Cumulative Distribution Function (Edexcel International A Level Maths: Statistics 2)

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Cumulative Distribution Function

What is the cumulative distribution function (c.d.f.)?

  • For a continuous random variable,X , with probability density function f(x) the cumulative distribution function (c.d.f.) is defined as

bold F bold left parenthesis bold italic x subscript bold 0 bold right parenthesis bold equals bold italic P bold left parenthesis bold italic X bold less or equal than bold italic x subscript bold 0 bold right parenthesis bold equals bold integral subscript bold minus bold infinity end subscript superscript bold x subscript bold 0 end superscript bold f bold left parenthesis bold italic t bold right parenthesis bold space bold d bold italic t

  • Compare this to the cumulative distribution function for a discrete random variable

straight F left parenthesis x subscript 0 right parenthesis equals P left parenthesis X less or equal than x subscript 0 right parenthesis equalssum for x less or equal than x subscript 0 of straight P left parenthesis X equals x right parenthesis

  • F(x0) is the probability that X is a value less than or equal to x0
  • Notice the use of uppercase text F end text for the c.d.f. but lowercase text f end text  for the p.d.f.
  • On the graph of the p.d.f. y= f(x)  this would be the area under the graph up to the (vertical) line x=x0
  •  F(x) should be defined for all values of x element of straight real numbers
  • The graph of the c.d.f. y = F(x) will
    • start on the x-axis (i.e. start at a probability of 0)
    • end at x = 1  (i.e. finish at a probability of 1)
    • will be continuous function, even when defined piecewise

e.g.

straight F left parenthesis x right parenthesis equals open curly brackets table row 0 cell x less than 0 end cell row cell 0.5 x squared end cell cell 0 less or equal than x less or equal than 1 end cell row cell 0.5 end cell cell 1 less or equal than x less or equal than 1.5 end cell row cell x minus 1 end cell cell 1.5 less or equal than x less or equal than 2 end cell row 1 cell x greater than 2 end cell end table close

BSM6-gbH_1-4-1-ial-fig1-cdf-graph

 

  • The horizontal lines at F(x) = 0 and F(x) = 1 may not always be shown

How do I find probabilities using the cumulative frequency distribution?

  • straight P left parenthesis a less or equal than X less or equal than b right parenthesis equals straight F left parenthesis b right parenthesis minus straight F left parenthesis a right parenthesis
  • Although straight P left parenthesis X equals k right parenthesis, for all values of k , F(k) is not necessarily zero

How do I find the cumulative frequency distribution (c.d.f.) from the probability density function (p.d.f.) and vice versa?

 

  • To find the c.d.f.,F(x)  , from the p.d.f.,f(x), integrate

straight F left parenthesis x right parenthesis equals integral subscript negative infinity end subscript superscript x straight f left parenthesis t right parenthesis space d t

    • Ensure you define F(x) fully forx element of straight real numbers  so include values of x for which F(x) = 0  and values of x for which F(x) = 1
    • For piecewise functions as well as integrating you will need to add on the value of the c.d.f. at the end of the previous part
      • Suppose there are two sections to a p.d.f. x less or equal than a and x greater than a
      • For x greater than a:

straight F left parenthesis x right parenthesis equals integral subscript negative infinity end subscript superscript x straight f left parenthesis t right parenthesis space straight d t space equals integral subscript negative infinity end subscript superscript a straight f left parenthesis t right parenthesis space straight d t space plus integral subscript a superscript x straight f left parenthesis t right parenthesis space straight d t space equals space straight F left parenthesis a right parenthesis plus integral subscript a superscript x straight f left parenthesis t right parenthesis space straight d t

    • Therefore the c.d.f can be calculated for the interval a < x < b  by using

straight F left parenthesis x right parenthesis space equals space straight F left parenthesis a right parenthesis space plus space integral subscript a superscript x straight f left parenthesis t right parenthesis space straight d t

      • See part (b) in the Worked Example below
  • To find the p.d.f from the c.d.f., differentiate

straight f left parenthesis x right parenthesis equals fraction numerator d over denominator d x end fraction straight F left parenthesis x right parenthesis

  • Any part of a c.d.f that is constant corresponds to the p.d.f. for that part being zero (the derivative of a constant is zero)

How do I find the median, quartiles and percentiles using the cumulative frequency distribution (c.d.f.)?

 

  • For piecewise functions, first identify the section the required value lies in
    • To do this find the upper limit of each section of the c.d.f.
  • To find the medianm, solve the equation F(m) = 0.5
    • The median is sometimes referred to as the second quartile, Q2
  • To find the lower quartile, Q1, solve the equation F(Q1) = 0.25
  • To find the upper quartile,Q3  , solve the equation F(Q3 ) = 0.75
  • To find the nth percentile, solve the equation  straight F left parenthesis p right parenthesis equals n over 100

Worked example

a)
The continuous random variable, X , has cumulative distribution function

 

straight F left parenthesis x right parenthesis equals open curly brackets table row cell space space space space space space space 0 end cell cell x less than 0 end cell row cell 1 fourth x open parentheses 4 minus x close parentheses end cell cell 0 less or equal than x less or equal than 2 end cell row cell space space space space space space space 1 end cell cell x greater than 2 end cell end table close

Find

(i)
straight P left parenthesis X greater than 1.5 right parenthesis
(ii)
straight P left parenthesis 0.5 less or equal than X less or equal than 1 right parenthesis
(iii)

The lower quartile of X.

(b)       The continuous random variable, X, has probability density function

 f left parenthesis x right parenthesis equals open curly brackets table row cell 0.5 x end cell cell 0 less or equal than x less or equal than 1 end cell row cell 0.5 end cell cell 1 less or equal than x less or equal than 2.5 end cell row 0 otherwise end table close
 

Find the cumulative frequency distribution, straight F left parenthesis x right parenthesis .

a)
The continuous random variable, X , has cumulative distribution function

 

straight F left parenthesis x right parenthesis equals open curly brackets table row cell space space space space space space space 0 end cell cell x less than 0 end cell row cell 1 fourth x open parentheses 4 minus x close parentheses end cell cell 0 less or equal than x less or equal than 2 end cell row cell space space space space space space space 1 end cell cell x greater than 2 end cell end table close

Find

(i)
straight P left parenthesis X greater than 1.5 right parenthesis
(ii)
straight P left parenthesis 0.5 less or equal than X less or equal than 1 right parenthesis
(iii)

The lower quartile of X.

1-4-1-ial-fig2-we-solution-part-1

(b)       The continuous random variable, X, has probability density function

 f left parenthesis x right parenthesis equals open curly brackets table row cell 0.5 x end cell cell 0 less or equal than x less or equal than 1 end cell row cell 0.5 end cell cell 1 less or equal than x less or equal than 2.5 end cell row 0 otherwise end table close
 

Find the cumulative frequency distribution, straight F left parenthesis x right parenthesis .

1-4-1-ial-fig2-we-solution-part-2

Examiner Tip

  • Remember that P(X=k) = 0  , for any value of k, is zero
    • This can be easily missed when working with c.d.f. rather than a p.d.f.
  • A quick check you can do is verify that your c.d.f. is continuous
    • The value of the c.d.f. at the upper limit of one section should equal the value of the c.d.f at the lower limit of the next section

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Paul

Author: Paul

Expertise: Maths

Paul has taught mathematics for 20 years and has been an examiner for Edexcel for over a decade. GCSE, A level, pure, mechanics, statistics, discrete – if it’s in a Maths exam, Paul will know about it. Paul is a passionate fan of clear and colourful notes with fascinating diagrams – one of the many reasons he is excited to be a member of the SME team.