What is the electronic configuration of a chromium atom?
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What is the electronic configuration of a chromium atom?
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A ligand must be an
electron-pair donor
electron-pair donor and negatively charged
electron-pair acceptor
electron-pair acceptor and negatively charged
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Nickel is classified as a transition metal. This is because nickel
is a d block element
has partially filled d orbitals
forms stable ions with partially filled d orbitals
forms stable compounds in which it has different oxidation states
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Cobalt chloride is used as a test for the presence of water.
This test depends on the fact that
anhydrous cobalt(II) chloride is blue and hydrated cobalt(II) chloride is pink
anhydrous cobalt(II) chloride is pink and hydrated cobalt(II) chloride is blue
cobalt(II) chloride is blue and cobalt(III) chloride is pink
cobalt(II) chloride is pink and cobalt(III) chloride is blue
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This question is about transition metal complexes.
covalent, dative covalent and ionic
covalent and dative covalent only
covalent only
dative covalent only
[Pt(NH3)2Cl2]
[Cu(H2O)4(OH)2]
[Cu(NH3)4(H2O)2]2+
[CoCl4]2−
[Co(NH2CH2CH2NHCH2CH2NH2)2]3+
[Cu(NH3)4(H2O)2]2+
[Ni(NH2CH2CH2NH2)3]2+
[Mn(EDTA)]2−
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In which of the following pairs does the metal have different oxidation numbers?
V2O5 and
and VO2+
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Which of the following statements best explains carbon monoxide poisoning?
carbon monoxide binds irreversibly to haemoglobin
carbon monoxide forms stronger dative covalent bonds with haemoglobin than oxygen does
the formation of carboxyhaemoglobin leads to a large increase in the entropy of the system
carbon monoxide has a triple bond whereas oxygen has a double bond
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Diamminecopper(I) ions are not coloured because
the d orbitals in copper(I) cannot be split
the energy difference between the split d orbitals is outside the visible region of the spectrum
d—d transitions are not possible because the d orbitals are fully occupied
copper(I) complexes are readily oxidised
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Which of these has the greatest number of unpaired electrons in each of its atoms?
chromium
iron
manganese
vanadium
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Copper(II) ions form a complex with 1,2-diaminoethane (symbol ‘en’) with the formula Cu(en)3 2+.
What type of ligand is 1,2-diaminoethane, and what is the coordination number of copper(II) in the complex?
Type of ligand | Coordination number | ||
□ | A | bidentate | 3 |
□ | B | bidentate | 6 |
□ | C | tridentate | 3 |
□ | D | tridentate | 6 |
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Some nickel(II) complex ions are formed by the addition of complexing agents to nickel(II) ions, [Ni(H2O)6]2+, in aqueous solution.
On formation, which of these leads to the most positive increase in ΔSsystem?
[NiCl4]2–
[Ni(EDTA)]2–
[Ni(C2O4)2 ]2–
[Ni(H2NCH2CH2NH2)3]2+
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Platinum forms a complex with the formula Pt(NH3)2Cl2 and chromium forms a complex with the formula CrCl4–.
both complexes are square planar
both complexes are tetrahedral
Pt(NH3)2Cl2 is tetrahedral and CrCl4– is square planar
Pt(NH3)2Cl2 is square planar and CrCl4– is tetrahedral
the bonding in both complexes is ionic
the bonding in both complexes is dative covalent
the bonding in Pt(NH3)2Cl2 is dative covalent and in CrCl4– is ionic
the bonding in Pt(NH3)2Cl2 is ionic and in CrCl4– is dative covalent
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