Constructing Born–Haber Cycles (Oxford AQA International A Level Chemistry)
Revision Note
Written by: Philippa Platt
Reviewed by: Stewart Hird
Constructing Born–Haber Cycles
The basic principle of drawing a Born-Haber cycle is to construct a diagram in which energy increases going up the diagram
The cycle shows all the steps needed to turn atoms into gaseous ions and from gaseous ions into the ionic lattice
The alternative route to the ionic lattice is the enthalpy of formation of the elements in their standard states
Drawing the cycle for sodium chloride
Step 1 - starting elements
A good starting point is to write the elements required to form the ionic compound
This should be placed:
On the left hand side of the diagram
About a third of the way up the diagram
The elements required should:
Be written on their own energy level, shown by a horizontal line
Include state symbols
Step 2 - gaseous atoms
The second step is to create the gaseous atoms
Creating gaseous ions is a bond breaking process, so arrows must be drawn upwards
It doesn't matter whether you start with sodium or chlorine
The enthalpy of atomisation of sodium is:
Na (s) → Na (g) ΔHatꝋ = +108 kJ mol -1
The enthalpy of atomisation of chlorine is:
½Cl2 (g) → Cl (g) ΔHatꝋ = +121 kJ mol -1
We can show the products of the process on the horizontal lines and the energy value against a vertical arrow connecting the energy levels
Step 3 - gaseous ions
The third step is to create the gaseous ions
The sodium ion loses an electron, so this energy change is the first ionisation energy for sodium:
Na (g) → Na+ (g) + e– ΔHieꝋ = +500 kJ mol-1
The change is endothermic so the direction continues upwards
The chlorine atom gains an electron, so this is electron affinity:
Cl (g) + e– → Cl- (g) ΔHeaꝋ = -364 kJ mol-1
The exothermic change means this is downwards
The change is displaced to the right to make the diagram easier to read
Step 4 - forming the ionic lattice
The two remaining parts of the cycle can now be completed:
Enthalpy of formation
Lattice enthalpy
The enthalpy of formation of sodium chloride is added:
On the left hand side of the diagram
At the bottom of the diagram
Na (s) + ½Cl2 (g) → NaCl (s) ΔHfꝋ = -411 kJ mol -1
This is an exothermic change for sodium chloride so the arrow points downwards
The lattice enthalpy is usually the enthalpy of lattice formation
The lattice enthalpy is added:
On the right hand side of the diagram
At the bottom of the diagram
This is usually shown as lattice formation
For sodium chloride the equation is:
Na+(g) + Cl-(g) → NaCl (s) ΔHlattꝋ
This is an exothermic change for sodium chloride so the arrow points downwards
The cycle is now complete and can be used to calculate the lattice enthalpy of an ionic solid
It can also be used to find other enthalpy changes if you are given the lattice enthalpy
Worked Example
Using the information in the table construct a Born-Haber cycle for MgCl2.
Enthalpy change | Enthalpy change / kJ mol-1 |
---|---|
Enthalpy of atomisation of Mg | +148 |
Enthalpy of atomisation of Cl | +122 |
First ionisation energy of Mg | +738 |
Second ionisation energy of Mg | +1451 |
Electron affinition of Cl | -349 |
Enthalpy of formation of MgCl2 | -641 |
Lattice formation enthalpy | -2524 |
Answer:
Each enthalpy change given in the table should have:
It's own arrow
A label for the enthalpy change (e.g. ΔHfꝋ )
An equation (including state symbols and electrons)
A value for enthalpy change, including if it needs to be doubled
Watch out for:
You must include the two different ionisation energies for magnesium as a 2+ ion is formed
There are two chlorine atoms required for the compound, so the atomisation and electron affinity of chlorine must both be doubled
Make sure your arrows point in the correct direction
Exothermic (negative value) arrow points down
Endothermic (positive value) arrow points up
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