Compose & Resolve Velocities (Cambridge (CIE) O Level Additional Maths): Revision Note

Exam code: 4037

Dan Finlay

Written by: Dan Finlay

Reviewed by: Lucy Kirkham

Updated on

Modelling velocities with vectors

How are velocities modelled by vectors?

  • Although introduced as being about paths and distances between points, a vector can also represent a velocity

    • For example the velocity vector (37) m s1 (or (3i+7j) m s1) would represent a particle or object moving

      • at 3 m s1 (metres per second) in the positive x direction

      • and 7 m s1  in the positive y direction

  • Speed is different to velocity

    • Speed is a scalar quantity, velocity is a vector quantity 

    • Velocity has direction, as well as magnitude

    • Speed is the magnitude of velocity

      • Therefore, speed can be found from velocity by finding its magnitude - i.e. using Pythagoras' theorem e.g.  The speed of a particle travelling with velocity (68) m s1 is 62+82=10 m s1

      • An object travelling with velocity (68) m s1 would have the same speed, 10 m s1 but be moving in the opposite direction

How do I find the position of a particle from a velocity vector?

  • In general, problems refer to a particle's position vector, (xi+yj) m (metres, from the origin) at time t seconds after its motion has started

    • This position vector is often called r

  • If the particle moves with (constant) velocity v m s1, after t seconds its position vector will be

    • r=r0+vt where r0 is the initial position of the particle (i.e. its position at the start of the motion)

  • For example if a particle starts at the point with coordinates (2, 3) and moves with (constant) velocity (4i+7j) m s1 after 10 seconds its position will be

r=(2i3j)+10(4i+7j)r=((2+40)i+(3+70)j)r=(42i+67j) m

How do I solve problems involving velocities and vectors?

  • Solving problems involving velocity may involve using a variety of the skills covered in the vectors section

    • A resultant velocity may be comprised of two (or more) velocities

      • e.g. the velocity of a javelin will be influenced by the athlete's ability and the wind speed/direction

      • a resultant velocity is found by adding velocity vectors

  • Problems may be phrased to distinguish the difference between speed and velocity

    • Speed is the magnitude of velocity (use Pythagoras' theorem)

  • Problems may use position vectors

    • The initial position (r0) is not necessarily the origin

      • r=r0+vt

  • There could be two particles to deal with in a problem

    • be clear about which particle has which velocity, position, etc

      • If two particles collide at time t seconds, then (at time t) their position vectors will be equal

      • Two vectors are equal if their components are equal

Examiner Tips and Tricks

  • Vector diagrams drawn previously to show paths and distances can still be used to visualise velocities

    • So use any given diagram, and if there isn't one, draw one!

  • Read questions carefully - a common mistake is to give a final answer as a position vector when the question has asked for coordinates, or vice versa

    • e.g.  A particle with position vector (3i2j) has coordinates (3, 2)

Worked Example

A boat leaves a harbour (the origin) and sails with a (constant) resultant velocity comprising of the velocity produced by the boat's engine, (i+2j) m s1 and the velocity produced by the water current, (1.5i+2j) m s1.

a) Find the resultant velocity of the boat.

The resultant velocity will be the sum of the two velocities.

v=(i+2j)+(1.5i+2j)v=(2.5i+4j)

The resultant velocity of the boat is (2.5i+4j) m s1.

A second boat has position vector (27i+6j) m at the same time as when the first boat leaves the harbour.
The second boat sails with (constant) resultant velocity (2i+3j) m s1.

b) Without intervention, the two boats will collide at time t seconds.

i) Find the value of t.

ii) Find the coordinates of the point at which the boats will collide.

i) The position of a particle at time t is r=r0+tv where r0 is the initial position and v is its (resultant) velocity.

The two boats will be in the same position when they collide.

 (0i+0j)+t(2.5i+4j)=(27i+6j)+t(2i+3j)

Equating i (or j) components gives an equation in t.

2.5t=272t4.5t=27t=6      or       4t=6+3tt=6

The boats collide at t=6 seconds.

ii) Find the position of either boat at t=6 seconds.

r=(0i+0j)+6(2.5i+4j)r=(15i+24j)

The question asks for coordinates (rather than a position vector).

The boats will collide at the point (15, 24).

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Dan Finlay

Author: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.

Lucy Kirkham

Reviewer: Lucy Kirkham

Expertise: Content Creator

Lucy has been a passionate Maths teacher for over 12 years, teaching maths across the UK and abroad helping to engage, interest and develop confidence in the subject at all levels.Working as a Head of Department and then Director of Maths, Lucy has advised schools and academy trusts in both Scotland and the East Midlands, where her role was to support and coach teachers to improve Maths teaching for all.