Resistors in Series (Edexcel IGCSE Science (Double Award))

Revision Note

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Resistors in series

  • When two or more resistors are connected in series, the total resistance is equal to the sum of their individual resistances

  • For two resistors of resistance R1 and R2, the total resistance can be calculated using the equation:

R space equals space R subscript 1 space plus space R subscript 2

  • Where:

    • R is the total resistance, in ohms (Ω)

  • Increasing the number of resistors increases the overall resistance

    • The charge now has more resistors to pass through

  • The total voltage is also the sum of the voltages across each of the individual resistors

combined-resistance, IGCSE & GCSE Physics revision notes

Three resistors connected in series. The total voltage is the sum of the individual voltages, and the total resistance is the sum of the three individual resistances

Summary of series and parallel circuits

  • For components connected in series:

    • the current is the same at all points and in each component

    • the voltage of the power supply is shared between the components

    • the total resistance is the sum of the resistances of each component

  • For components connected in parallel:

    • the current from the supply splits in the branches

    • the voltage across each branch is the same

    • the total resistance is less than that of each component

Worked Example

The combined resistance R in the following series circuit is 60 Ω.

What is the resistance value of R2?

A     100 Ω               B     30 Ω               C     20 Ω               D     40 Ω

ANSWER:  C

Step 1: Write down the equation for the combined resistance in series

R space equals space R subscript 1 space plus space R subscript 2 space plus space R subscript 3

Step 2: Substitute the values for total resistance R and the other resistors

60 Ω = 30 Ω + R2 + 10 Ω

Step 3: Rearrange for R2

R2 = 60 Ω – 30 Ω – 10 Ω = 20 Ω

Worked Example

Dennis sets up a series circuit as shown below.

WE Series Circuit Question image, downloadable IGCSE & GCSE Physics revision notes

The cell supplies a current of 2 A to the circuit, and the fixed resistor has a resistance of 4 Ω.

(a) How much current flows through the fixed resistor?

(b) What is the reading on the voltmeter?

Answer:

Part (a)

Step 1: Recall that current is conserved in a series circuit

  • Since current is conserved in a series circuit, it is the same size if measured anywhere in the series loop

  • This means that since the cell supplies 2 A to the circuit, the current is 2 A everywhere

  • Therefore, 2 A flows through the fixed resistor

Part (b)

Step 1: List the known quantities

  • Current, I = 2 A

  • Resistance, R = 4 Ω

Step 2: State the equation linking potential difference, resistance and current

  • The equation linking potential difference, resistance and current is:

V space equals space I space cross times space R

Step 3: Substitute the known values into the equation and calculate the potential difference

V = 2 × 4 = 8 V

  • Therefore, the voltmeter reads 8 V across the fixed resistor

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Ashika

Author: Ashika

Expertise: Physics Project Lead

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.