Unit Conversions for Energy & Mass
Units of Energy
- The electronvolt is a unit of energy
- It is equivalent to the amount of energy transferred to an electron accelerated across a potential difference of 1 V:
1 eV = 1.6 × 10–19 J
- In order to convert between electronvolts and joules:
- Multiply electronvolts by 1.6 × 10–19 to get the equivalent energy in joules
- Divide joules by 1.6 × 10–19 to get the equivalent energy in electronvolts
Converting between electronvolts and joules
- Sometimes, units of MeV or GeV are used
- These are given by:
1 MeV = 1 × 106 eV = 1.6 × 10–13 J
1 GeV = 1 × 109 eV = 1.6 × 10–10 J
Units of Mass
- Energy and mass are related by Einstein's energy-mass relation
- Therefore, units of mass can be related to units of energy by division of c2
- This provides particle physicists convenient units of calculation to work with
- This is especially useful in experiments involving particle collisions, where annihilation and creation is common
- Possible units of mass are therefore:
, or,
- The following conversions are used to convert into S.I. units:
= 1.78 × 10–30 kg
= 1.78 × 10–27 kg
Worked example
Show that the rest mass of a proton, 1.67 × 10–27 kg, is roughly equivalent to 1 GeV/c2.
Step 1: Write the known quantities
-
- Rest mass of a proton, mp = 1.67 × 10–27 kg
- Speed of light c = 3 × 108 m s–1
Step 2: Substitute quantities into Einstein's energy-mass relation
E = mpc2
E = (1.67 × 10–27) × (3 × 108)2 = 1.50 × 10–10 J
Step 3: Convert joules to electronvolts
-
- To convert a quantity of energy in joules to electronvolts, divide by 1.6 × 10–19
= 9.4 × 108 eV = 0.94 GeV
Step 4: Convert electronvolts to GeV/c2
-
- 0.94 GeV is equivalent to a mass of 0.94 GeV/c2, which is roughly 1 GeV/c2
Examiner Tip
In this worked example, we could have used the direct conversion between GeV/c2 and kg, because 1 GeV/c2 = 1.78 × 10–27 kg, but you should be super comfortable with using Einstein's energy-mass relation to find quantities of mass/energy in standard units, and converting to eV and eV/c2 the 'long way round'. Exam questions may require you to do this when the conversions are not so straightforward.