Pulse-Echo Technique (Edexcel International A Level Physics)
Revision Note
Pulse-Echo Technique
Foetal Scanning
In medicine, ultrasound can be used to construct images of a foetus in the womb
An ultrasound detector is made up of a transducer that produces and detects a beam of ultrasound waves into the body
The ultrasound waves are reflected back to the transducer by different boundaries between tissues in the path of the beam
For example, the boundary between fluid and soft tissue or tissue and bone
Using the speed of sound and the time of each echo’s return, the detector calculates the distance from the transducer to the tissue boundary
Gel is put onto the scanner so that the boundary between the instrument and the skin is of the same density as the skin, this allows the signal to be easily transmitted
By taking a series of ultrasound measurements, sweeping across an area, the time measurements may be used to build up an image
Unlike many other medical imaging techniques, ultrasound is non-invasive and harmless
Ultrasound can be used to construct an image of a foetus in the womb
Sonar
Sonar uses ultrasound to detect objects underwater
The sound wave is reflected off the object being tracked
Examples include;
Finding fish by fishing fleets
Military uses looking for underwater vessels
Mapping the ocean bottom
The time it takes for the sound wave to return is used to calculate the depth of the water
The distance the wave travels is twice the depth of the ocean
This is the distance to the ocean floor plus the distance for the wave to return
Pulse Duration and Wavelength
The amount of detail which can be captured (the resolution) of pulse-echo techniques depends on the wavelength
Shorter wavelengths have smaller (better) resolution
More detail can be seen since they diffract (spread out) less
More energy is needed as short wavelength waves have higher frequency
Wavelength is chosen to be similar in size to the object that is being resolved
This makes best use of diffraction effects
Pulse duration is a consideration because ultrasound transducers cannot transmit and receive pulses at the same time.
If incoming and outgoing pulses overlap the information is lost and image quality suffers
This affects the range since a longer wait time for pulses to return reduces the amount of information which can be collected
Ultrasound pulses are very short, only a few microseconds, to reduce reflections from nearby interfaces
The gap between pulses is relatively long, measured in milliseconds, to prevent overlapping signals
This combination of short pulses with relatively large spaces between them produces the clearest images
Worked Example
A sonar system uses ultrasound with frequency of 3.2 kHz to map the ocean floor. The speed of sound in water is 1 500 m s−1.
An echo is detected 3.6 s after the pulse is transmitted.
a) Determine the depth of the sea at this point.
b) Suggest a resolution for this ultrasound survey of the seafloor
Part (a)
Step 1: Write the known values from the question
Frequency, f = 3.2 kHz = 3 200 Hz
Speed of sound, v = 1 500 m s−1
Time, t = 3.6 s
Step 2: Write the correct equation and substitute the values
Distance;
d = vt = 1 500 × 3.6 = 5 400 m
Step 3: Account for the received signal being an echo
Total distance travelled by the signal = 5 400 m
Depth of the sea floor = 1/2 × 5 400 = 2 700 m
Part (b)
Step 1: Write the wave equation and rearrange to make wavelength the subject
Step 2: Calculate to find wavelength
Step 3: Write the final answer to correct significant figures and give units
The resolution of the signal is similar to the wavelength, and λ = 0.47 m
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