Measuring the Rate of a Reaction (Oxford AQA International A Level Chemistry)
Revision Note
Written by: Richard Boole
Reviewed by: Stewart Hird
Required Practical 7: Measuring the Rate of a Reaction
Required practical 7 is split into:
Part A: Measuring the rate of reaction by an initial rate method
Part B: Measuring the rate of reaction by a continuous monitoring method
Part A: Measuring the rate of reaction by an initial rate method
Objective
Use an 'iodine clock' experiment to investigate the reaction of iodide(V) ions with hydrogen peroxide in acidic solution and determine the order of the reaction with respect to iodide ions
Apparatus
0.25 mol dm–3 dilute sulfuric acid, H2SO4 (aq)
0.10 mol dm–3 potassium iodide solution, KI (aq)
A burette of 0.05 mol dm–3 sodium thiosulfate solution, Na2S2O3 (aq)
0.10 mol dm–3 hydrogen peroxide solution, H2O2 (aq)
Starch solution
50 cm3 burettes with funnel, stand and clamp
White tile
Pipette
Measuring cylinders
100 and 250 cm3 beakers
Stirrer
Timer
Distilled / deionised water
Method
Experiment 1
Rinse and fill the burette with potassium iodide solution
Place the following in a clean, dry 250cm3 beaker:
25 cm3 of sulfuric acid, using a 50 cm3 measuring cylinder
20 cm3 of distilled / deionised water, using a 25 cm3 measuring cylinder
1 cm3 of starch solution, using the pipette
5.0 cm3 of potassium iodide solution
5.0 cm3 of sodium thiosulfate solution
The sodium thiosulfate solution must be added last
Stir the mixture in the 250 cm3 beaker
Transfer 10.0 cm3 of hydrogen peroxide solution to the 250 cm3 beaker
Immediately start the timer
Stir the mixture
Stop the timer when the mixture in the 250 cm3 beaker turns blue-black
This experiment could take several minutes
Record the time to an appropriate precision in a suitable results table
Empty the 250 cm3 beaker
Rinse the 250 cm3 beaker with distilled / deionised water
Dry the 250 cm3 beaker
Experiments 2–5
Repeat steps (2) to (10) in four further experiments using the following volumes:
Experiment | 0.25 mol dm–3 H2SO4 (aq) | Starch solution | Water | 0.10 mol dm–3 KI (aq) | 0.05 mol dm–3 Na2S2O3 (aq) |
---|---|---|---|---|---|
1 | 25 | 1 | 20 | 5.0 | 5.0 |
2 | 25 | 1 | 15 | 10.0 | 5.0 |
3 | 25 | 1 | 10 | 15.0 | 5.0 |
4 | 25 | 1 | 5 | 20.0 | 5.0 |
5 | 25 | 1 | 0 | 25.0 | 5.0 |
Diagram
Practical Tip
Hydrogen peroxide is typically found in 'volume' concentrations, based on the volume of oxygen given of when it decomposes:
2H2O2 (aq) → O2 (g) + 2H2O (l)
For example in school laboratories, a suitable concentration of hydrogen peroxide may be listed as 3% or '10 vol'
'10 vol' means that when 1 cm3 of hydrogen peroxide decomposes it generates 10 cm3 of oxygen
'10 vol' or 3% hydrogen peroxide has a concentration of 0.979 mol dm3
Results
Record your results for each test carefully in a suitable table like the one below:
KI (aq) | [KI (aq)] | Time for blue colour to appear | Rate (1 / t) |
---|---|---|---|
5.0 | |||
10.0 | |||
15.0 | |||
20.0 | |||
25.0 |
Evaluation
Calculate the concentration of KI (aq)
1 dm3 of KI (aq) = 0.1 mol dm-3
5 cm3 of KI (aq) = 0.1 / 200 = 0.0005 mol dm-3
10 cm3 of KI (aq) = 0.1 / 100 = 0.0010 mol dm-3
Convert the time to rate
Rate = 1 / time
Plot a graph of the results
x-axis = concentration of KI (aq) / mol dm-3
y-axis = rate of reaction / s-1
Use the graph to deduce the order with respect to iodide ions
Worked Example
The iodine clock reaction between hydrogen peroxide and iodine is:
H2O2 (aq) + 2I- (aq) + 2H+(aq) → I2 (aq) + 2H2O (l)
The reaction is monitored using sodium thiosulfate solution.
Use the following results to determine the order of reaction with respect to iodide ions.
[KI (aq)] | Time for blue colour to appear | Rate (1 / t) |
---|---|---|
0.015 | 40 | 0.025 |
0.030 | 20 | 0.050 |
0.045 | 13 | 0.075 |
0.060 | 10 | 0.100 |
0.075 | 8 | 0.120 |
Answer:
Plot the rate versus concentration graph:
The graph shows that the rate of reaction is directly proportional to the concentration of potassium iodide
As concentration doubles; the rate of reaction also doubles
This tells us that the reaction is first order with respect to iodide ions
Part B: Measuring the rate of reaction by a continuous monitoring method
Objective
Use a continuous monitoring method to investigate the reaction of magnesium and hydrochloric acid
Apparatus
6 cm strips of magnesium ribbon
0.8 mol dm–3 hydrochloric acid
50 cm3 measuring cylinder
100 cm3 conical flask
Gas collection equipment:
Stand, boss and clamp
Gas syringe with bung and delivery tube
OR
Water trough with inverted 100 cm3 measuring cylinder, bung and delivery tube
Timer
Distilled / deionised water
Method
Experiment 1
Transfer 50 cm3 of 0.8 mol dm–3 hydrochloric acid into the conical flask
Set up the gas collection equipment (as shown in the diagrams below)
Add one 6 cm strip of magnesium ribbon to the conical flask
Immediately place the bung firmly into the top of the flask and start the timer
Record the volume of hydrogen gas collected every 15 seconds for 2.5 minutes
Experiment 2
Mix 25 cm3 of 0.8 mol dm–3 hydrochloric acid with 25 cm3 of distilled / deionised water
This produces 50 cm3 of 0.4 mol dm–3 hydrochloric acid
Transfer the 50 cm3 of 0.4 mol dm–3 hydrochloric acid into the conical flask
Set up the gas collection equipment (as shown in the diagrams below)
Add one 6 cm strip of magnesium ribbon to the conical flask
Immediately place the bung firmly into the top of the flask and start the timer
Record the volume of hydrogen gas collected every 15 seconds for 2.5 minutes
Diagram
Gas syringe method
Water trough method
Practical Tip
If the magnesium does not look new and shiny, you may need to clean the surface with a bit of sandpaper
Results
Record your results for each test carefully in a suitable results table like the one below:
Time (s) | Volume of gas (cm3) produced by... | |
---|---|---|
0.8 mol dm–3 HCl | 0.4 mol dm–3 HCl | |
0 | ||
15 | ||
30 | ||
45 | ||
60 | ||
75 | ||
90 | ||
105 | ||
120 | ||
135 | ||
150 |
Evaluation
Plot a graph of the results
x-axis = time / seconds
y-axis = volume of gas / cm3
Add one smooth curve of best fit for the 0.8 mol dm-3 results
Draw the tangent starting at t = 0 s
Calculate the gradient of the tangent to get the initial rate of reaction
Add one smooth curve of best fit for the 0.4 mol dm-3 results
Draw the tangent starting at t = 0 s
Calculate the gradient of the tangent to get the initial rate of reaction
Worked Example
The reaction between magnesium and hydrochloric acid was used to investigate the effect of concentration on rate of reaction.
Mg (s) + 2HCl (aq) → MgCl2 (aq) + H2 (g)
Two experiments were completed using the following concentrations of hydrochloric acid:
0.5 mol dm-3
1.0 mol dm-3
The results are shown in the table below.
Time (s) | Volume of gas (cm3) produced by... | |
---|---|---|
0.5 mol dm–3 HCl | 1.0 mol dm–3 HCl | |
0 | 0 | 0 |
10 | 6 | 3 |
20 | 11 | 6 |
30 | 15 | 9 |
40 | 19 | 12 |
50 | 21 | 14 |
60 | 22 | 15 |
Calculate the initial rate of reaction for both experiments.
Answer:
Plot a graph of the results
x-axis = time / seconds
y-axis = volume of gas / cm3
Add one smooth curve of best fit for the 0.5 mol dm-3 results
Draw the tangent starting at t = 0 s
Calculate the gradient of the tangent to get the initial rate of reaction
Add one smooth curve of best fit for the 1.0 mol dm-3 results
Draw the tangent starting at t = 0 s
Calculate the gradient of the tangent to get the initial rate of reaction
Calculations:
0.5 mol dm-3 results:
18 cm3 of gas produced in 30 seconds
Rate = volume / time
Rate = 18 / 30 = 0.6 cm3 s-1
0.5 mol dm-3 results:
12 cm3 of gas produced in 40 seconds
Rate = volume / time
Rate = 12 / 40 = 0.3 cm3 s-1
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