Modulus & Argument (Edexcel International A Level Further Maths)

Revision Note

Mark Curtis

Written by: Mark Curtis

Reviewed by: Dan Finlay

Argand Diagrams

What is an Argand diagram?

  • An Argand diagram is a 2D Cartesian grid used to visualise complex numbers

  • The complex number x plus y straight i is represented by the point with coordinates left parenthesis x comma space y right parenthesis

    • The real part is measured along the x -axis

      • called the real axis, written "Re"

    • The imaginary part is measured along the y -axis

      • called the imaginary axis, written "Im"

  • Complex numbers can be thought of as points, or as vectors from the origin

8-2-1-argand-diagrams---basics-diagram-1
8-2-1-argand-diagrams---basics-diagram-2

Examiner Tips and Tricks

If asked to sketch an Argand diagram, it does not need to be to scale (plotted), but should roughly show the correct positions.

Worked Example

Sketch, on the same Argand diagram, the complex numbers 5 plus 7 straight i and negative 4 minus 2 straight i.

Two complex numbers plotted on an Argand diagram

Modulus & Argument

How do I find the modulus of a complex number?

The modulus of a complex number
  • The modulus of a complex number is its distance from the origin on an Argand diagram

    • It is written open vertical bar z close vertical bar

    • If z equals x plus straight i y, then by Pythagoras' theorem

      • open vertical bar z close vertical bar equals square root of x squared plus y squared end root

  • A modulus is always positive or zero

    • It cannot be negative

  • For example

    • vertical line 3 plus 4 straight i vertical line equals square root of 3 squared plus 4 squared end root equals 5

    • vertical line 1 minus straight i vertical line equals square root of 1 squared plus open parentheses negative 1 close parentheses squared end root equals square root of 2

    • vertical line minus 5 vertical line equals 5

    • vertical line 8 straight i vertical line equals 8

    • vertical line 0 plus 0 straight i vertical line equals 0

What rules does the modulus follow?

  • Helpful modulus rules are:

    • vertical line z subscript 1 z subscript 2 vertical line equals vertical line z subscript 1 vertical line vertical line z subscript 2 vertical line

    • open vertical bar z subscript 1 over z subscript 2 close vertical bar equals fraction numerator open vertical bar z subscript 1 close vertical bar over denominator open vertical bar z subscript 2 close vertical bar end fraction

    • vertical line z vertical line equals vertical line z asterisk times vertical line

    • z z asterisk times equals z asterisk times z equals vertical line z vertical line squared

      • Proved using z equals x plus y straight i and z asterisk times equals x minus y straight i

  • Be careful:open vertical bar z subscript 1 plus z subscript 2 close vertical bar not equal to open vertical bar z subscript 1 close vertical bar plus vertical line z subscript 2 vertical line

    • For example, z subscript 1 equals 3 plus 4 straight i and z subscript 2 equals negative 3 plus 4 straight i 

      • open vertical bar z subscript 1 close vertical bar equals square root of 3 squared plus 4 squared end root equals 5 and vertical line z subscript 2 vertical line equals square root of open parentheses negative 3 close parentheses squared plus 4 squared end root equals 5

      • so vertical line z subscript 1 vertical line plus vertical line z subscript 2 vertical line equals 10

      • but z subscript 1 plus z subscript 2 equals 8 straight i so open vertical bar z subscript 1 plus z subscript 2 close vertical bar equals 8

How do I find the argument of a complex number?

A diagram showing the different cases of arguments of a complex number
  • The argument of a complex number is the angle in radians that it makes to the positive real axis

    • It is written as arg space z

    • The positive direction is anticlockwise

  • The range normally used is negative pi space less than space arg space z space less or equal than space pi

    • This is called the principal range

    • The sign of the angle depends on the quadrant:

      • The 1st quadrant is positive acute

      • The 2nd quadrant is positive obtuse

      • The 3rd quadrant is negative obtuse

      • The 4th quadrant is negative acute

  • Arguments are found by

    • drawing a sketch

    • forming a right-angled triangle

    • using trigonometry

  • The argument of the origin, arg space open parentheses 0 plus 0 straight i close parentheses, is undefined

    • No angle can be drawn

Examiner Tips and Tricks

Always draw a sketch to see which quadrant the complex number is in.

Worked Example

(a) Find the modulus and argument of z equals 2 plus 3 straight i, giving your answers correct to 3 significant figures.

Sketch this on an Argand diagram
Form a right-angled triangle

The complex number 2 + 3i on an Argand diagram

Use open vertical bar z close vertical bar equals square root of x squared plus y squared end root (or Pythagoras) to find the modulus

table row cell vertical line z vertical line end cell equals cell square root of 2 squared plus 3 squared end root end cell row blank equals cell square root of 13 end cell row blank equals cell 3.60555127... end cell end table

z is in the first quadrant so the argument is positive and acute
Use trigonometry to find the argument theta in radians

table row cell tan space theta end cell equals cell 3 over 2 end cell row theta equals cell tan to the power of negative 1 end exponent open parentheses 3 over 2 close parentheses end cell row theta equals cell 0.98279372... end cell end table

Round the answers to 3 significant figures

vertical line z vertical line equals 3.61 and arg space z equals 0.983 to 3 significant figures

(b) Find the modulus and argument of w equals negative 1 minus square root of 3 straight i blank, leaving your answers as exact values.

Sketch this on an Argand diagram
Form a right-angled triangle

A complex number in the third quadrant on an Argand diagram

Use open vertical bar z close vertical bar equals square root of x squared plus y squared end root (or Pythagoras) to find the modulus

table row cell vertical line z vertical line end cell equals cell square root of open parentheses negative 1 close parentheses squared plus open parentheses negative square root of 3 close parentheses squared end root end cell row blank equals cell square root of 4 end cell row blank equals 2 end table

z is in the third quadrant so the argument is negative and obtuse
Use trigonometry to first find alpha in radians

table row cell tan space alpha end cell equals cell fraction numerator square root of 3 over denominator 1 end fraction end cell row alpha equals cell tan to the power of negative 1 end exponent open parentheses square root of 3 close parentheses end cell row alpha equals cell pi over 3 end cell end table

Then find theta by subtracting alpha from 180° (pi radians)

table row theta equals cell pi minus alpha end cell row blank equals cell pi minus pi over 3 end cell row blank equals cell fraction numerator 2 pi over denominator 3 end fraction end cell end table

Remember that the argument here must be a negative angle

vertical line z vertical line equals 2 and arg space z equals negative fraction numerator 2 pi over denominator 3 end fraction

These answers must be exact

Modulus-Argument Form

What is modulus-argument form?

8-2-3_notes_fig3
  • All complex numbers can be written in the form:

    • z equals r open parentheses cos space theta plus isin space theta close parentheses

    • where r equals vertical line z vertical line and theta equals arg space z

      • This is called the modulus-argument (or polar) form

  • Negative arguments should be shown clearly without simplifying

    • z equals 2 open parentheses cos space open parentheses negative pi over 3 close parentheses plus isin space open parentheses negative pi over 3 close parentheses close parentheses

      • Simplifying them gives the Cartesian form

      •  z equals 2 open parentheses 1 half plus straight i open parentheses negative fraction numerator square root of 3 over denominator 2 end fraction close parentheses close parentheses equals 1 minus square root of 3 blank straight i

  • Be careful: z equals r open parentheses cos space theta minus isin space theta close parentheses is not in modulus-argument form (due to the minus sign)

    • Rewrite it as z equals r open parentheses cos invisible function application open parentheses negative theta close parentheses plus isin invisible function application open parentheses negative theta close parentheses close parentheses

      • This uses the symmetries cos open parentheses negative theta close parentheses identical to cos open parentheses theta close parentheses and sin open parentheses negative theta close parentheses identical to negative sin space theta

    • The argument is negative theta

Worked Example

Write z space equals space minus 4 space plus space 4 straight i in the exact form r left parenthesis cos space theta space plus space straight i space sin space theta right parenthesis where r greater than 0 and negative pi less than theta less or equal than pi.

Draw a sketch to find the modulus, r, and argument, theta, of z
Form a right-angled triangle

The complex number -4+4i on an Argand diagram

Use open vertical bar z close vertical bar equals square root of x squared plus y squared end root (or Pythagoras) to find the modulus

table row cell vertical line z vertical line end cell equals cell square root of open parentheses negative 4 close parentheses squared plus open parentheses 4 close parentheses squared end root end cell row blank equals cell square root of 32 end cell row blank equals cell 4 square root of 2 end cell end table

z is in the second quadrant so the argument is positive and obtuse
Use trigonometry to first find alpha in radians

table row cell tan space alpha end cell equals cell 4 over 4 end cell row alpha equals cell tan to the power of negative 1 end exponent open parentheses 1 close parentheses end cell row alpha equals cell pi over 4 end cell end table

Then find theta by subtracting alpha from 180° (pi radians)

table row theta equals cell pi minus alpha end cell row blank equals cell pi minus pi over 4 end cell row blank equals cell fraction numerator 3 pi over denominator 4 end fraction end cell end table

Write the final answer in the form r left parenthesis cos space theta space plus space straight i space sin space theta right parenthesis

z equals 4 square root of 2 open parentheses cos open parentheses fraction numerator 3 pi over denominator 4 end fraction close parentheses plus straight i italic space sin space open parentheses fraction numerator 3 pi over denominator 4 end fraction close parentheses close parentheses

Leave the modulus and argument exact

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.