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Answer
Step 1: Write the equation for the reaction:
HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)
Step 2: Calculate the number of moles of the NaOH
Moles = (volume ÷ 1000) x concentration
Moles of NaOH = 0.012 dm3 x 0.100 mol/dm3 = 1.21 x 10-3 mol
Step 3: Deduce the number of moles of the acid
Since the acid reacts in a 1:1 ratio with the alkali, the number of moles of HCl is also 1.21 x 10-3 mol
This is present in 25.0 cm3 of the solution (25.0 cm3 = 0.025 dm3)