Magnetic Force on a Current-Carrying Conductor (Edexcel International A Level Physics)

Revision Note

Katie M

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Katie M

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Magnetic Force on a Current-Carrying Conductor

  • A current-carrying conductor produces its own magnetic field

    • An external magnetic field will therefore exert a magnetic force on it

  • A current-carrying conductor (eg. a wire) will experience the maximum magnetic force if the current through it is perpendicular to the direction of the magnetic flux lines

    • A simple situation would be a copper rod placed within a uniform magnetic field

    • When current is passed through the copper rod, it experiences a force which makes it accelerate

Copper rod experiment, downloadable AS & A Level Physics revision notes

A copper rod moves within a magnetic field when current is passed through it

  • The force F on a conductor carrying current I in a magnetic field with flux density B is defined by the equation

F = BIL sin θ

  • Where:

    • F = magnetic force on the current-carrying conductor (N)

    • B = magnetic flux density of external magnetic field (T)

    • I = current in the conductor (A)

    • L = length of the conductor in the field (m)

    • θ = angle between the conductor and external flux lines (degrees)

  • This equation shows that the magnitude of the magnetic force F is proportional to:

    • Current I 

    • Magnetic flux density B

    • Length of conductor in the field L

    • The sine of the angle θ between the conductor and the magnetic flux lines

Force on conductor (1), downloadable AS & A Level Physics revision notes
Force on conductor (2), downloadable AS & A Level Physics revision notes

Magnitude of the force on a current carrying conductor depends on the angle of the conductor to the external B field

  • The maximum force occurs when sin θ = 1

    • This means θ = 90o and the conductor is perpendicular to the B field

    • This equation for the magnetic force now becomes:

F = BIL

  • The minimum force (0) is when sin θ = 0

    • This means θ = 0o and the conductor is parallel to the B field

  • It is important to note that a current-carrying conductor will experience no force if the current in the conductor is parallel to the field

Worked Example

A current of 0.87 A flows in a wire of length 1.4 m placed at 30o to a magnetic field of flux density 80 mT.

Calculate the force on the wire.

Answer:

Step 1: Write down the known quantities

  • Magnetic flux density, B = 80 mT = 80 × 10-3 T

  • Current, I = 0.87 A

  • Length of wire, L = 1.4 m

  • Angle between the wire and the magnetic flux lines, θ = 30o

Step 2: Write down the equation for the magnetic force on a current-carrying conductor

F = BIL sin θ

Step 3: Substitute in values and calculate

F = (80 × 10-3) × (0.87) × (1.4) × sin (30) = 0.04872 = 0.049 N (2 s.f)

Examiner Tips and Tricks

Remember that the direction of current is the flow of positive charge (i.e. conventional current) and this is in the opposite direction to the flow of electrons (i.e. electron flow)!

Fleming's Left Hand Rule for a Current-Carrying Conductor

  • Fleming's Left Hand Rule was previously used to determine the direction of the magnetic force on a moving charged particle in a magnetic field

  • It can also be used to determine the direction of the magnetic force on a current-carrying conductor in a magnetic field

    • This is because inside a conductor (e.g. a wire) there are many charged particles flowing as a current

  • As a reminder, the image representing Fleming's Left Hand Rule is shown below: 

Flemings left hand rule, downloadable AS & A Level Physics revision notes

Fleming's Left Hand Rule. Remember, current is the flow of conventional current (i.e. positive to negative)

  • Using the conventional symbols representing vectors like magnetic flux density B and force F that go into the page (arrows) or out of the page (dots) we can apply Fleming's Left Hand Rule to problems in 3D

Worked Example

A current flows perpendicularly to a uniform magnetic field as shown in the diagram below. 

Worked example - LH rule question image, downloadable AS & A Level Physics revision notes

As a result, the conductor carrying the current experiences a magnetic force, F

Determine the direction of the current flowing in the conductor.

Answer:

Step 1: Apply the instructions for Fleming's Left Hand Rule

  • Using Fleming’s Left Hand Rule for the quantities given:

First finger is the magnetic field, B = into the page (or screen!)

Thumb is the direction of the magnetic force F = vertically downwards

Step 2: Determine the direction of the conventional current

  • The first finger should be pointing into the page (or screen!) along the direction of the field

  • Rotating the entire hand allows the thumb to point downwards, along the direction of force

  • The second finger should be pointing towards the left of the page (or screen!)

  • This is the direction of conventional current in the wire, i.e., from right to left

Worked example - LH rule solution image, downloadable AS & A Level Physics revision notes

Examiner Tips and Tricks

You will certainly need to apply Fleming's Left Hand Rule in your examination, at some point, whenever there is a current or charge flowing in a magnetic field. Remember, it is used to give the direction of either the magnetic force F, the magnetic field B, or the conventional current (or flow of positive charge) I

As ever, you will gain more confidence twisting your arm in funny positions with three fingers at right-angles the more questions you practise: the more, the better! 

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.