Equating Real & Imaginary Parts (Edexcel International AS Further Maths)

Revision Note

Mark Curtis

Written by: Mark Curtis

Reviewed by: Dan Finlay

Equating Real & Imaginary Parts

How do I equate real and imaginary parts?

  • If two complex expressions are equal, then

    • their real parts are equal

    • and their imaginary parts are equal

  • If a plus b straight i equals 8 minus 10 straight i where a and b are real

    • then a equals 8 (equating real parts)

    • and b equals negative 10 (equating imaginary parts)

How do I solve equations using real and imaginary parts?

  • Introduce z equals x plus y straight i for expressions in z

  • For example, solve z plus 2 z asterisk times equals 12 minus straight i

    • Let z equals x plus y straight i

    • Substitute in

      • open parentheses x plus y straight i close parentheses plus 2 open parentheses x minus y straight i close parentheses equals 12 minus i

    • Expand and collect terms

      • 3 x minus y straight i equals 12 minus straight i

    • Equate real and imaginary parts

      • 3 x equals 12 gives x equals 4

      • negative y equals negative 1 gives y equals 1

    • Substitute back into z

      • z equals 4 plus straight i

How do I use real and imaginary parts with modulus signs?

  • If z equals x plus y straight i then vertical line z vertical line equals square root of x squared plus y squared end root

  • Helpful modulus rules are:

    • vertical line z subscript 1 z subscript 2 vertical line equals vertical line z subscript 1 vertical line vertical line z subscript 2 vertical line

    • open vertical bar z subscript 1 over z subscript 2 close vertical bar equals fraction numerator open vertical bar z subscript 1 close vertical bar over denominator open vertical bar z subscript 2 close vertical bar end fraction

    • vertical line z vertical line equals vertical line z asterisk times vertical line

    • z z asterisk times equals z asterisk times z equals vertical line z vertical line squared

      • Proved using z equals x plus y straight i and z asterisk times equals x minus y straight i

  • For example, find p if z subscript 1 equals p plus p straight i, z subscript 2 equals 2 straight i and vertical line z subscript 1 z subscript 2 vertical line equals 6 square root of 2

    • Use vertical line z subscript 1 z subscript 2 vertical line equals vertical line z subscript 1 vertical line vertical line z subscript 2 vertical line

      • vertical line p plus p straight i vertical line vertical line 2 straight i vertical line equals 6 square root of 2

    • Use vertical line z vertical line equals square root of x squared plus y squared end root

      • square root of p squared plus p squared end root cross times 2 equals 6 square root of 2 so 2 square root of 2 p squared end root equals 6 square root of 2

    • Square both sides and simplify

      • p squared equals 9

      • p equals plus-or-minus 3

Examiner Tips and Tricks

Harder exam questions may not tell you to write z as x plus y straight i (you have to spot it yourself).

Worked Example

Let z and w be complex numbers.
It is known that w equals 5 plus 2 straight i and that z squared plus 10 w equals z z asterisk times.

Find the two possible values of z.

Write z in the form x plus y straight i

z equals x plus y straight i

Substitute this, and w, into the equation

open parentheses x plus y straight i close parentheses squared plus 10 open parentheses 5 plus 2 straight i close parentheses equals open parentheses x plus y straight i close parentheses open parentheses x minus y straight i close parentheses

Expand the brackets and use straight i squared equals negative 1

x squared plus 2 x y straight i plus y squared straight i squared plus 50 plus 20 straight i equals x squared minus y squared straight i squared
x squared plus 2 x y straight i minus y squared plus 50 plus 20 straight i equals x squared plus y squared

Equate the real parts and solve for y

table row cell x squared minus y squared plus 50 end cell equals cell x squared plus y squared end cell row 50 equals cell 2 y squared end cell row 25 equals cell y squared end cell row y equals cell plus-or-minus 5 end cell end table

Now equate the imaginary parts and solve for x
Note that there are no imaginary parts on the right

table row cell 2 x y plus 20 end cell equals 0 row cell x y end cell equals cell negative 10 end cell row x equals cell negative 10 over y end cell end table

When y equals 5, then x equals negative 2
When y equals negative 5, then x equals 2
Substitute these back in to get z

negative 2 plus 5 straight i or 2 minus 5 straight i

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.