Potential Dividers (Edexcel International A Level Physics)
Revision Note
Potential Dividers
The electrical voltages rule is defined as:
The sum of the e.m.f.s in a closed circuit loop is equal to the sum of the potential differences around that loop
Therefore, when two resistors are connected in series, the potential difference across the power source will be divided across the two resistors
Potential dividers are circuits that produce an output voltage as a fraction of the input voltage
This is done by using two resistors in series to split or divide the voltage of the supply in a chosen ratio
Potential dividers have three main purposes:
To provide a variable potential difference
To enable a specific potential difference to be chosen
To split the potential difference of a power source between two or more components
Potential dividers are used widely in volume controls and sensory circuits using LDRs and thermistors
The link between the input voltage and the output voltage across each resistor is linked in an equation
Potential divider diagram and equation
The input voltage Vin is applied across both resistors, which are in series
The output voltage Vout is measured across one of the resistors, in this case resistor R2
The potential difference V across each resistor depends upon its resistance R:
The resistor with the largest resistance will have the greater potential difference across it
This is shown as a greater Vout
This is from V = IR
If the resistance of one of the resistors is increased, it will get a greater share of the potential difference, whilst the other resistor will get a smaller share
Since potential divider circuits are based on the ratio of voltage between components, and since V=IR, this is equal to the ratio of the resistances of the resistors
Therefore, the ratios of the potential differences and resistances across each resistor can be linked
Where:
V1 = potential difference of R1 (V)
V2 = potential difference or R2 (V)
Using Ohm's Law, with a constant current, I, these can also be written as:
V1 = IR1
V2 = IR2
Worked Example
The circuit shown is designed to light up a lamp when the input voltage exceeds a preset value.
Vout is equal to 5.3 V when the lamp lights.
Calculate the input voltage Vin.
Answer:
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