Acid-Base Titrations with Indicators (Edexcel International AS Chemistry): Revision Note
Acid-Base Titrations with Indicators
Acid-base titrations are used to find the unknown concentrations of solutions of acids and bases
Acid-base indicators give information about the change in chemical environment
They change colour reversibly depending on the concentration of H+ ions in the solution
Indicators are weak acids and bases where the conjugate bases and acids have a different colour
Many acid-base indicators are derived from plants, such as litmus
Common Indicators Table
A good indicator gives a very sharp colour change at the equivalence point
In titrations is it not always possible to use two colour indicators because of this limitation, so for example litmus cannot be used successfully in a titration
When phenolphthalein is used, it is usually better to have the base in the burette because it is easier to see the sudden and permanent appearance of a colour (pink in this case) than the change from a coloured solution to a colourless one
Volumes & concentrations of solutions
The concentration of a solution is the amount of solute dissolved in a solvent to make 1 dm3 of solution
The solute is the substance that dissolves in a solvent to form a solution
The solvent is often water
Concentration (mol dm3) =
A concentrated solution is a solution that has a high concentration of solute
A dilute solution is a solution with a low concentration of solute
When carrying out calculations involve concentrations in mol dm-3 the following points need to be considered:
Change mass in grams to moles
Change cm3 to dm3
To calculate the mass of a substance present in solution of known concentration and volume:
Rearrange the concentration equation
number of moles (mol) = concentration (mol dm-3) x volume (dm3)
Multiply the moles of solute by its molar mass
mass of solute (g) = number of moles (mol) x molar mass (g mol-1)
Worked Example
Neutralisation calculation
25.0 cm3 of 0.050 dm-3 sodium carbonate was completely neutralised by 20.00 cm3 of dilute hydrochloric acid. Calculate the concentration in mol dm-3 of the hydrochloric acid.
Answer
Step 1: Write the balanced symbol equation
Na2CO3 + 2HCl → 2NaCl + H2O + CO2
Step 2: Calculate the amount, in moles, of sodium carbonate reacted by rearranging the equation for amount of substance (mol) and dividing the volume by 1000 to convert cm3 to dm3
amount (Na2CO3) = 0.025 dm3 x 0.050 mol dm-3 = 0.00125 mol
Step 3: Calculate the moles of hydrochloric acid required using the reaction’s stoichiometry
1 mol of Na2CO3 reacts with 2 mol of HCl, so the molar ratio is 1 : 2
Therefore 0.00125 moles of Na2CO3 react with 0.00250 moles of HCl
Step 4: Calculate the concentration, in mol dm-3, of hydrochloric acid
concentration (HCl) (mol dm-3) = 0.125 mol dm-3
Worked Example
Concentration in g dm-3
A student dissolved 10 g of sodium hydroxide, NaOH, in 2 dm3 of distilled water. Calculate the concentration of the solution.
Answer:
Uncertainty - Calculations
Percentage Uncertainties
Percentage uncertainties are a way to compare the significance of an absolute uncertainty on a measurement
This is not to be confused with percentage error, which is a comparison of a result to a literature value
The formula for calculating percentage uncertainty is as follows:
Adding or subtracting measurements
When you are adding or subtracting two measurements then you add together the absolute measurement uncertainties
For example,
Using a balance to measure the initial and final mass of a container
Using a thermometer for the measurement of the temperature at the start and the end
Using a burette to find the initial reading and final reading
In all of these examples, you have to read the instrument twice to obtain the quantity
If each time you read the instrument the measurement is ‘out’ by the stated uncertainty, then your final quantity is potentially ‘out’ by twice the uncertainty
Total experimental uncertainty
Some experiments use multiple pieces of equipment, which each have a measure of uncertainty in their use
For example, a titration against a standard solution will have the following uncertainties:
Using a balance to measure the mass of the solid used to make the standard solution
Using a volumetric flask to make the standard solution
Using a volumetric pipette to measure the sample that is being titrated against
Using a burette to find the initial reading and final reading that determine the titre volume
If each piece of equipment used in the experiment has its own associated uncertainty, you can determine the total experimental uncertainty by adding the total individual uncertainties
For example, a titration against a standard solution may have:
An uncertainty of ±0.5% for the use of the balance
An uncertainty of ±0.1% for the use of the volumetric flask
An uncertainty of ±0.2% for the use of the volumetric pipette
An uncertainty of ±0.4% for the use of the burette
Therefore, the total experimental uncertainty would be 0.5 + 0.1 + 0.2 + 0.4 = ±1.2%
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