Rate of Change of Momentum (Oxford AQA IGCSE Physics)

Revision Note

Leander Oates

Written by: Leander Oates

Reviewed by: Caroline Carroll

Rate of Change of Momentum

  • Newton's second law is defined by the equation:

F space equals space m space cross times space a

  • Momentum is calculated using the equation:

space p space equals space m space cross times space v

  • Combining these equations gives Newton's second law in terms of momentum:

F space equals space fraction numerator increment p over denominator t end fraction

  • Where:

    • F = resultant force measured in newtons (N)

    • p = change in momentum measured in kilogram metres per second (kg m/s)

    • t = time measured in seconds (s)

  • Remember to consider the direction of object's motion

    • If you take the initial direction as positive then the reverse direction is negative

  • Force is the rate of change of momentum on a body

    • Where the rate of change describes how a variable changes with respect to time

  • The shorter the time over which momentum changes then the bigger the force applied

  • So, force and time are inversely proportional to each other

Worked Example

A car of mass 1500 kg hits a wall at an initial velocity of 15 m/s and rebounds with a velocity of 5 m/s. The car is in contact with the wall for 3 seconds.

Calculate the average force experienced by the car and state the direction of the force.

Answer:

Step 1: List the known quantities

  • Mass of car, = 1500 kg

  • Velocity before collision, vi = 15 m/s

  • Velocity after collision, vf = 5 m/s

  • Time of impact, t = 3 s

Step 2: Draw a diagram of the collision

  • The diagram should include:

    • The velocity before and after the collision

    • The direction of motion before and after the collision

A car travels to the right at 15 metres per second. It collides with a wall and rebounds at 5 metres per second in the other direction

Step 3: Calculate the initial momentum of the car

p space equals space m space cross times space v

p subscript i space equals space 1500 space cross times space 15

 p subscript i space equals space 22 space 500 space kg space straight m divided by straight s

Step 4: Calculate the final momentum of the car

p subscript f space equals space m v

p subscript f space equals space 1500 space cross times space minus 5

 p subscript f space equals space minus 7500 space kg space straight m divided by straight s

Step 5: Calculate the change in momentum before and after the collision

straight capital delta p space equals space p subscript f space minus space p subscript i

straight capital delta p space equals space minus 7500 space minus space 22 space 500

straight capital delta p space equals space minus 30 space 000 space kg space straight m divided by straight s

Step 6: Calculate the force on the car and state the direction

F space equals space fraction numerator increment p over denominator t end fraction

F space equals space fraction numerator negative 30 space 000 over denominator 3 end fraction

F space equals space minus 10 space 000 space straight N

  • The minus sign means the direction of the force is to the left or in the opposite direction to the car's initial motion

Worked Example

A tennis ball hits a racket twice, with a change in momentum of 0.5 kg m/s both times.

During the first hit, the contact time is 2 s and during the second hit, the contact time is 0.1 s

By calculating both forces, determine which strike of the tennis racket experiences the greatest force from the tennis ball.

The first tennis racket is in contact with the ball for 2 seconds. The second tennis racket is in contact with the ball for 0.1 second.

Answer:

Step 1: Calculate the force during the first hit

F space equals space fraction numerator increment p over denominator t end fraction

F space equals space fraction numerator 0.5 over denominator 2 end fraction

F space equals space 0.25 space straight N

Step 2: Calculate the force during the second hit

F space equals space fraction numerator increment p over denominator t end fraction

F space equals space fraction numerator 0.5 over denominator 0.1 end fraction

F space equals space 5.0 space straight N

Step 3: State your answer

  • The tennis racket experiences the greatest force from the ball during the second hit

Momentum and safety

  • Since force is equal to the rate of change in momentum, the force of an impact in a vehicle collision can be decreased by increasing the contact time over which the collision occurs

    • Contact time is the period of time between the colliding objects first touching and the moment they lose contact or come to rest

Vehicles

  • Vehicle safety features are designed to absorb energy upon an impact by changing shape

  • The main vehicle safety features are crumple zonesseat belts and airbags

    • For a given force upon impact, these absorb the energy from the impact and increase the time over which the force takes place

    • This, in turn, increases the time taken for the change in momentum of the passenger and the vehicle to come to rest

    • The increased time reduces the force and risk of injury to a passenger

  • The usefulness of safety equipment depends on two main factors: mass and velocity

  • If the impact is from a large mass, for example, a truck travelling very fast and colliding with a wall, the momentum will be very large

    • The change in momentum (ie. from a high speed to rest) will also be very large

    • This means that a very long contact time is needed to reduce the force of impact

Safety features on a car

Car Safety Features for IGCSE & GCSE Physics revision notes
The seat belt, airbag and crumple zones help reduce the risk of injury on a passenger
  • Seat belts

    • These are designed to stop a passenger from colliding with the interior of a vehicle by keeping them fixed to their seat in an abrupt stop

    • They are designed to stretch slightly to increase the time for the passenger’s momentum to reach zero and reduce the force on them in a collision

  • Airbags

    • These are deployed at the front on the dashboard and steering wheel when a collision occurs

    • They act as a soft cushion to prevent injury on the passenger when they are thrown forward upon impact, increasing contact time

  • Crumple zones

    • These are designed into the exterior of vehicles

    • They are at the front and back and are designed to crush or crumple in a controlled way in a collision

    • This is why vehicles after a collision look more heavily damaged than expected, even for relatively small collisions

    • The crumple zones increase the time over which the vehicle comes to rest, lowering the impact force on the passengers

Crash mats

  • Crash mats used in gymnasiums help reduce the risk of injury for falls in gymnastics and climbing

    • They are thick and soft to offer shock absorption of the force created by the person landing on the mat

  • When a person lands on a crash mat with a large force, for example after jumping, the soft landing means their body is in contact with the mat for a longer period of time than if it was otherwise not there

  • This increases the contact time over which their momentum is reduced creating a smaller impact force and a lower chance of injury

Climber using a crash mat

A climber using a crash mat to cushion their fall for IGCSE & GCSE Physics revision notes
A bouldering mat is a type of crash mat used to reduce the chance of injury in falls whilst climbing
  • In a similar way, playgrounds utilise cushioned surfaces as children will often fall onto these with a large momentum

    • The cushioned surface reduces the risk of a severe injury by increasing their contact time with the ground

  • Meanwhile, a child in a gymnasium can use a thinner crash mat than an adult due to having a lower mass and therefore lower momentum for a given speed

  • This is the same for activities where a person/adult will fall with a low velocity such as falling from lower heights

    • Therefore, thin crash mats are suitable for low-impact activities

  • Safety features are intended to reduce the chance of serious injury but do not completely prevent it in all cases

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Leander Oates

Author: Leander Oates

Expertise: Physics

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.

Caroline Carroll

Author: Caroline Carroll

Expertise: Physics Subject Lead

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.