Equilibrium Constant & Entropy (Edexcel International A Level Chemistry): Revision Note
Equilibrium Constant & Entropy
The equation for calculating the total entropy change is:
ΔSꝋtotal = ΔS ꝋsys + ΔSꝋsurr
(sys = system and surr = surroundings)
Remember that ΔSꝋtotal is positive for all spontaneous changes
There is very little change in ΔSꝋsys with a change in temperature unless there is a change in the state of one of the reactants or products
There will be a significant change in ΔSꝋsurr however
The entropy change of the surroundings during a chemical reaction is
Where ΔH is the enthalpy change and T is the absolute temperature (measured in kelvin)
We can use this information to determine whether a reaction is spontaneous at a given temperature
Worked Example
Is the decomposition of calcium carbonate into calcium oxide and carbon dioxide spontaneous at the given temperatures?
CaCO3(s) → CaO(s) + CO2(g) ΔH = +177.9 kJ mol-1 ΔSsys = +160.4 J K-1 mol-1
293K (20 °C)
1173K (900 °C)
Answer 1: at 293 K (20°C)
ΔSsurroundings = = -607.2 J K-1 mol-1
ΔStotal(293K) = (+160.4 - 607.2) = -446.8 J K-1 mol-1
The decomposition of calcium carbonate is not spontaneous at 293K
Answer 2: at 1173K (900°C)
ΔSsurroundings = = -151.7 J K-1 mol-1
ΔStotal(1173) = (+160.4 - 151.7) = +8.7 J K-1 mol-1
The decomposition of calcium carbonate is spontaneous when heated to 1173K
Relationship between entropy change and equilibrium constant
For a reversible reaction that can reach equilibrium, the equilibrium position can be reached from either side of the reaction
This means that both the forward and backward reactions are spontaneous
ΔS must be positive in both directions
For example, consider the following reaction:
N2O4 (g) ⇌ 2NO2 (g)
A graph of entropy against the percentage of NO2 in a mixture of N2O4 and NO2
The entropy of N2O4 is less than the entropy of the equilibrium mixture
The change in entropy from pure N2O4 to the equilibrium mixture is positive
The change is spontaneous
The entropy change for NO2 to the equilibrium mixture is also positive
This change is also spontaneous
The entropy change for a mixture of the gases in any proportions moving towards the equilibrium position is also positive
Neither the forward nor backward reaction can go to completion as the entropy change from the equilibrium mixture to either the reactants or products is negative
At equilibrium, the total entropy change is zero
ΔStotal [forward reaction] = ΔStotal [backward reaction]
The relationship between the total entropy of the reaction and the equilibrium constant (Kc or Kp) is
ΔStotal = R lnK
Using total entropy change to calculate an equilibrium constant
Rearranging the equation mentioned above we get:
lnK =
Hence:
K =
Relationship between equilibrium constant and equilibrium position
There is no hard rule for the relationship between equilibrium constant and the position of equilibrium
As a general rule, we can say a very large value of K suggests the equilibrium position is pushed towards the products (right-hand side)
Similarly, a very small value of K suggests the equilibrium position is pushed towards the reactants (left-hand side)
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