Elimination Reactions of Halogenoalkanes (Oxford AQA International A Level Chemistry): Revision Note
Elimination Mechanism
In an elimination reaction, an organic molecule loses a small molecule
In the case of halogenoalkanes this small molecule is a hydrogen halide (e.g. HCl)
The halogenoalkanes are heated with ethanolic sodium hydroxide (no water present) causing the C-X bond to break heterolytically, forming an X- ion and leaving an alkene as an organic product
Under these conditions the OH- ion can act as a base removing an H+ ion from the halogenoalkane
Elimination of a halogenoalkane
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Elimination with OH-
There are three curly arrows in this mechanism
Curly arrow from lone pair on :OH- ion to H atom bonded to the adjacent carbon atom
Curly arrow from the C–H bond adjacent to the appropriate C–C bond
Curly arrow from C-X bond to Br (X) atom
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Which product will form?
Note that the reaction conditions should be stated correctly as different reaction conditions will result in different types of organic reactions
Mechanism favoured | Conditions | Product |
---|---|---|
Nucleophilic substitution | NaOH in water Room temperature Favoured by primary halogenoalkanes | Alcohol |
Elimination | NaOH in ethanol (no water present) High temperature Favoured by tertiary halogenoalkanes | Alkene |
Isomeric alkenes
It is possible for elimination of halogenoalkanes to produce a mixture of alkenes which can also exhibit E / Z isomerism
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Examiner Tips and Tricks
To help visualise the elimination mechanism you can think of a stair case as the shape is very similar. Double check you have drawn first curly arrow to the correct hydrogen atom.
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