High Resolution Mass Spectrometry (Edexcel International A Level Chemistry): Revision Note
High Resolution Mass Spectrometry
At AS level, you have used mass spectrometry to determine:
Relative atomic mass from isotopic abundance
Possible molecular formulae from molecular ion peaks
Organic structures from fragmentation patterns
High resolution mass spectrometry can be used to deduce / confirm molecular formulae
High resolution mass spectrometers provide data accurate to four, or sometimes more, decimal places
This means that a compounds molecular formula can sometimes be deduced by using atomic masses accurate to four decimal places
Table of selected accurate relative atomic masses
Element | Hydrogen | Carbon | Nitrogen | Oxygen |
---|---|---|---|---|
Symbol | H | C | N | O |
Accurate Ar | 1.0078 | 12.0000 | 14.0031 | 15.9949 |
Worked Example
A compound is found to have an Mr value of 58.0417.
Determine if the compound is:
C4H10
C2H6N2
C3H6O
Answer
Element | Hydrogen | Carbon | Nitrogen | Oxygen |
---|---|---|---|---|
Symbol | H | C | N | O |
Accurate Ar | 1.0078 | 12.0000 | 14.0031 | 15.9949 |
C4H10 = (4 x 12.0000) + (10 x 1.0078) = 58.0780
C2H6N2 = (2 x 12.0000) + (6 x 1.0078) + (2 x 14.0031) = 58.0530
C3H6O =(3 x 12.0000) + (6 x 1.0078) + (15.9949) = 58.0417
Therefore, the correct formula of the compound is C3H6O
Examiner Tips and Tricks
High resolution mass spectrometry can inform you about the molecular formula, it cannot tell you about the actual structure
In the worked example above, the final answer was C3H6O but you cannot say whether this is propanal or propanone
You would have to use the fragments on the mass spectrum for further detail that might help deduce more information about the structure
Sometimes you may calculate the molecular mass of a compound and it won't match the value given in the question exactly
In this case, you should:
Firstly, double check your calculation(s)
Secondly, choose the compound that is the closest
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