Which are correct for the reaction shown?
CH3COOH + KOH → CH3COO−K++ H2O ΔH = –55.8 kJ mol−1
|
| Type of reaction | Type of enthalpy change |
☐ | A | endothermic | formation |
☐ | B | endothermic | neutralisation |
☐ | C | exothermic | formation |
☐ | D | exothermic | neutralisation |
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