Newton-Raphson Method (Edexcel International AS Further Maths)

Revision Note

Mark Curtis

Written by: Mark Curtis

Reviewed by: Dan Finlay

Newton-Raphson Method

How do I apply the Newton-Raphson method?

  • The Newton-Raphson method is a process for finding roots of equations

    • Equations must be rearranged into the form straight f open parentheses x close parentheses equals 0

  • If x equals alpha is a root of the equation straight f open parentheses x close parentheses equals 0, then you need to choose x subscript 0, the initial (first) approximation

    • This is usual given in the question (and is a value near to the root)

  • You can then find successive approximations x subscript 1, x subscript 2, x subscript 3, ... using the Newton-Raphson formula:

    • x subscript n plus 1 end subscript equals x subscript n minus fraction numerator straight f open parentheses x subscript n close parentheses over denominator straight f apostrophe open parentheses x subscript n close parentheses end fraction

    • This is an iterative formula

    • straight f apostrophe open parentheses x close parentheses is the derivative of straight f open parentheses x close parentheses

      • Work this out beforehand

  • Increasing the number of approximations improves the accuracy

    • The Newton-Raphson method usually converges quickly to the root compared to other methods

Examiner Tips and Tricks

The formula for the Newton-Raphson method is given in the Formulae Booklet.

How do I apply the Newton-Raphson method on my calculator?

  • If your calculator has a recursion function

    • Input the formula, start value and number of steps

    • The output is a table showing all the approximations

  • Alternatively:

    • Type in the value of x subscript 0 and press =

      • This stores it in the "Ans" (answer) button

    • Type Ans minus fraction numerator straight f open parentheses Ans close parentheses over denominator straight f apostrophe open parentheses Ans close parentheses end fraction into your calculator and press =

      • This finds x subscript 1

    • Without pressing any other button, press = again

      • This finds x subscript 2

    • Repeatedly pressing = gives further approximations

      • The more you press it, the closer to the root it becomes

How does the Newton-Raphson method work geometrically?

  • The method works by drawing a tangent to the curve y equals straight f open parentheses x close parentheses at x equals x subscript 0

    • then finding where the tangent cuts the x-axis

    • This x-intercept is the new approximation, x subscript 1

  • This process is then repeated

    • Draw the tangent to y equals straight f open parentheses x close parentheses at x equals x subscript 1

    • Find its x-intercept and call it x subscript 2

  • The approximations get closer and closer to the root

A geometric explanation as to how the Newton Raphson Method works

How do I know if the Newton-Raphson method will fail?

  • The Newton-Raphson method fails if the initial value, x subscript 0, satisfies straight f apostrophe open parentheses x subscript 0 close parentheses equals 0

    • Algebraically, this is because the formula x subscript n plus 1 end subscript equals x subscript n minus fraction numerator straight f open parentheses x subscript n close parentheses over denominator straight f apostrophe open parentheses x subscript n close parentheses end fraction cannot divide by zero

    • Geometrically, this is because x subscript 0 is at a stationary point on the curve y equals straight f open parentheses x close parentheses

      • A tangent drawn at a stationary point is horizontal

      • This will never intersect the x-axis

  • The Newton-Raphson method also fails if the sequence x subscript 1, x subscript 2, x subscript 3, ... diverges

    • This can happen if x subscript 0 is chosen:

      • too far away from the root

      • or at a point where the gradient is very small

  • The Newton-Raphson method is sometimes avoided when straight f open parentheses x close parentheses is too tricky to differentiate

A diagram showing cases when the Newton Rahpson method fails

Worked Example

The equation 2 x to the power of 4 minus 4 x cubed equals negative 1 has a solution in the interval open square brackets 1 comma space 2 close square brackets.

(a) Using x subscript 0 equals 2 as the first approximation to the solution, apply the Newton-Raphson method to find a second approximation.

Rearrange the formula into the form straight f open parentheses x close parentheses equals 0

2 x to the power of 4 minus 4 x cubed plus 1 equals 0 so straight f open parentheses x close parentheses equals 2 x to the power of 4 minus 4 x cubed plus 1

(You could also use negative 1 plus 4 x cubed minus 2 x to the power of 4)
Find straight f apostrophe open parentheses x close parentheses using differentiation

straight f apostrophe open parentheses x close parentheses equals 8 x cubed minus 12 x squared

Substitute straight f open parentheses x close parentheses and straight f apostrophe open parentheses x close parentheses into the Newton-Raphson formula x subscript n plus 1 end subscript equals x subscript n minus fraction numerator straight f open parentheses x subscript n close parentheses over denominator straight f apostrophe open parentheses x subscript n close parentheses end fraction

x subscript n plus 1 end subscript equals x subscript n minus fraction numerator open parentheses 2 x subscript n to the power of 4 minus 4 x subscript n cubed plus 1 close parentheses over denominator open parentheses 8 x subscript n cubed minus 12 x subscript n squared close parentheses end fraction

Substitute x subscript 0 equals 2 into the formula to get x subscript 1

x subscript 1 equals 2 minus fraction numerator open parentheses 2 cross times 2 to the power of 4 minus 4 cross times 2 cubed plus 1 close parentheses over denominator open parentheses 8 cross times 2 cubed minus 12 cross times 2 squared close parentheses end fraction
equals 2 minus 1 over 16
equals 1.9375

Check this solution lies in the interval open square brackets 1 comma space 2 close square brackets

x subscript 1 equals 1.9375

31 over 16 is also accepted

(b) Explain why the midpoint of the interval open parentheses 1 comma space 2 close parentheses cannot be used as the first approximation when applying the Newton-Raphson method.

The Newton-Raphson method fails if x subscript 0 satisfies straight f apostrophe open parentheses x subscript 0 close parentheses equals 0
Find the midpoint of the interval

x subscript 0 equals fraction numerator 1 plus 2 over denominator 2 end fraction equals 1.5

Check if straight f apostrophe open parentheses 1.5 close parentheses equals 0

straight f apostrophe open parentheses 1.5 close parentheses equals 8 cross times 1.5 cubed minus 12 cross times 1.5 squared equals 0

Write a conclusion either about dividing by zero, or about having a horizontal tangent

straight f apostrophe open parentheses 1.5 close parentheses equals 0, but you cannot divide by zero in the formula x subscript n plus 1 end subscript equals x subscript n minus fraction numerator straight f open parentheses x subscript n close parentheses over denominator straight f apostrophe open parentheses x subscript n close parentheses end fraction
So 1.5 cannot be used as the first approximation

You could also say that x equals 1.5 is at a stationary point where the tangent is horizontal, meaning it cannot intersect the x-axis to make x subscript 1

Last updated:

You've read 0 of your 5 free revision notes this week

Sign up now. It’s free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.