks

Oxygen is produced by the decomposition of hydrogen peroxide. Manganese(IV) oxide is the catalyst for this reaction.

The equation for the decomposition of hydrogen peroxide is shown.

2H2O2 (aq) → 2H2O (l) + O2 (g)

25.0 cm3 of aqueous hydrogen peroxide forms 48.0 cm3 of oxygen at room temperature and pressure (r.t.p.).

Calculate the concentration of aqueous hydrogen peroxide at the start of the experiment using the following steps.

  • Calculate the number of moles of oxygen formed.
  • Deduce the number of moles of hydrogen peroxide that decomposed.
  • Calculate the concentration of hydrogen peroxide in mol/dm3.

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11a1 mark

This question is about elements X, Y and Z.

What is the name of the amount of any substance that contains 6.02 × 1023 particles?

11b1 mark

The constant 6.02 × 1023 has a name.

What is the name of this constant?

11c
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2 marks

Sulfur dioxide, SO2, is used in the manufacture of sulfuric acid.

The next stage of the process is a reaction which can reach equilibrium.

The equation for this stage is shown.

2SO2 (g) + O2 (g) rightwards harpoon over leftwards harpoon for blank of 2SO3 (g)

Calculate the percentage by mass of sulfur in sulfur trioxide, SO3.

percentage = ..............................%

11d3 marks

This question is about reactions of bases and acids.

A student wanted to find the concentration of some dilute sulfuric acid by titration. The student found that 25.0 cm3 of 0.0400 mol/dm3 NaOH (aq) reacted exactly with 20.0 cm3 of H2SO4 (aq).

Calculate the concentration of the H2SO4(aq) in mol/dm3 using the following steps.

  • Calculate the number of moles of NaOH in 25.0 cm3.

moles = ..............................

  • Deduce the number of moles of H2SO4 that reacted with the 25.0 cm3 of NaOH (aq).

moles = ..............................

  • Calculate the concentration of H2SO4 (aq) in mol/dm3.

concentration = .............................. mol/dm3
11e
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2 marks

A student wanted to find the concentration of some dilute sulfuric acid by titration. The student found that 25.0 cm3 of 0.0400 mol/dm3 NaOH (aq) reacted exactly with 20.0 cm3 of H2SO4 (aq).

Calculate the concentration of the 0.0400 mol/dm3 NaOH (aq) in g/dm3.

concentration = .............................. g/dm3

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12a
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1 mark

Ammonia, NH3, is used to produce nitric acid, HNO3. This happens in a three-stage process.

Stage 1 is a redox reaction.

4NH3 + 5O2 → 4NO + 6H2O

In this reaction the predicted yield of NO is 512 g. The actual yield is 384 g. Calculate the percentage yield of NO in this reaction.

percentage yield of NO = ................................ %
12b
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4 marks

The equation for the reaction in stage 3 is shown.

4NO2 + 2H2O + O2 → 4HNO3

Calculate the volume of O2 gas, at room temperature and pressure (r.t.p.), needed to produce 1260 g of HNO3.


Use the following steps.

  • Calculate the number of moles of HNO3.

moles of HNO3 = ..............................

  • Deduce the number of moles of O2 that reacted.

moles of O2 = ..............................

  • Calculate the volume of O2 gas that reacts at room temperature and pressure (r.t.p.).

volume of O2 gas = .............................. dm3

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13a1 mark

The structure of propenyl ethanoate is shown.

Use the structure to explain why propenyl ethanoate is unsaturated.

q9a-cie-o-level-chemistry-june-2021-paper-2

13b2 marks

Describe a chemical test to show that propenyl ethanoate is unsaturated.

test:.........................................................

observation:............................................

13c3 marks

Propenyl ethanoate is prepared by the reaction between a carboxylic acid and an alcohol, as shown.

q9c-cie-o-level-chemistry-june-2021-paper-2

i)
Name the carboxylic acid used.
[1]
ii)
The reaction uses concentrated sulfuric acid as a catalyst.
Describe how a catalyst speeds up a chemical reaction.
[2]
13d4 marks

In an experiment 11.6 g of the alcohol is reacted with an excess of the carboxylic acid. The experimental yield of propenyl ethanoate is 6.72 g.

 [The relative formula mass of propenyl ethanoate is 100.]

i)
Show that the maximum possible yield of propenyl ethanoate is 20.0 g
[3]
ii)
Calculate the percentage yield of propenyl ethanoate in this experiment.
[1]

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14a1 mark

Salts can be prepared by the reaction of acids with bases or alkalis and also by precipitation reactions.

State the ionic equation for the reaction between an acid and an alkali.

14b1 mark

Sodium sulfate is a soluble salt prepared by a titration method using an acid and an alkali. Identify the acid and the alkali used to prepare sodium sulfate.

14c4 marks

Aqueous sodium sulfate is used to prepare barium sulfate in a precipitation reaction.

Ba2+ (aq) + SO42− (aq) → BaSO4 (s)

In an experiment 20.0 cm3 of 0.550 mol / dm3 of barium nitrate is added to an excess of sodium sulfate.

i)
State the colour of the precipitate formed in the reaction.

[1]

ii)
Calculate the maximum mass of barium sulfate that could be made.

[Mr : BaSO4, 233]

Show your working.

[2]

iii)
A mass of 1.92 g of dry barium sulfate is obtained. Calculate the percentage yield of barium sulfate.

[1]

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1a
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6 marks

The following method is used to make crystals of hydrated nickel sulphate.

An excess of nickel carbonate, 12.0 g, was added to 40 cm3 of sulphuric acid, 2.0 mol/dm3. The unreacted nickel carbonate was filtered off and the filtrate evaporated to obtain the crystals.

NiCO3 + H2SO4  → NiSO4 + CO2 + H2O

NiSO4 + 7H2O  → NiSO4.7H2O

Mass of one mole of NiSO4.7H2O = 281 g
Mass of one mole of NiCO3 = 119 g

i)
Calculate the mass of unreacted nickel carbonate.

Number of moles of H2SO4 in 40 cm3 of 2.0 mol/dm3 acid = 0.08

Number of moles of NiCO3 reacted = ...................................... 

Mass of nickel carbonate reacted = ...................................... g

Mass of unreacted nickel carbonate =  ...................................... g
[3]
ii)
The experiment produced 10.4 g of hydrated nickel sulphate. Calculate the percentage yield.

The maximum number of moles of NiSO4.7H2Othat could be formed = ......................................

The maximum mass of NiSO4.7H2O that could be formed = ...................................... g

The percentage yield = ...................................... %
[3]
1b6 marks

In the above method, a soluble salt was prepared by neutralising an acid with an insoluble base. Other salts have to be made by different methods.

i)
Give a brief description of how the soluble salt, rubidium sulphate could be made from the soluble base, rubidium hydroxide.

[3]

ii)
Suggest a method of making the insoluble salt, calcium fluoride.

[3]

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2a4 marks

Soluble salts can be made using a base and an acid.

Complete this method of preparing dry crystals of the soluble salt cobalt(II) chloride-6-water from the insoluble base cobalt(II) carbonate.

   step 1
   Add an excess of cobalt(II) carbonate to hot dilute hydrochloric acid.

  step 2

   step 3


   
step 4

2b
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6 marks
i)
5.95 g of cobalt(II) carbonate were added to 40 cm3 of hydrochloric acid, concentration 2.0 mol / dm3.

Calculate the maximum yield of cobalt(II) chloride-6-water and show that the cobalt(II) carbonate was in excess.

CoCO3 + 2HCl → CoCl2 + CO2 + H2O

CoCl2 + 6H2O → CoCl2.6H2O

maximum yield:

number of moles of HCl used = .....................................................................

number of moles of CoCl2 formed = ...............................................................

number of moles of CoCl2.6H2O formed = .......................................................

mass of one mole of CoCl2.6H2O = 238 g

maximum yield of CoCl2.6H2O = ...................................................................g

to show that cobalt(II) carbonate is in excess:

number of moles of HCl used = ..................................... (use your value from above)

mass of one mole of CoCO3 = 119 g

number of moles of CoCO3 in 5.95 g of cobalt(II) carbonate = ..............................
[5]
ii)
Explain how these calculations show that cobalt(II) carbonate is in excess.
[1]

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3a4 marks

Crystals of sodium sulphate-10-water, Na2SO4.10H2O, are prepared by titration.

prep-sodium-sulphate-10-water

25.0 cm3 of aqueous sodium hydroxide is pipetted into a conical flask.

A few drops of an indicator are added. Using a burette, dilute sulphuric acid is slowly added until the indicator just changes colour. The volume of acid needed to neutralise the alkali is noted.

Suggest how you would continue the experiment to obtain pure, dry crystals of sodium sulphate-10-water.

3b
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4 marks

Using 25.0 cm3 of aqueous sodium hydroxide, 2.24 mol / dm3, 3.86 g of crystals were obtained. Calculate the percentage yield.

2NaOH + H2SO4 → Na2SO4 + 2H2O

Na2SO4 + 10H2O → Na2SO4.10H2O

Number of moles of NaOH used =

Maximum number of moles of Na2SO4.10H2O that could be formed =

Mass of one mole of Na2SO4.10H2O = 322g

Maximum yield of sodium sulphate-10-water, in g =

Percentage yield = 

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4a6 marks

Calcium and other minerals are essential for healthy teeth and bones. Tablets can be taken to provide these minerals.

Healthy Bones

Each tablet contains
calcium
magnesium
zinc
copper
boron

Boron is a non-metal with a macromolecular structure.

i)
Predict two physical properties of boron.

[2]

ii)
Name another element and a compound that have macromolecular structures.

[2]

iii)
Sketch the structure of one of the above macromolecular substances.

[2]

4b4 marks

Describe the reactions, if any, of zinc and copper(II) ions with an excess of aqueous sodium hydroxide.

i)
Zinc ions
Addition of aqueous sodium hydroxide:
Excess sodium hydroxide:

[2]

ii)
Copper(II) ions
Addition of aqueous sodium hydroxide:
Excess sodium hydroxide:
[2]
4c
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5 marks

Each tablet contains the same number of moles of CaCO3 and MgCO3. One tablet reacted with excess hydrochloric acid to produce 0.24 dm3 of carbon dioxide at r.t.p.

CaCO3 + 2HCl → CaCl2 + CO2 + H2O
MgCO3 + 2HCl → MgCl2 + CO2 + H2O

i)
Calculate how many moles of CaCO3 there are in one tablet.

Number of moles CO2 =

Number of moles of CaCO3 and MgCO3 =

Number of moles of CaCO3 =

[3]

ii)
Calculate the volume of hydrochloric acid, 1.0 mol / dm3, needed to react with one tablet.

Number of moles of CaCO3 and MgCO3 in one tablet = 
Use your answer to (c)(i).

Number of moles of HCl needed to react with one tablet =

Volume of hydrochloric acid, 1.0 mol / dm3, needed to react with one tablet =

[2]

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5a5 marks

The soluble salt hydrated lithium sulfate is made by titration from the soluble base lithium hydroxide.

titration-lioh--h2so4

The sulfuric acid is added slowly from the burette until the indicator just changes colour. The volume of sulfuric acid  needed to just neutralise the lithium hydroxide is noted.

Describe how you would continue the experiment to obtain pure dry crystals of hydrated lithium sulfate.

5b
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4 marks

Separate: Chemistry and Extended Only

Using 25.0 cm3 of aqueous lithium hydroxide, concentration 2.48 mol / dm3, 2.20 g of hydrated lithium sulfate was obtained.

Calculate the percentage yield, giving your answer to one decimal place.

2LiOH + H2SO4 → Li2SO4 + 2H2O
Li2SO4 + H2O → Li2SO4.H2O

   Number of moles of LiOH used = .......................
   Number of moles of Li2SO4.H2O which could be formed = .......................
   Mass of one mole of Li2SO4.H2O = 128g
   Maximum yield of Li2SO4.H2O = ....................... g
   Percentage yield = .......................%

5c4 marks

An experiment was carried out to show that the formula of the hydrated salt is Li2SO4.H2O. A sample of the hydrated salt was weighed and its mass recorded. It was then heated and the anhydrous salt was weighed. This procedure was repeated until two consecutive masses were the same. This procedure is called ‘heating to constant mass’.

i)
What is the reason for heating to constant mass?
[1]
ii)
The mass of the hydrated salt is m1 and the mass of the anhydrous salt is m2. Explain how you could show that the hydrated salt has one mole of water of crystallisation per mole of the anhydrous salt.
[3]

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6a3 marks

The elements in Period 3 and some of their common oxidation states are shown below.

Element Na Mg Al Si P S I Ar
Oxidation state +1 +2 +3 +4 -3 -2 -1 0

i)
Why do the oxidation states increase from sodium to silicon?

[1]

ii)
After Group(IV) the oxidation states are negative and decrease across the period.
Explain why.

[2]

6b1 mark

Aluminium sulfide contains two elements. Predict its formula.

6c3 marks

Choose a different element from Period 3 that matches each description.

i)
It has a similar structure to diamond.

[1]

ii)
It reacts violently with cold water to form a solution pH = 14.

[1]

iii)
It has a gaseous oxide of the type XO2, which is acidic.

[1]

6d3 marks

Draw a diagram that shows the arrangement of the outer electrons in the ionic compound sodium phosphide.

Use o to represent an electron from sodium.
Use x to represent an electron from phosphorus.

6e
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4 marks

Sodium reacts with sulphur to form sodium sulfide.

2Na + S → Na2S

An 11.5 g sample of sodium is reacted with 10 g of sulfur. All of the sodium reacted but there was an excess of sulfur.

Calculate the mass of sulfur left unreacted.

i)
Number of moles of sodium atoms reacted = 
[2 moles of Na react with 1 mole of S]

[1]

ii)
Number of moles of sulfur atoms that reacted =

[1]

iii)
Mass of sulfur reacted, in grams =

[1]

iv)
Mass of sulfur left unreacted, in grams =

[1]

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7a2 marks

Sulfuric acid is made by the Contact process.

2SO2 + O2 rightwards harpoon over leftwards harpoon 2SO3

This is carried out in the presence of a catalyst at 450°C and 2 atmospheres pressure.

i)
Name the catalyst used.

[1]

ii)
If the temperature is decreased to 300°C, the yield of sulfur trioxide increases.
Explain why this lower temperature is not used.

[1]

7b5 marks

Sulfuric acid was first made in the Middle East by heating the mineral, green vitriol, FeSO4.7H2O. The gases formed were cooled.

FeSO4.7H2O (s) → FeSO4 (s) + 7H2O (g)
green crystals      yellow powder

2FeSO4 (s) → Fe2O3 (s) + SO2 (g) + SO3 (g)

On cooling
SO3 + H2O → H2SO4 sulfuric acid
SO2 + H2O → H2SO3 sulfurous acid

i)
How could you show that the first reaction is reversible?

[2]

ii)
Sulfurous acid is a reductant (reducing agent). What would you see when acidified potassium manganate(VII) is added to a solution containing this acid?

[2]

iii)
Suggest an explanation why sulfurous acid in contact with air changes into sulfuric acid.

[1]

7c
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6 marks

9.12 g of anhydrous iron(II) sulfate was heated. Calculate the mass of iron(III) oxide formed and the volume of sulfur trioxide, at r.t.p., formed. 

2FeSO4 (s) → Fe2O3 (s) + SO2 (g) + SO3 (g)

mass of one mole of FeSO4 = 152 g
number of moles of FeSO4 used = _____________
number of moles of Fe2O3 formed = _____________ 
mass of one mole of Fe2O3 = _____________ g
mass of iron(III) oxide formed = _____________ g
number of moles of SO3 formed = _____________ 
volume of sulfur trioxide formed = _____________ dm3

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8a4 marks

Sulfur dioxide, SO2, and sulfur trioxide, SO3, are the two oxides of sulfur.

Sulfur trioxide can be made from sulfur dioxide.

i)
Why is this reaction important industrially?

[1]

ii)
Complete the word equation.

sulfur dioxide + .............................................. → sulfur trioxide

[1]

iii)
What are the conditions for this reaction?

[2]

8b5 marks

Sulphur dioxide is easily oxidised in the presence of water.

SO2 + 2H2O – 2e– → SO42– + 4H+

i)
What colour change would be observed when an excess of aqueous sulphur dioxide is added to an acidic solution of potassium manganate(VII)?
[2]
ii)
To aqueous sulphur dioxide, acidified barium chloride solution is added. The mixture remains clear. When bromine is  added, a thick white precipitate forms. What is the white precipitate? Explain why it forms.

[3]

8c
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5 marks

Sulphur dioxide reacts with chlorine in an addition reaction to form sulphuryl chloride.

SO2 + Cl2 → SO2Cl2

8.0 g of sulphur dioxide was mixed with 14.2 g of chlorine. The mass of one mole of SO2Cl2 is 135 g.

Calculate the mass of sulphuryl chloride formed by this mixture.

Calculate the number of moles of SO2 in the mixture = ..................

Calculate the number of moles of Cl2 in the mixture = ..................

Which reagent was not in excess? ...............................

How many moles of SO2Cl2 were formed = ...................

Calculate the mass of sulphuryl chloride formed = ............. g

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