Mass Spectrometry (Oxford AQA International A Level (IAL) Chemistry): Revision Note
Exam code: 9622
Mass Spectrometry
- Mass spectrometry (MS) is an analytical technique used to identify unknown compounds 
- When a molecule is analysed in a mass spectrometer, the vaporised sample is ionised which creates molecular ions, MOLECULE+•: 
MOLECULE  MOLECULE+• + e–
- The peak with the highest mass to charge ratio or m/z value is the molecular ion (M+) peak 
- This gives information about the molecular mass of the compound - The m/z value of the molecular ion peak is the relative molecular mass of the compound 
 
The M+1 peak
- The [M+1] peak is a smaller peak which is due to the natural abundance of the isotope carbon-13 
- The height of the [M+1] peak for a particular ion depends on the number of atoms in the molecule - More carbon atoms = a larger [M+1] peak 
- For example, the [M+1] peak for a hexane ion will be higher / bigger than the [M+1] peak for an ethane ion 
 
Fragmentation
- The molecular ion can further fragment to form new ions, molecules, and radicals 
Fragmentation of a molecule in mass spectroscopy

- The relative abundances of the detected ions form a mass spectrum 
Mass spectrum of pent-1-ene

- The fragments in a mass spectrum are like a molecular fingerprint that can be used by a computer to identify the compound from a database 
- Fragments appear due to the formation of characteristic fragments or the loss of small molecules 
Table of common fragments and small molecules
| Fragment | m/z | Small molecule | m/z | 
|---|---|---|---|
| CH3+ | 15 | H2O | 18 | 
| C2H5+ | 29 | CO | 28 | 
| C3H7+ | 43 | CO2 | 44 | 
Worked Example
Which alcohol is not likely to have a peak at m/z = 43 in its mass spectrum?
- 2-methylpropan-1-ol, (CH3)2CHCH2OH 
- Pentan-2-ol, CH3CH(OH)CH2CH2CH3 
- Butan-1-ol, CH3CH2CH2CH2OH 
- Butan-2-ol, CH3CH2CH(OH)CH3 
Answer:
- A line at m/z = 43 corresponds to an ion with a mass of 43 for example: - [CH3CH2CH2]+ 
- [(CH3)2CH]+ 
 
- Butan-2-ol does not have either of these C3H7+ ions within its structure so it cannot produce a mass spectrum peak at m/z = 43 
Low resolution mass spectrometry
- Low resolution mass spectrometry typically reports mass to 2 decimal places - This uses more accurate values for atomic mass than are shown on the periodic table 
- For example: - Hydrogen = 1.00 
- Carbon = 12.00 
- Oxygen = 16.00 
 
 
- Low resolution mass spectrometry is suitable for general analysis or identifying simple compounds 
- However, it does not work for molecules with similar molecular masses 
High resolution mass spectrometry
- High resolution mass spectrometry typically reports mass to 4 or 5 decimal places - The values for atomic mass are far more precise than the periodic table 
- For example: - Hydrogen = 1.00783 
- Carbon = 12.0000 
- Oxygen = 15.99491 
 
 
- Therefore, a more precise molecular mass can be calculated 
- This means that it is possible to: - Determine the molecular formula of a compound 
- Distinguish between molecules with similar molecular masses 
 
- However, it does not work for isomers because they have an identical molecular mass 
Comparing low and high resolution mass spectrometry
| Molecule | Low resolution MS | High resolution MS | 
|---|---|---|
| Propane, C3H8 | (3 x 12.00) + (8 x 1.00) = 44.00 | (3 x 12.0000) + (8 x 1.00783) = 44.06264 | 
| Ethanal, CH3CHO | (2 x 12.00) + (4 x 1.00) + 16.00 = 44.00 | (2 x 12.00) + (4 x 1.00783) + 15.99491 = 44.02623 | 
Worked Example
Fluoroethyne, CHCF, and carbon dioxide, CO2, both have a relative molecular mass of 44.00.
Explain how mass spectrometry can be used to distinguish between these compounds. Show your working.
- Ar (H) = 1.00783 
- Ar (C) = 12.0000 
- Ar (O) = 15.99491 
- Ar (F) = 18.9984 
Answer:
- High resolution mass spectrometry will distinguish between the compounds because it it more accurate 
- Mr (CHCF) = (2 x 12.0000) + 1.00783 + 18.9984 = 44.00623 
- Mr (CO2) = 12.00 + (2 x 15.99491) = 43.98982 
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