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Ar & Mr (Cambridge O Level Chemistry)
Revision Note
Relative Masses
Relative Atomic Mass
- The symbol for the relative atomic mass is Ar
- The relative atomic mass for each element can be found in the Periodic Table along with the atomic number
- The relative atomic mass is shown underneath the atomic symbol and is larger than the atomic number (except for hydrogen where they are the same)
- Atoms are too small to accurately weigh but scientists needed a way to compare the masses of atoms
- The carbon-12 is used as the standard atom and has a fixed mass of 12 units
- It is against this atom which the masses of all other atoms are compared
- Relative atomic mass (Ar) can therefore be defined as:
- The average mass of the isotopes of an element compared to 1/12th of the mass of an atom of 12C
- The relative atomic mass of carbon is 12
- The relative atomic mass of magnesium is 24 which means that magnesium is twice as heavy as carbon
- The relative atomic mass of hydrogen is 1 which means it has one twelfth the mass of one carbon-12 atom
Relative molecular (formula) mass
- The symbol for the relative molecular mass is Mr and it refers to the total mass of the molecule
- To calculate the Mr of a substance, you have to add up the relative atomic masses of all the atoms present in the formula
- Relative formula mass is used when referring to the total mass of an ionic compound
Relative Formula Mass Calculations Table
Reacting masses
- The Law of Conservation of mass tells us that mass cannot be created or destroyed
- In a chemical reaction, the total mass of reactants equals the total mass of the products
- We can use this, along with relative atomic/formula masses to perform calculations to identify the quantities of reactants or products involved in a chemical reaction
- Example:
2Ca + O2 → 2CaO
- Relative atomic masses: Ca = 40; O = 16
- Using the balanced symbol equation shows that 2 x 40 = 80 units of mass of calcium react with 2 x 16 = 32 units of mass of oxygen to form 2 x (40 + 16) = 112 units of mass of CaO:
2Ca + O2 → 2CaO
80 + 32 = 112
- The ratio of the mass of calcium and oxygen reacting will always be the same, regardless of the units
- E.g. 80 g of calcium will react with 32 g of oxygen to form 112 g of calcium oxide
- Or, 40 tonnes of calcium will react in excess oxygen to form 56 tonnes of calcium oxide
Worked example
Calculate the mass of carbon dioxide produced when 32 g of methane, CH4, reacts completely in excess oxygen:
CH4 + 2O2 → CO2 + 2H2O
Relative atomic masses, Ar: H = 1; C = 12; O = 16
Answer
- In terms of relative mass the equation is:
CH4 + 2O2 → CO2 + 2H2O
12 + (4 x 1) + 2 x (2 x 16) → 12 + (2 x 16) + 2 x (2 x 1 + 16)
16 + 64 → 44 + 36
- So 16 g of methane would react in excess oxygen to form 44 g of carbon dioxide
- Therefore, 32 g of methane would produce 44 x 2 = 88 g of carbon dioxide
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