Measuring the Rate of a Reaction (Oxford AQA International A Level Chemistry)

Revision Note

Richard Boole

Written by: Richard Boole

Reviewed by: Stewart Hird

Required Practical 7: Measuring the Rate of a Reaction

Required practical 7 is split into:

  • Part A: Measuring the rate of reaction by an initial rate method

  • Part B: Measuring the rate of reaction by a continuous monitoring method

Part A: Measuring the rate of reaction by an initial rate method

Objective

Use an 'iodine clock' experiment to investigate the reaction of iodide(V) ions with hydrogen peroxide in acidic solution and determine the order of the reaction with respect to iodide ions

Apparatus

  • 0.25 mol dm–3 dilute sulfuric acid, H2SO4 (aq)

  • 0.10 mol dm–3 potassium iodide solution, KI (aq)

  • A burette of 0.05 mol dm–3 sodium thiosulfate solution, Na2S2O3 (aq)

  • 0.10 mol dm–3 hydrogen peroxide solution, H2O2 (aq)

  • Starch solution

  • 50 cm3 burettes with funnel, stand and clamp

  • White tile

  • Pipette

  • Measuring cylinders

  • 100 and 250 cm3 beakers

  • Stirrer

  • Timer

  • Distilled / deionised water

Method

Experiment 1

  1. Rinse and fill the burette with potassium iodide solution

  2. Place the following in a clean, dry 250cm3 beaker:

    • 25 cm3 of sulfuric acid, using a 50 cm3 measuring cylinder

    • 20 cm3 of distilled / deionised water, using a 25 cm3 measuring cylinder

    • 1 cm3 of starch solution, using the pipette

    • 5.0 cm3 of potassium iodide solution

    • 5.0 cm3 of sodium thiosulfate solution

    • The sodium thiosulfate solution must be added last

  3. Stir the mixture in the 250 cm3 beaker

  4. Transfer 10.0 cm3 of hydrogen peroxide solution to the 250 cm3 beaker

    • Immediately start the timer

  5. Stir the mixture

  6. Stop the timer when the mixture in the 250 cm3 beaker turns blue-black

    • This experiment could take several minutes

  7. Record the time to an appropriate precision in a suitable results table

  8. Empty the 250 cm3 beaker

  9. Rinse the 250 cm3 beaker with distilled / deionised water

  10. Dry the 250 cm3 beaker

Experiments 2–5

  • Repeat steps (2) to (10) in four further experiments using the following volumes:

Experiment

0.25 mol dm–3 H2SO4 (aq)
/ cm3

Starch solution
/ cm3

Water
/ cm3

0.10 mol dm–3 KI (aq)
/ cm3

0.05 mol dm–3 Na2S2O3 (aq)
/ cm3

1

25

1

20

5.0

5.0

2

25

1

15

10.0

5.0

3

25

1

10

15.0

5.0

4

25

1

5

20.0

5.0

5

25

1

0

25.0

5.0

Diagram

Iodine clock reaction experiment, downloadable AS & A Level Chemistry revision notes

Practical Tip

  • Hydrogen peroxide is typically found in 'volume' concentrations, based on the volume of oxygen given of when it decomposes:

2H2O2 (aq)  → O2 (g) +  2H2O (l)

  • For example in school laboratories, a suitable concentration of hydrogen peroxide may be listed as 3% or '10 vol'

    • '10 vol' means that when 1 cm3 of hydrogen peroxide decomposes it generates 10 cm3 of oxygen

    • '10 vol' or 3% hydrogen peroxide has a concentration of 0.979 mol dm3

Results

  • Record your results for each test carefully in a suitable table like the one below: 

KI (aq)
/ cm3

[KI (aq)]
/ mol dm-3

Time for blue colour to appear
/ s

Rate (1 / t)
/ s-1

5.0

10.0

15.0

20.0

25.0

Evaluation

  • Calculate the concentration of KI (aq)

    • 1 dm3 of KI (aq) = 0.1 mol dm-3

    • 5 cm3 of KI (aq) = 0.1 / 200 = 0.0005 mol dm-3

    • 10 cm3 of KI (aq) = 0.1 / 100 = 0.0010 mol dm-3

  • Convert the time to rate

    • Rate = 1 / time

  • Plot a graph of the results

    • x-axis = concentration of KI (aq) / mol dm-3

    • y-axis = rate of reaction / s-1

  • Use the graph to deduce the order with respect to iodide ions

Worked Example

The iodine clock reaction between hydrogen peroxide and iodine is:

H2O2 (aq) + 2I- (aq) + 2H+(aq) → I2 (aq) + 2H2O (l)

The reaction is monitored using sodium thiosulfate solution.

Use the following results to determine the order of reaction with respect to iodide ions.

[KI (aq)]
/ mol dm-3

Time for blue colour to appear
/ s

Rate (1 / t)
/ s-1

0.015

40

0.025

0.030

20

0.050

0.045

13

0.075

0.060

10

0.100

0.075

8

0.120

Answer: 

  • Plot the rate versus concentration graph:

  • The graph shows that the rate of reaction is directly proportional to the concentration of potassium iodide

    • As concentration doubles; the rate of reaction also doubles

  • This tells us that the reaction is first order with respect to iodide ions

Part B: Measuring the rate of reaction by a continuous monitoring method

Objective

Use a continuous monitoring method to investigate the reaction of magnesium and hydrochloric acid

Apparatus

  • 6 cm strips of magnesium ribbon

  • 0.8 mol dm–3 hydrochloric acid

  • 50 cm3 measuring cylinder

  • 100 cm3 conical flask

  • Gas collection equipment:

    • Stand, boss and clamp

    • Gas syringe with bung and delivery tube
      OR
      Water trough with inverted 100 cm3 measuring cylinder, bung and delivery tube

  • Timer

  • Distilled / deionised water

Method

Experiment 1

  1. Transfer 50 cm3 of 0.8 mol dm–3 hydrochloric acid into the conical flask

  2. Set up the gas collection equipment (as shown in the diagrams below)

  3. Add one 6 cm strip of magnesium ribbon to the conical flask

  4. Immediately place the bung firmly into the top of the flask and start the timer

  5. Record the volume of hydrogen gas collected every 15 seconds for 2.5 minutes

Experiment 2

  1. Mix 25 cm3 of 0.8 mol dm–3 hydrochloric acid with 25 cm3 of distilled / deionised water

    1. This produces 50 cm3 of 0.4 mol dm–3 hydrochloric acid

  2. Transfer the 50 cm3 of 0.4 mol dm–3 hydrochloric acid into the conical flask

  3. Set up the gas collection equipment (as shown in the diagrams below)

  4. Add one 6 cm strip of magnesium ribbon to the conical flask

  5. Immediately place the bung firmly into the top of the flask and start the timer

  6. Record the volume of hydrogen gas collected every 15 seconds for 2.5 minutes

Diagram

Gas syringe method

Diagram showing how to collect gas using a gas syringe

Water trough method

Diagram showing how to collect gas using an inverted measuring cylinder

Practical Tip

  • If the magnesium does not look new and shiny, you may need to clean the surface with a bit of sandpaper

Results

  • Record your results for each test carefully in a suitable results table like the one below: 

Time (s)

Volume of gas (cm3) produced by...

0.8 mol dm–3 HCl

0.4 mol dm–3 HCl

0

15

30

45

60

75

90

105

120

135

150

Evaluation

  • Plot a graph of the results

    • x-axis = time / seconds

    • y-axis = volume of gas / cm3

  • Add one smooth curve of best fit for the 0.8 mol dm-3 results

    • Draw the tangent starting at t = 0 s

    • Calculate the gradient of the tangent to get the initial rate of reaction

  • Add one smooth curve of best fit for the 0.4 mol dm-3 results

    • Draw the tangent starting at t = 0 s

    • Calculate the gradient of the tangent to get the initial rate of reaction

Worked Example

The reaction between magnesium and hydrochloric acid was used to investigate the effect of concentration on rate of reaction.

Mg (s) + 2HCl (aq) → MgCl2 (aq) + H2 (g)

Two experiments were completed using the following concentrations of hydrochloric acid:

  • 0.5 mol dm-3

  • 1.0 mol dm-3

The results are shown in the table below.

Time (s)

Volume of gas (cm3) produced by...

0.5 mol dm–3 HCl

1.0 mol dm–3 HCl

0

0

0

10

6

3

20

11

6

30

15

9

40

19

12

50

21

14

60

22

15

Calculate the initial rate of reaction for both experiments.

Answer:

  • Plot a graph of the results

    • x-axis = time / seconds

    • y-axis = volume of gas / cm3

  • Add one smooth curve of best fit for the 0.5 mol dm-3 results

    • Draw the tangent starting at t = 0 s

    • Calculate the gradient of the tangent to get the initial rate of reaction

  • Add one smooth curve of best fit for the 1.0 mol dm-3 results

    • Draw the tangent starting at t = 0 s

    • Calculate the gradient of the tangent to get the initial rate of reaction

Sketch graph of the Mg HCl rates practical
  • Calculations:

    • 0.5 mol dm-3 results:

      • 18 cm3 of gas produced in 30 seconds

      • Rate = volume / time

      • Rate = 18 / 30 = 0.6 cm3 s-1

    • 0.5 mol dm-3 results:

      • 12 cm3 of gas produced in 40 seconds

      • Rate = volume / time

      • Rate = 12 / 40 = 0.3 cm3 s-1

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Richard Boole

Author: Richard Boole

Expertise: Chemistry

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.

Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Lead

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.