Nucleophilic Addition–Elimination (Oxford AQA International A Level Chemistry)
Revision Note
Written by: Philippa Platt
Reviewed by: Stewart Hird
Nucleophilic Addition–Elimination Mechanism
Amines undergo nucleophilic addition-elimination reactions with acyl chlorides and acid anhydrides
The delta positive carbon atom is the site of the nucleophilic attack by the lone pair on the nitrogen in ammonia or the amine
Chlorine is more electronegative than oxygen, so creates a stronger dipole along the C-Cl bond making the carbon more susceptible to attack from nucleophiles
This is why acyl chlorides are more reactive than acid anhydrides
The reaction produces HCl as an elimination product (hence the name addition-elimination), but since both ammonia and amines are basic the HCl reacts to form ammonium chloride or the amine salt respectively
Hence, two moles of ammonia /amine are needed in the overall equation:
RCOCl + 2NH3 → RCONH2 + NH4Cl
and
RCOCl + 2R’NH2 → RCONHR’ + R’NH3Cl
Formation of amides: reaction mechanism
Step 1 - addition
The lone pair on the nitrogen atoms carry out an initial attack on the carbonyl carbon
A pair of electrons from the C=O bond moves to the O atom forming a negatively charged oxygen
Step 2 - elimination
A lone pair of electrons on negatively charged O reforms the C=O
The Cl group leaves
The H atom leaves and restores the electron density on the N atom
Both reactions of acyl chlorides with ammonia and amines are vigorous however there are also differences
With ammonia - The product is a non-substituted amide and white fumes of NH4Cl are formed
With amines - The product is a substituted amide and the HCl formed reacts with the unreacted amine to form a white organic ammonium salt
Nucleophilic addition-elimination mechanism
Primary amines and acyl chloride reaction mechansim
Examiner Tips and Tricks
If you want to name substituted amines or amides you can use the prefix letter N, to show that the alkyl (or other group) is attached to the nitrogen, so in the last example calling it N-methylpropanmide avoids any ambiguity about the location of the methyl group.
Last updated:
You've read 0 of your 10 free revision notes
Unlock more, it's free!
Did this page help you?