Buffer Calculations (Edexcel International A Level Chemistry): Revision Note
Buffer Calculations
The pH of a buffer solution can be calculated using:
The Ka of the weak acid
The equilibrium concentration of the weak acid and its conjugate base (salt)
To determine the pH, the concentration of hydrogen ions is needed which can be found using the equilibrium expression
To simplify the calculations, logarithms are used such that the expression becomes:
Since -log10 [H+] = pH, the expression can also be rewritten as:
This is known as the Hendersen-Hasselbalch equation
Worked Example
Calculate the pH of a buffer solution containing 0.305 mol dm-3 of ethanoic acid and 0.520 mol dm-3 sodium ethanoate.
The Ka of ethanoic acid = 1.74 × 10-5 mol dm-3 at 298 K
Answer
Ethanoic acid is a weak acid that ionises as follows:
CH3COOH (aq) ⇌ H+ (aq) + CH3COO- (aq)
Step 1: Write down the equilibrium expression to find Ka
Step 2: Rearrange the equation to find [H+]
Step 3: Substitute the values into the expression
= 1.02 x 10-5 mol dm-3
Step 4: Calculate the pH
pH = - log [H+]
= -log 1.02 x 10-5
= 4.99
How to make a buffer solution with a required pH
To make a buffer solution with a pH of less than 7, you need to use a mixture of a weak acid and its conjugate base
Conversely, you can make a buffer solution with a pH greater than 7 by using a mixture of a weak base and its conjugate acid
Imagine we want to make a buffer solution with a pH of 5.00 at a temperature of 298K
This would require a hydrogen ion concentration of:
[H+(aq)] = 1.00 x 10-5 mol dm-3
The hydrogen ion concentration of a buffer solution of a weak acid and its conjugate base is calculated using the formula:
[H+ (aq)] = Ka x
We will use ethanoic acid as our weak acid of choice, with a Ka value of 1.74 x 10-5 mol dm-3
Substituting our known values into the equation we get:
1.00 x 10-5 = 1.74 x 10-5 x
This gives a value for the ratio of the concentrations of acid and base needed in our buffer solution:
= 0.575
Mixing an equal volume of ethanoic acid with a concentration of 0.575 mol dm-3 and a sodium ethanoate solution of 1.00 mol dm-3 would allow us to make this buffer solution
This would give a solution with an acid concentration of 0.2875 mol dm-3 and a salt concentration of 0.500 mol dm-3
= 0.575
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