Force & Extension (Oxford AQA IGCSE Physics)

Revision Note

Force & Extension

  • When a force is applied to an elastic object such as a spring, the object will stretch

    • The object will store energy in its elastic potential store

  • The extension of an elastic object is directly proportional to the force applied, up to the limit of proportionality

    • Directly proportional means that if you change the value of one variable, the value of the other variable will change by the same proportion

      • So if you double the force, the extension will also double

    • The limit of proportionality is the point at which a stretched object will no longer return to its original shape when the force is removed

Force, load and extension of a spring

Load extension and force for IGCSE & GCSE Physics revision notes
A force applied to a spring will cause it to extend by an amount proportional to the force applied
  • The force applied to an elastic object can be calculated using:

F space equals space k space cross times space e

  • Where:

    • F = force in newtons (N)

    • k = spring constant in newtons per metre (N/m)

    • e = extension in metres (m)

  • This equation is known as Hooke's Law

  • You may need to rearrange this equation in the exam, a formula triangle can help

Formula triangle for force, extension, spring constant

Formula triangle with force on the top, extension and spring constant on the bottom
Simply cover up the variable you want to calculate and the formula triangle will show you the correct structure of the equation
  • The spring constant represents how stiff a spring is

    • The greater the spring constant, the greater the stiffness

  • The extension of an object can be calculated by:

Extension = final length – original length

  • The extension of the spring can be measured by marking the position of the bottom of the unstretched spring

  • When the spring is stretched, the final length must be measured from the bottom of the spring

Measuring the extension of a spring

Measuring the extension of a spring for IGCSE & GCSE Physics revision notes
The extension measured between the final and original length of the spring using a ruler

Worked Example

The figure below shows the forces acting on a child who is balancing on a pogo stick. The child and pogo stick are not moving.

Child on a pogo stick for IGCSE & GCSE Physics revision notes

The spring constant of the spring on the pogo stick is 4900 N/m. The weight of the child causes the spring to compress elastically from a length of 40 cm to a new length of 33 cm.

Calculate the weight of the child.

Answer:

Step 1: List the known quantities

  • Spring constant, k = 4900 N/m

  • Original length = 40 cm

  • Final length = 33 cm

Step 2: Write the relevant equation

F space equals space k space cross times space e

Step 3: Calculate the extension, e

e space equals space final space length space minus space original space length

e space equals space 40 space minus space 33

e space equals space 7 space cm

Step 4: Convert the units

  • Since the spring constant is given in N/m, the extension, e, must be in metres (m)

e space equals fraction numerator space 7 over denominator 100 end fraction

e space equals space 0.07 space straight m

Step 5: Substitute the known values into the equation

F space equals space 4900 space cross times space 0.07

F space equals space 343 space straight N

Examiner Tips and Tricks

Look out for unit conversions! Unless the spring constant is given in N/cm, make sure the extension is converted into metres (÷ 100) before substituting values into the equation.

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