Speed-Time Graphs (CIE IGCSE Physics: Co-ordinated Sciences (Double Award))

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Leander

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Speed-time graphs

  • A speed-time graph is used to describe the speed of an object and calculate its acceleration

Constant acceleration on a speed-time graph

  • If an object is moving at a constant acceleration, the speed-time graph will be a straight line
    • If the constant acceleration is zero, the line will be horizontal
    • If the constant speed is non-zero, the line will have a gradient

  • If an object has an acceleration of zero, the object is travelling at a constant velocity
    • Its velocity is not changing over time
    • If the constant speed is zero, then the object is stationary

Motion on a speed-time graph

1-2-4-speed-time-graph-2-cie-igcse-23-rn

This image shows how to interpret the slope of a speed-time graph

 

  • The gradient of a speed-time graph represents the object's acceleration
    • A steeper slope, or a higher gradient, represents a greater acceleration
    • A shallower slope, or a lower gradient, represents a slower acceleration

  • If the gradient is positive, the line slopes upward
    • A positive gradient represents an increasing speed, or acceleration

  • If the gradient is negative, the line slopes downward
    • A negative gradient represents a decreasing speed, or deceleration

Speeding up and slowing down on a speed-time graph

1-2-4-speed-time-graph-cie-igcse-23-rn

Both of these objects are moving at a constant acceleration, because the lines are straight. The positive gradient represents an increasing speed or positive acceleration. The negative gradient represents a decreasing speed or negative acceleration.

Examiner Tip

For CIE IGCSE Physics, you may be asked plot a graph of your own, or to interpret information given to you in a graph. You can read more about graph skills in the article Graph skills in GCSE Physics

Calculating distance from speed-time graphs

  • Speed-time graphs can also be used to determine the distance travelled by an object

The area under a speed-time graph

  • The area under a speed-time graph represents the distance travelled

area-under-speed-time-graph

The area under a speed-time graph represents the distance travelled

 

  • If the area of a section of the speed-time graph forms a triangle, the area can be calculated using:

 A subscript T space equals space 1 half b h

  • If the area of a section of the speed-time graph forms a rectangle, the area can be determined using:

 A subscript R space equals space b h

  • Where:
    • A subscript T = area of a triangle
    • A subscript R = area of a rectangle
    • b = base
    • h = height

  • The total distance travelled can be determined by finding the total area under the speed-time graph
  • The distance travelled for part of the journey can be determined by finding the area under the graph for a specific time interval

Area under a speed-time graph split into sections

Determining Distance on a V-T graph

The area under a speed-time graph can split into triangular and rectangular sections

Worked example

The speed-time graph below shows a car journey that lasts for 160 seconds.

1-2-4-worked-eg-1-cie-igcse-23-rn

Calculate the total distance travelled by the car on this journey.

Answer:

Step 1: Recall that the area under a velocity-time graph represents the distance travelled

  • In order to calculate the total distance travelled, the total area underneath the line must be determined

Step 2: Identify each enclosed area

  • In this example, there are five enclosed areas under the line
  • These can be labelled as areas 1, 2, 3, 4 and 5, as shown in the image below:

1-2-4-worked-eg-2-cie-igcse-23-rn

Step 3: Calculate the area of each enclosed shape under the line

  • Area 1 = area of a triangle

A subscript 1 space equals space 1 half b h

A subscript 1 space equals space 1 half space cross times space 40 space cross times space 17.5

A subscript 1 space equals space 350 space straight m

  • Area 2 = area of a rectangle

A subscript 2 space equals space b h

A subscript 2 space equals space 30 space cross times space 17.5

A subscript 2 space equals space 525 space straight m

  • Area 3 = area of a triangle

A subscript 3 space equals space 1 half b h

A subscript 3 space equals space 1 half space cross times space 20 space cross times space 7.5

A subscript 3 space equals space 75 space straight m

  • Area 4 = area of a rectangle

A subscript 4 space equals space b h

A subscript 4 space equals space 20 space cross times space 17.5

A subscript 4 space equals space 350 space straight m

  • Area 5 = area of a triangle

A subscript 5 space equals space 1 half b h

A subscript 5 space equals space 1 half space cross times space 70 space cross times space 25

A subscript 5 space equals space 875 space straight m

Step 4: Calculate the total distance travelled by finding the total area under the line

  • Add up each of the five areas enclosed:

total space distance space equals space A subscript 1 space plus space A subscript 2 space plus space A subscript 3 space plus space A subscript 4 space plus space A subscript 5

total space distance space equals space 350 space plus space 525 space plus space 75 space plus space 350 space plus space 875

total space distance space equals space 2175 space straight m

Examiner Tip

Some areas will need to be split into a triangle and a rectangle to determine the area for a specific time interval, like areas 3 & 4 in the worked example above.

If you are asked to find the distance travelled for a specific time interval, then you just need to find the area of the section above that time interval.

For example, the distance travelled between 70 s and 90 s is the sum of Area 3 + Area 4

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Leander

Author: Leander

Expertise: Physics

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.