pH Curves, Titrations & Indicators (Oxford AQA International A Level Chemistry)
Revision Note
Written by: Alexandra Brennan
Reviewed by: Stewart Hird
Titrations Calculations
Titration calculations are used to find the concentration of unknown solutions
They can also be used to calculate the pH after a given point during a titration
The steps in a titration are:
Measuring a known volume (usually 20 or 25 cm3) of one of the solutions with a volumetric or graduated pipette and placing it into a conical flask
The other solution is placed in the burette
A few drops of the indicator are added
The tap on the burette is carefully opened and the solution added, portion by portion, to the conical flask until the indicator just changes colour (this is the end point)
Multiple trials are carried out until concordant results are obtained
Worked Example
Calculating the concentration of an unknown solution.
In a titration, 25.00 cm3 of 0.05 mol dm-3 hydrochloric acid was neutralised by 8.50 cm3 of sodium hydroxide solution.
NaOH + HCl → NaCl + H2O
Calculate the concentration of the sodium hydroxide solution.
Answer:
Step 1: Find the number of moles of hydrochloric acid
moles of acid = concentration x volume in dm3
moles of acid = 0.05 x 0.025 = 1.25 x 10-3 mol
Step 2: Deduce the number of moles of sodium hydroxide
The equation for the reaction shows the mole ratio is 1:1
so moles of alkali = 1.25 x 10-3 mol
Step 3: Work out the concentration of the alkali
concentration = moles/volume in dm3
concentration = 1.25 x 10-3/0.0085 = 0.15 mol dm-3
Worked Example
Calculating the pH in a strong acid-strong base titration.
50.0 cm3 of 0.10 mol dm3 NaOH is gradually added to 25.0 cm3 of 0.15 mol dm3 hydrochloric acid.
NaOH + HCl → NaCl + H2O
Determine the pH after 45 cm3 of NaOH has been added.
(Kw = 1 x 10-14 mol2 dm-6 at 298 K).
Answer:
Step 1: Find the number of moles of acid
moles of acid = concentration x volume in dm3
moles of acid = 0.15 x 0.025 = 3.75 x 10-3 mol
Step 2: Deduce the number of moles of alkali added
The equation for the reaction shows the mole ratio is 1:1
moles of alkali added = 0.10 x 0.045 = 4.50 x 10-3 mol
so moles of alkali in excess = (4.50 x 10-3- 3.75 x 10-3) = 7.5 x 10-4 mol
Step 3: Work out the concentration of the alkali (using total volume of solution)
concentration = moles/volume in dm3
concentration = 7.5 x 10-4/0.070 = 0.0107 mol dm-3
Step 4: Use Kw to find the concentration of H+
Kw = [H+][OH-]
[H+] = Kw /[OH-] = 1.00 x 10-14/0.0107 = 9.35 x 10-13
Step 5: Find the pH
-log[H+] = -log(9.35 x 10-13)
pH = 12.03
pH Curves & Indicators
All pH curves show an s-shape curve
Halfway along the vertical region of the curve is called the equivalence point and is the point at which neutralisation occurs
Equivalence point → moles of alkali = moles of acid
From the curves you can:
Determine the pH of the acid by looking where the curve starts on the y-axis
Find the pH at the equivalence point
Find the volume of base at the equivalence point
Obtain the range of pH at the vertical section of the curve
Example pH titration curve
Sketching a pH titration curve
Draw axes with volume added (cm3) on the x-axis and pH on the y-axis
Draw a horizontal line running parallel to the x-axis at pH 7
Everything below this line will be in the acidic region and everything above it in the alkaline region
Determine which substance is in the conical flask
If it is a strong acid the initial pH is about 0 - 2
If it is a weak acid the initial pH is about 2-4
If it is a strong alkali the initial pH is about 13-14
If it is a weak alkali the initial pH is about 11
Determine what type of acid and alkali are used:
Strong acid + strong alkali
Strong acid + weak alkali
Weak acid + strong alkali
Weak acid + weak alkali
Draw the pH titration curve
Strong acid + strong alkali pH titration curve
Initially, there are only H+ ions present in the solution from the dissociation of the strong acid (HCl) (initial pH about 1-2)
As the volume of strong alkali (NaOH) added increases, the pH of the HCl solution slightly increases too as more and more H+ ions react with the OH- from the NaOH to form water
The change in pH is not that much until the volume added gets close to the equivalence point
The pH surges upwards very steeply
The equivalence point is the point at which all H+ ions have been neutralised
Therefore, the pH is 7 at the equivalence point
Adding more NaOH will increase the pH as now there is an excess in OH- ions (final pH about 13-14)
The pH titration curve for HCl added to a NaOH has the same shape
The initial pH and final pH are the other way around
The equivalence point is still 7
Strong acid + weak alkali pH titration curve
Initially, there are only H+ ions present in the solution from the dissociation of the strong acid (HCl) (initial pH about 1-2)
As the volume of weak alkali (NH3) added increases, the pH of the analyte solution slightly increases too as more and more H+ ions react with the NH3
The change in pH is not that much until the volume added gets close to the equivalence point
The equivalence point is the point at which all H+ ions have been neutralised by the NH3 however the equivalence point is not neutral, but the solution is still acidic (pH about 5.5)
This is because all H+ have reacted with NH3 to form NH4+ which is a relatively strong acid, causing the solution to be acidic
As more of the NH3 is added, the pH increases to above 7 but below that of a strong alkali as NH3 is a weak alkali
The pH titration curve for strong acid added to a weak alkali has the same shape
The initial and final pH are the other way around
The equivalence point is still about 5.5
Weak acid + strong alkali pH titration curve
Initially, there are only H+ ions present in the solution from the dissociation of the weak acid (CH3COOH, ethanoic acid) (initial pH about 2-3)
As the volume of strong alkali (NaOH) added increases, the pH of the ethanoic acid solution slightly increases too as more and more H+ ions react with the OH- from the NaOH to form water
The change in pH is not that much until the volume added gets close to the equivalence point
The pH surges upwards very steeply
The equivalence point is the point at which all H+ ions have been neutralised by the OH- ions however the equivalence point is not neutral, but the solution is slightly basic (pH about 9)
This is because all H+ in CH3COOH have reacted with OH- however, CH3COO- is a relatively strong base, causing the solution to be basic
As more of the NaOH is added, the pH increases to about 13-14
The pH titration curve for weak acid added to a strong alkali has the same shape
The initial and final pH are the other way around
The equivalence point is still about 9
Weak acid + weak alkali pH titration curve
Initially, there are only H+ ions present in the solution from the dissociation of the weak acid (CH3COOH, ethanoic acid) (initial pH about 2-3)
In these pH titration curves, there is no vertical region
There is a ‘point of inflexion’ at the equivalence point
The curve does not provide much other information
Examiner Tips and Tricks
You should be able to read and sketch pH titration curves of titrations where the titrant is an acid or an alkali.
Worked Example
A 10.0 cm3 sample of 0.150 mol dm–3 aminoethanoic acid with a pH of 5.3 was titrated with 0.100 mol dm–3 NaOH. After 20.0 cm3 of NaOH, an excess, had been added, the pH was found to be 12.5.
Using the following axes, sketch a graph showing how the pH changes during this titration.
Answer:
The curve starts at pH 5.3
Mark on graph
The volume of NaOH added to reach the vertical section of the graph = 15.0 cm3
Vol acid x Concentration acid = Vol base x Concentration base
10 x 0.150 = Vol base x 0.100
= 15.0 cm3
There is no mark for the height of the vertical section, but the equivalence point must be above pH 7 for a weak acid - strong base titration
The curve finishes at pH = 12.5 at 20 cm3.
Make sure the graph does not go above pH 12.5
This is the maximum pH value given in the question
Make sure that the volume does not exceed 20 cm3
This is the maximum volume of base added given in the question
Indicators
Indicators are substances that change colour when they are added to acidic or alkaline solutions
When choosing the appropriate indicator, the pH of the equivalence point is very important
The two most common indicators that are used in titrations are methyl orange and phenolphthalein
Indicator & pH range table
Indicator | pH range |
---|---|
Methyl orange | 3.1 - 4.4 |
Phenolphthalein | 8.3 - 10.0 |
Both indicators change colour over a specific pH range
Methyl orange changes from red to yellow over a pH range of 3.1 - 4.4
Phenolphthalein changes from colourless to pink over a pH range of 8.3 - 10.0
Choosing indicators for titrations
Strong acid and strong alkali
The colour change for both indicators takes place at a pH range that falls within the vertical region of the curve
Therefore, either indicator can be used
Strong acid and weak alkali
Only methyl orange will change colour at a pH close to the equivalence point and within the vertical region of the curve
Weak acid and strong alkali
Now, only phenolphthalein will change colour at a pH close to the equivalence point and within the vertical region of the curve
The pH range at which methyl orange changes colour falls below the curve
Weak acid and weak alkali
Neither indicator is useful, and a different method should be considered
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