Acceleration (Oxford AQA IGCSE Combined Science Double Award)

Revision Note

Acceleration

What is acceleration?

  • Acceleration is defined as the rate of change of velocity

  • In other words, it describes how much an object's velocity changes every second

  • Acceleration is a vector quantity, it has both magnitude and direction

  • Any change in velocity is acceleration

  • This includes:

    • Speeding up

    • Slowing down

    • Changing direction

  • As it is a vector quantity, the sign of acceleration tells us its direction, depending on which direction is defined as positive

    • If an object is speeding up (accelerating), its acceleration has the same sign as its velocity

    • If an object is slowing down (decelerating), its acceleration has the opposite sign to its velocity

Acceleration & Deceleration

An accelerating rocket and a decelerating car, for IGCSE & GCSE Physics revision notes
A rocket speeding up (accelerating) and a car slowing down (decelerating)

Calculating average acceleration

  • Average acceleration can be calculated using:

a space equals space fraction numerator increment v over denominator t end fraction

  • Where:

    • a = average acceleration measured in metres per second squared (m/s2)

    • Δv = change in velocity measured in metres per second

    • t = time measured in seconds (s)

  • Change in velocity can be found using:

increment v space equals space v subscript f space minus space v subscript i

  • Where:

    • Δv = change in velocity

    • vf = final velocity

    • vi = initial velocity

Worked Example

A Japanese bullet train decelerates at a constant rate in a straight line. The velocity of the train decreases from 50 m/s to 42 m/s in 30 seconds.

(a) Calculate the change in velocity of the train.

(b) Calculate the deceleration of the train, and explain how your answer shows the train is slowing down.

Answer:

Part (a)

Step 1: List the known quantities

  • Initial velocity, vi = 50 m / s

  • Final velocity, vf = 42 m / s

Step 2: Write the relevant equation

increment v space equals space v subscript f space minus space v subscript i

Step 3: Substitute values for final and initial velocity

increment v space equals space 42 space minus space 50

increment v space equals space minus 8 space straight m divided by straight s

Part (b)

Step 1: List the known quantities

  • Change in velocity, Δv = − 8 m/s

  • Time taken, t = 30 s

Step 2: Write the relevant equation

 a space equals space fraction numerator increment v over denominator t end fraction

Step 3: Substitute the values for change in velocity and time

a space equals space fraction numerator negative 8 over denominator 30 end fraction

a space equals space minus 0.27 space straight m divided by straight s squared

Step 4: Interpret the value for deceleration

  • The answer is negative, which indicates the train is slowing down

Examiner Tip

Remember the units for acceleration are metres per second squared, m/s2. In other words, acceleration measures how much the velocity (in m / s) changes every second, m/s/s.

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