Calorimetry (Oxford AQA International A Level Chemistry)
Revision Note
Written by: Alexandra Brennan
Reviewed by: Stewart Hird
Calorimetry
The process of calorimetry is used to measure enthalpy changes
Measuring enthalpy changes of combustion
The apparatus below is used to find the enthalpy change when a fuel burns
The steps are:
Measure a fixed volume of water into a copper can
Weigh the spirit burner containing a fuel using a balance
Measure the initial temperature of the water
Burn the fuel and stir the water
Wait until the temperature has risen by approximately 20 oC and extinguish the flame
Record the final temperature of the water and re-weigh the spirit burner
To calculate the energy released by the fuel we can use the data obtained from the experiment above and the specific heat capacity of water
The specific heat capacity, c, is the energy needed to raise the temperature of 1 g of a substance by 1 °C
The specific heat capacity of water is 4.18 J/g/°C
The heat energy change is calculated using:
The symbols / letters are:
q = the heat energy change, J
m = the mass of the substance being heated, g
c = the specific heat capacity, J/g/°C
ΔT = the temperature change, °C
We can compare the amount of energy released per gram and per mole for different fuels
In both cases, the energy released (q) is calculated first
To calculate the energy released per gram of fuel:
energy released per gram= energy released / mass of fuel burned
To calculate the energy released per mole of fuel:
energy released per mole= energy released / number of moles
Enthalpy changes of reactions in solutions
To calculate the amount of energy produced by a chemical reaction in solution we measure the temperature change when the solutions are mixed together
The solutions need to be mixed together in an insulated container to prevent heat loss
This method can be used for:
Neutralisation reactions
Displacement reaction
Equipment Set up
Method:
A fixed volume of one reagent is added to the calorimeter and the initial temperature taken with a thermometer
An excess amount of the second reagent is added and the solution is stirred continuously
The maximum temperature is recorded and the temperature rise calculated
Again, the energy released would be calculated using:
We assume that the density of the solution is the same as pure water, i.e. 1 g/cm3
To calculate the energy released per mole, kJ mol-1:
Cooling curves
For reactions which are not instantaneous there may be a delay before the maximum temperature is reached
During that delay the substances themselves may be losing heat to the surroundings and would lead to inaccurately calculated enthalpy changes
To overcome this problem we can produce a cooling curve:
Place one reactant in the polystyrene cup
Take the temperature of the reactant every minute for approximately 4 minutes
Add the second reactant and continue recording the temperature every minute for approximately 6 minutes
Plot the graph of temperature against time
Extrapolate the cooling part of the graph until you intersect the time at which the second reactant was added
Worked Example
The energy from 0.01 mol of propanol was used to heat up 250 g of water.
The temperature of the water rose from 25 °C to 37 °C .
The specific heat capacity of water is 4.18 J/g/°C.
Calculate the enthalpy change in kJ/mol.
Answer:
Step 1: q = m x c x ΔT
m (of water) = 250 g
c (of water) = 4.18 J /g/°C
ΔT (of water) = 37 – 25 °C = 12 °C
q = 250 x 4.18 x 12 = 12 540 J
Step 2: Calculate the energy released per mole
ΔH = q ÷ n
12 540 J ÷ 0.01 mol = 1 254 000 J mol-1
– 1254 kJ mol-1
Worked Example
50 cm3 of 1.00 mol dm-3 HCl and 50 cm3 of of 1.00 mol dm-3 sodium hydroxide were mixed together in a polystyrene cup. The temperature increased by 12 K.
Calculate the enthalpy change for the reaction in kJ mol-1.
Answer:
Step 1: q= m x c x ΔT
m (of solution) = 100 g
c (of water) = 4.18 J /g/°C
ΔT (of water) = 12 K
q = 100 x 4.18 x 12 = 5016 J
Step 2: Calculate the number of moles of acid
Moles= (50/1000) x 1= 0.05 mol
Step 3: Calculate ΔH = q ÷ n
5016 J ÷ 0.05 mol = 1 00 320 J mol-1
= – 100.32 kJ mol-1
Examiner Tips and Tricks
You could be given the temperatures in K or oC, but remember the temperature change will be the same!
Last updated:
You've read 0 of your 5 free revision notes this week
Sign up now. It’s free!
Did this page help you?