Ionisation Energy (Oxford AQA International A Level Chemistry)
Revision Note
Written by: Alexandra Brennan
Reviewed by: Stewart Hird
Ionisation Energy
The Ionisation Energy (IE) of an element is:
'The amount of energy required to remove one mole of electrons from one mole of gaseous atoms of an element to form one mole of gaseous ions'
Process of Ionisation
Ionisation energies are measured under standard conditions which are 298 K and 101 kPa
The units of IE are kilojoules per mole, kJ mol-1
The values for ionisation energies are always positive as this is an endothermic process
This is because energy is required to break the force of attraction between the electron and the central positive nucleus
Successive Ionisation energies
The energy required to remove electrons one by one from an element can be measured, starting with the outer electrons
The first ionisation energy will be the energy required to remove one mole of electrons from one mole of atoms to form one mole of 1+ ions
For sodium this is represented as:
Na (g) → Na+ (g) + e-
The second ionisation energy will be the energy required to remove one mole of electrons from one mole of 1+ ions to form one mole of 2+ ions and so on
For sodium this is represented as:
Na+(g) → Na2+ (g) + e-
The equation for the third ionisation energy of sodium is:
Na2+(g) → Na3+ (g) + e-
These are known as successive ionisation energies
The amount of energy needed to remove each electron will increase as more electrons are removed
The first electron is being removed from an atom
The second electron is being removed from a 1+ ion
The third electron is being removed from a 2+ ion and so on
The ionisation energies of sodium in kJ mol-1 are shown below:
1st I.E | 2nd I.E | 3rd I.E | 4th I.E | 5th I.E | 6th I.E | 7th I.E | 8th I.E | 9th I.E | 10th I.E | 11th I.E |
---|---|---|---|---|---|---|---|---|---|---|
496 | 4563 | 6913 | 9544 | 13352 | 16611 | 20115 | 25491 | 28934 | 141367 | 159079 |
We can see a distinct set of energy levels here:
The first electron is relatively easy to remove
The next 8 electrons are hard to remove
The last two (those closest to the nucleus) are even harder to remove
The largest increase between ionisation energies indicates which group an element is located in
The largest increase is between the 1st and 2nd ionisation energy
This demonstrates sodium is in Group 1 because a much higher amount of energy is needed to remove the second electron as the energy level it is being removed from is closer to the nucleus
Worked Example
Give the equation for the second ionisation energy of magnesium.
Answer:
The equation is:
Mg+ (g) → Mg2+ (g) + e-
The second ionisation energy refers to removing one mole of electrons from one mole of positive ions so you must begin with Mg+
Trends in Ionisation energies
Trends in ionisation energies can be observed across a period and down a group in the Periodic Table
Across Period 3
The first ionisation energy generally increases for each element going across Period 3 in the Periodic Table
Graph to show ionisation energies of Period 3 elements
This is because going across Period 3:
The nuclear charge (the number of protons in the nucleus) increases
This causes the atomic radius of the atoms to decrease, as the outer shell is pulled closer to the nucleus
Therefore the distance between the nucleus and the outer electrons decreases
The shielding by inner shell electrons remains reasonably constant across the period as electrons are being added to the same shell
It becomes harder to remove an electron as you move so more energy is needed
There are two elements which do not follow the general trend:
Aluminium has a lower first I.E than magnesium
Sulfur has a lower first I.E than phosphorus
These deviations provide evidence for the presence of s- and p- orbitals
Why does aluminium have a lower first I.E than magnesium?
Magnesium has the electronic configuration 1s22s22p63s2
Magnesium loses its first electron from the 3s orbital
Aluminium has the electronic configuration 1s22s22p63s2 3p1
Aluminium loses its first electron from the 3p orbital
The 3p orbital is of slightly higher energy than the 3s orbital so less energy is needed to remove the electron, despite the increasing nuclear charge
Why does sulfur have a lower first I.E than phosphorus?
Phosphorus has the electronic configuration 1s22s22p63s2 3p3
Each 3p orbital will contain one electron
Sulfur has the electronic configuration 1s22s22p63s2 3p4
One of the 3p orbitals contains two electrons
There is repulsion between the two electrons in the 3p orbital of sulfur making it easier to remove the electron, despite the increasing nuclear charge
Down Group 2
The first ionisation energy of elements in Group 2 generally decreases going down the group
This is because, going down Group 2:
The atomic radius of the atoms increases due to an increasing number of electrons
The shielding by inner shell electrons also increases
These factors outweigh the increased nuclear charge, so it becomes easier to remove the outer electron
Examiner Tips and Tricks
Make sure you can confidently:
Write equations for ionisation energies with state symbols
Explain the general trends in ionisation energies across Period 3 and Group 2
Explain any deviations from these trends as evidence of shells and sub-shells
Last updated:
You've read 0 of your 5 free revision notes this week
Sign up now. It’s free!
Did this page help you?