Decay Equations (Edexcel IGCSE Physics (Modular))

Revision Note

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Ashika

Written by: Ashika

Reviewed by: Caroline Carroll

Alpha, beta, gamma & neutron emission

Alpha decay

  • During alpha decay, an alpha particle is emitted from an unstable nucleus

  • A completely new element is formed in the process

Alpha decay diagram, downloadable AS & A Level Physics revision notes

Alpha decay usually happens in large unstable nuclei, causing the overall mass and charge of the nucleus to decrease

  • An alpha particle is a helium nucleus

    • It is made of 2 protons and 2 neutrons

  • When the alpha particle is emitted from the unstable nucleus, the mass number and atomic number of the nucleus changes

    • The mass number decreases by 4

    • The atomic number decreases by 2

  • Alpha decay can be represented by the following nuclear equation:

straight X presubscript straight Z presuperscript straight A space rightwards arrow space straight Y presubscript straight Z minus 2 end presubscript presuperscript straight A minus 4 end presuperscript space plus thin space straight alpha presubscript 2 presuperscript 4

  • Where:

    • straight X presubscript straight Z presuperscript straight A is the initial element X with mass number A and atomic number Z

    • Y presubscript Z minus sign 2 end presubscript presuperscript A minus sign 4 end presuperscript is the new element Y

    • straight alpha presubscript 2 presuperscript 4 is an alpha particle

Beta decay

  • During beta decay, a neutron changes into a proton and an electron

    • The electron is emitted and the proton remains in the nuclei

  • A completely new element is formed because the atomic number changes

Beta minus decay GCSE, downloadable IGCSE & GCSE Physics revision notes

Beta decay often happens in unstable nuclei that have too many neutrons. The mass number stays the same, but the atomic number increases by one

  • A beta particle is a high-speed electron

  • It has a mass number of 0

    • This is because the electron has a negligible mass, compared to neutrons and protons

  • Therefore, the mass number of the decaying nuclei remains the same

  • Electrons have an atomic number of -1

    • This means that the atomic number of the new nucleus will increase by 1 to balance the overall atomic number before and after the decay

  • Beta decay can be represented by the following nuclear equation:

straight X presubscript straight Z presuperscript straight A space rightwards arrow space straight Y presubscript straight Z plus 1 end presubscript presuperscript straight A space plus thin space straight beta presubscript negative 1 end presubscript presuperscript 0

  • Where:

    • straight X presubscript straight Z presuperscript straight A is the initial element X with mass number A and atomic number Z

    • Y presubscript Z plus 1 end presubscript presuperscript A is the new element Y 

    • straight beta presubscript negative 1 end presubscript presuperscript 0 is a beta particle

Gamma decay

  • During gamma decay, a gamma ray is emitted from an unstable nucleus

  • The process that makes the nucleus less energetic but does not change its structure

Gamma decay, downloadable IGCSE & GCSE Physics revision notes

Gamma decay does not affect the mass number or the atomic number of the radioactive nucleus, but it does reduce the energy of the nucleus

  • The gamma ray that is emitted has a lot of energy, but no mass or charge

  • Gamma decay can be represented by the following nuclear equation:

straight X presubscript straight Z presuperscript straight A space rightwards arrow space straight X presubscript straight Z presuperscript straight A space plus thin space straight gamma presubscript 0 presuperscript 0

  • Where:

    • straight X presubscript straight Z presuperscript straight A is the element X with mass number A and atomic number Z

    • straight gamma presubscript 0 presuperscript 0 is a gamma ray

  • Notice that the mass number and atomic number of the unstable nucleus remains the same during the decay

Neutron emission

  • A small number of isotopes can decay by emitting neutrons

  • When a nucleus emits a neutron:

    • The atomic number (number of protons) does not change

    • The mass number (total number of nucleons) decreases by 1

  • Neutron emission can be represented by the following nuclear equation:

straight X presubscript straight Z presuperscript straight A space rightwards arrow space straight X presubscript straight Z presuperscript straight A minus 1 end presuperscript space plus thin space straight n presubscript 0 presuperscript 1

  • Where:

    • straight X presubscript straight Z presuperscript straight A is the element X with mass number A and atomic number Z

    • straight n presubscript 0 presuperscript 1 is a neutron

  • Notice that the atomic number remains the same during the decay but the mass number has changed

    • This means an isotope of the original element has formed

Examiner Tips and Tricks

It is easy to forget that an alpha particle is a helium nucleus. The two are interchangeable, so don’t be surprised to see either used in the exam.

You are not expected to know the names of the elements produced during radioactive decays, but you do need to be able to calculate the mass and atomic numbers by making sure they are balanced on either side of the reaction.

Decay equations

  • Radioactive decay events can be shown using nuclear decay equations

  • A decay equation is similar to a chemical reaction equation as

    • the particles present before the decay are shown before the arrow

    • the particles produced in the decay are shown after the arrow

  • In a decay equation:

    • the sum of the mass numbers before and after the reaction must be the same

    • the sum of the atomic numbers before and after the reaction must be the same

  • The following decay equation shows polonium-212 undergoing alpha decay

Po presubscript 84 presuperscript 212 space rightwards arrow space Pb presubscript 82 presuperscript 208 space plus space straight alpha presubscript 2 presuperscript 4

  • When a nucleus of polonium-212 decays, a nucleus of lead-208 forms and an alpha particle is emitted

  • To check if the equation is balanced:

    • mass number:  212 = 208 + 4 

    • atomic number:  84 = 82 + 2

  • The sum of the numbers are the same on each side, so the equation is balanced

Worked Example

A nucleus with 84 protons and 126 neutrons undergoes alpha decay. It forms lead, which has the element symbol Pb.

A.   Pb presubscript 82 presuperscript 206

B.   Pb presubscript 82 presuperscript 208

C.   Pb presubscript 84 presuperscript 210

D.   Pb presubscript 86 presuperscript 214

Which of the isotopes of lead pictured is the correct one formed during the decay?

ANSWER:   A

Step 1: Calculate the mass number of the original nucleus

  • The mass number is equal to the number of protons plus the number of neutrons

  • The original nucleus has 84 protons and 126 neutrons

84 + 126 = 210

  • The mass number of the original nucleus is 210

Step 2: Calculate the new atomic number

  • The alpha particle emitted is made of two protons and two neutrons

  • Protons have an atomic number of 1, and neutrons have an atomic number of 0

  • Removing two protons and two neutrons will reduce the atomic number by 2

84 – 2 = 82

  • The new nucleus has an atomic number of 82

Step 3: Calculate the new mass number

  • Protons and neutrons both have a mass number of 1

  • Removing two protons and two neutrons will reduce the mass number by 4

210 – 4 = 206

  • The new nucleus has a mass number of 206

Worked Example

A nucleus with 11 protons and 13 neutrons undergoes beta decay. It forms magnesium, which has the element symbol Mg.

A.   Mg presubscript 9 presuperscript 20

B.   Mg presubscript 10 presuperscript 24

C.   Mg presubscript 11 presuperscript 23

D.   Mg presubscript 12 presuperscript 24

Which is the correct isotope of magnesium formed during the decay?

ANSWER:  D

Step 1: Calculate the mass number of the original nucleus

  • The mass number is equal to the number of protons plus the number of neutrons

  • The original nucleus has 11 protons and 13 neutrons

11 + 13 = 24

  • The mass number of the original nucleus is 24

Step 2: Calculate the new atomic number

  • During beta decay a neutron changes into a proton and an electron

  • The electron is emitted as a beta particle

  • The neutron has an atomic number of 0 and the proton has an atomic number of 1

  • So the atomic number increases by 1

11 + 1 = 12

  • The new nucleus has an atomic number of 12

Step 3: Calculate the new mass number

  • Protons and neutrons both have a mass number of 1

  • Changing a neutron to a proton will not affect the mass number

  • The new nucleus has a mass number of 24 (the same as before)

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Ashika

Author: Ashika

Expertise: Physics Project Lead

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Caroline Carroll

Author: Caroline Carroll

Expertise: Physics Subject Lead

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.