Buffer Action (Oxford AQA International A Level Chemistry)

Revision Note

Alexandra Brennan

Written by: Alexandra Brennan

Reviewed by: Stewart Hird

Acidic & Basic Buffers

  • A buffer solution is a solution which resists changes in pH when small amounts of acids or alkalis are added

  • A buffer solution is used to keep the pH almost constant by maintaining an almost constant concentration of hydrogen and hydroxide ions in a solution

Acidic Buffers

  • Acidic buffers are made from a weak acid and a soluble salt of the acid

  • A common example is an aqueous mixture of ethanoic acid and sodium ethanoate

  • In a solution:

    • Ethanoic acid partially ionises to form a relatively low concentration of ethanoate ions

CH3COOH (aq) ⇌ H(aq) + CH3COO- (aq) 

ethanoic acid                       ethanoate

high conc                               low conc

  • Sodium ethanoate is a salt which fully ionises in solution

CH3COONa + aq → Na+ (aq) + CH3COO- (aq) 

sodium ethanoate                       ethanoate ion

low conc.                                    high conc.

  • The buffer solution there contains relatively high concentrations of CH3COOH and CH3COO-

  • In the buffer solution, the ethanoic acid is in equilibrium with hydrogen and ethanoate ions

CH3COOH (aq) ⇌ H(aq) + CH3COO- (aq) 

high conc.                               high conc.

  • When H+ ions (acid) are added:

    • The equilibrium position shifts to the left as H+ ions react with CH3COO- ions to form more CH3COOH until equilibrium is re-established

    • As there is a large reserve supply of CH3COO- the concentration of CH3COO- in solution doesn’t change much as it reacts with the added H+ ions

    • As there is a large reserve supply of CH3COOH the concentration of CH3COOH in solution doesn’t change much as CH3COOH is formed from the reaction of CH3COO- with H+

    • As a result, the pH remains reasonably constant

Equilibria - Effect of adding H+, downloadable AS & A Level Chemistry revision notes
When hydrogen ions are added to the solution the pH of the solution would decrease; However, the ethanoate ions in the buffer solution react with the hydrogen ions to prevent this and keep the pH constant
  • When OH- ions (base) are added:

    • The OH- reacts with H+ to form water

      OH- (aq) + H(aq) → H2O (l)

    • The H+ concentration decreases

    • The equilibrium position shifts to the right and more CH3COOH molecules ionise to form more H+ and CH3COO- until equilibrium is re-established

    CH3COOH (aq) → H+ (aq) + CH3COO- (aq)

    • As there is a large reserve supply of CH3COOH the concentration of CH3COOH in solution doesn’t change much when CH3COOH dissociates to form more H+ ions

    • As there is a large reserve supply of CH3COO- the concentration of CH3COO- in solution doesn’t change much

    • As a result, the pH remains reasonably constant

Diagram showing the action of a buffer when OH- are added
When hydroxide ions are added to the solution, the hydrogen ions react with them to form water; The decrease in hydrogen ions would mean that the pH would increase however the equilibrium moves to the right to replace the removed hydrogen ions and keep the pH constant

Basic Buffers

  • A basic buffer keeps the pH of a solution at above 7

  • It is made by mixing a solution of a weak base with its salt

  • An example is a mixture of aqueous ammonia, NH3 (aq), and ammonium chloride, NH4Cl (aq)

  • In a solution:

NH3 (aq) + H2O (l)rightwards harpoon over leftwards harpoon NH4+ (aq) + OH (aq)

The equilibrium lies to the left as NH3 is a weak base

NH4Cl (aq) → NH4+ (aq) + Cl (aq)

NH4Cl is a soluble salt so fully dissociates in solution

  • The mixture therefore contains high concentrations of NH3 (aq) and NH4+ (aq) which will be able to react with any H+ and OH added

Adding acid to an basic buffer

  • If H+ (acid) is added:

    • NH3 (aq) + H+ (aq)rightwards harpoon over leftwards harpoon NH4+ (aq) 

    • H+ will combine with NH3 to form NH4+ so removing any added H+

Adding base to a basic buffer

  • If OH(base) is added:

    • NH4+ (aq) + OH (aq) rightwards harpoon over leftwards harpoonNH3 (aq) + H2O (l)

    • OH will combine with the acid NH4+ and form NH3 and H2O so removing any added OH

  • Therefore there is no overall change is pH if there are small amounts of acid or base are added

Examiner Tips and Tricks

Remember: Buffer solutions cannot cope with excessive addition of acids or alkalis as their pH will change significantly. The pH will only remain relatively constant if small amounts of acids or alkalis are added

Applications of Buffers

  • In humans, HCO3- ions act as a buffer to keep the blood pH between 7.35 and 7.45

  • Body cells produce CO2 during aerobic respiration

  • This CO2 will combine with water in blood to form a solution containing H+ ions

CO2 (g) + H2O (l) ⇌ H+ (aq) + HCO3- (aq)

  • This equilibrium between CO2 and HCO3- is extremely important

  • If the concentration of H+ ions is not regulated, the blood pH would drop and cause ‘acidosis’

    • Acidosis refers to a condition in which there is too much acid in the body fluids such as blood

    • This could cause body malfunctioning and eventually lead to coma

  • If there is an increase in H+ ions

    • The equilibrium position shifts to the left until equilibrium is restored

    • This reduces the concentration of H+ and keeps the pH of the blood constant

  • If there is a decrease in H+ ions

    • The equilibrium position shifts to the right until equilibrium is restored

    • This increases the concentration of H+ and keeps the pH of the blood constant

  • Buffers are also used in every day products such as shampoos and detergents

Buffer Calculations

  • The pH of an acidic buffer solution can be calculated using:

    • The Ka of the weak acid

    • The equilibrium concentration of the weak acid and its conjugate base (salt)

  • To determine the pH, the concentration of hydrogen ions is needed which can be found using the equilibrium expression

Calculating pH of Buffer Solutions equation 1
  • To simplify the calculations, logarithms are used such that the expression becomes:

Calculating pH of Buffer Solutions equation 2
  • Since -log10 [H+] = pH, the expression can also be rewritten as:

  • This is known as the Hendersen-Hasselbalch equation

Worked Example

Calculate the pH of a buffer solution containing 0.305 mol dm-3 of ethanoic acid and 0.520 mol dm-3 sodium ethanoate.

The Ka of ethanoic acid  = 1.74 × 10-5 mol dm-3

Answer:

Ethanoic acid is a weak acid that ionises as follows:

CH3COOH (aq) ⇌ H+ (aq) + CH3COO- (aq)

Step 1: Write down the equilibrium expression to find Ka

Calculating pH of Buffer Solutions equation 4

Step 2: Rearrange the equation to find [H+]

Calculating pH of Buffer Solutions equation 5

Step 3: Substitute the values into the expression

= 1.02 x 10-5 mol dm-3

Step 4: Calculate the pH

pH = - log [H+]

= -log 1.02 x 10-5

= 4.99

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Alexandra Brennan

Author: Alexandra Brennan

Expertise: Chemistry

Alex studied Biochemistry at Newcastle University before embarking upon a career in teaching. With nearly 10 years of teaching experience, Alex has had several roles including Chemistry/Science Teacher, Head of Science and Examiner for AQA and Edexcel. Alex’s passion for creating engaging content that enables students to succeed in exams drove her to pursue a career outside of the classroom at SME.

Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Lead

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.