Preparation (Oxford AQA International A Level Chemistry)
Revision Note
Written by: Philippa Platt
Reviewed by: Stewart Hird
Aliphatic Amines
Amines can be thought of as derivatives of ammonia, in which one or more of the hydrogens is replaced by an alkyl or aryl group
The number of substituted hydrogens is the basis of classifying amines
Primary amines
Secondary amines
Tertiary amines
Amines can be classified as primary, secondary and tertiary
Preparing Amines
Primary amines can be prepared from different reactions including:
The reaction of halogenoalkanes with ammonia
The reduction of nitriles
Reaction of halogenoalkanes with ammonia
This is a nucleophilic substitution reaction in which the nitrogen lone pair in ammonia acts as a nucleophile and replaces the halogen in the halogenoalkane
When a halogenoalkane is reacted with excess, hot ethanolic ammonia under pressure a primary amine is formed
Reduction of nitriles
Nitriles contain a -CN functional group which can be reduced to an -NH2 group
The nitrile vapour and hydrogen gas are passed over a nickel catalyst or LiAlH4 in dry ether can be used to form a primary amine
Reaction of halogenoalkanes with primary amine
This is also a nucleophilic substitution reaction in which the nitrogen in the primary amine acts as a nucleophile and replaces the halogen in the halogenoalkane
When a halogenoalkane is reacted with a primary amine in ethanol and heated in a sealed tube, under pressure a secondary amine is formed
Tertiary amines can also be formed by further reaction of the secondary amine
In this example, further substitution would form triethylamine (CH3CH2)N
Aromatic Amines
Phenylamine is an organic compound consisting of a benzene ring and an amine (NH2) functional group
Phenylamine is the starting point for making many other chemicals including dyes
It is made in industry using benzene produced from crude oil
Nitrobenzene, C6H5NO2, can be reduced to phenylamine, C6H5NH2 in two steps
Preparation of phenylamine
Stage 1 - Reduction of nitrobenzene
Nitrobenzene, C6H5NO2, is reacted with tin, Sn, and concentrated hydrochloric acid, HCl
Tin and hydrochloric acid act as reducing agents
The reaction mixture is heated under reflux in a boiling water bath
The phenylammonium ions, C6H5NH3+, are protonated due to the acidic conditions
Stage 2 - Formation of phenylamine
The phenylammonium ions, C6H5NH3+, are deprotonated by the addition of excess sodium hydroxide solution, NaOH (aq)
Last updated:
You've read 0 of your 10 free revision notes
Unlock more, it's free!
Did this page help you?