Potential Difference in Circuits (CIE IGCSE Physics: Co-ordinated Sciences (Double Award))

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Potential difference in series circuits

Extended Tier Only

  • In a series circuit, the sum of potential differences across the components is equal to the total e.m.f. (electromotive force) of the power supply

Potential difference in a series circuit

Voltage in series, IGCSE & GCSE Physics revision notes

In a series circuit the components share the e.m.f. of the power supply

 

Worked example

In the circuit diagram below, the power source has an e.m.f., E, of 16 V. There is a potential difference of 10 V across component X. Calculate the potential difference across component Y. 

9-3-2b-h-resistors-x-and-y-in-series

Answer:

Step 1: Recall the rule for potential difference in series

  • The sum of potential differences across components in series is equal to the e.m.f. across the power source

Step 2: Write an equation to determine the potential difference across Y

EVX VY

  • Where:
    • E is the e.m.f. of the power source = 16 V
    • Vis the potential difference across X = 10 V
    • VY is the potential difference across Y
  • Recall that:
    • E = 16 V
    • VX = 10 V

Step 3: Substitute in the known quantities and calculate VY

16 = 10 + VY

  • Therefore, the potential difference across Y is 6 V

Potential difference in a parallel circuit

Extended Tier Only

  • The potential difference across each branch of a parallel circuit is the same as the e.m.f. of the power source

Potential difference in a parallel circuit

Parallel Circuit Example

The power source has an e.m.f .of 12 V and there is a potential difference of 12 V across each branch

  • It is important to notice that the potential difference in a parallel circuit is equal across each branch
    • In the example above, if one branch in the circuit contained multiple components, the 12 V would be split between the components on that branch

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Deva

Author: Deva