Series Circuits (Oxford AQA IGCSE Physics)

Revision Note

Series Circuit

  • There are two ways of joining electrical components:

    • In series

    • In parallel

  • Some circuits include both series and parallel parts

  • For components connected in series:

    • the combined resistance is the sum of the resistance of each component

    • the current is the same in each component

    • the total potential difference of the power supply is shared between the components

    • The combined voltage of several sources in series is their sum

Current in series

  • In a series circuit, the current is the same value at any point

    • So all components have the same current

    • The number of electrons per second that pass through one part of the circuit is the same number that passes through any other part

Current is the same

In the series circuit the current through each ammeter is 0.3 A, for IGCSE & GCSE Physics revision notes
The current is the same at each point in a series circuit
  • The amount of current flowing in a series circuit depends on:

    • The voltage of the power source

    • The total resistance of the components

    • This is Ohm's law, but applied to the circuit as a whole

  • Increasing the voltage of the power source drives more current around the circuit

    • So, decreasing the voltage of the power source reduces the current

  • Increasing the number of components in the circuit increases the total resistance

    • Hence less current flows through the circuit

Increasing the voltage and number of components

Changing current in series circuits, for IGCSE & GCSE Physics revision notes
Current will increase if the voltage of the power supply increases and will decrease if the number of components increases

Voltage in series

  • The total potential difference of the power supply is shared between the components

Voltage is shared

The 12 V source of potential difference from the battery is shared evenly between the two lamps in the circuit
Lamps connected in a series circuit share the potential difference from the battery

Resistance in series

  • When two or more resistors are connected in series, the total resistance is equal to the sum of their individual resistances

  • For two resistors of resistance R1 and R2, the total resistance can be calculated using the equation:

R space equals space R subscript 1 space plus space R subscript 2

  • Where:

    •  R is the total resistance, in ohms (Ω)

  • Increasing the number of resistors increases the overall resistance

    • The charge now has more resistors to pass through

Resistance is increased

The total resistance of resistors connected in series is the sum of the resistance of each resistor
Resistors connected in series

Worked Example

The combined resistance R in the following series circuit is 60 Ω.

What is the resistance value of R2?

A.     100 Ω               B.     30 Ω               C.     20 Ω               D.     40 Ω

Answer: C

Step 1: Write down the equation for the combined resistance in series

R = R1 + R2 + R3

Step 2: Substitute the values for total resistance R and the other resistors

60 Ω = 30 Ω + R2 + 10 Ω

Step 3: Rearrange for R2

R2 = 60 Ω – 30 Ω – 10 Ω = 20 Ω

Worked Example

A student sets up a series circuit as shown below.

WE Series Circuit Question image, downloadable IGCSE & GCSE Physics revision notes

The cell supplies a current of 2 A to the circuit, and the fixed resistor has a resistance of 4 Ω.

(a) How much current flows through the fixed resistor?

(b) What is the reading on the voltmeter?

Answer:

Part (a)

Step 1: Recall that current is conserved in a series circuit

  • Since the current is conserved in a series circuit, it is the same size if measured anywhere in the series loop

  • This means that since the cell supplies 2 A to the circuit, the current is 2 A everywhere

  • Therefore, 2 A flows through the fixed resistor

Part (b)

Step 1: List the known quantities

  • Current I = 2 A

  • Resistance R = 4 Ω

Step 2: State the equation linking potential difference, resistance and current

  • The equation linking potential difference, resistance and current is:

V = IR

Step 3: Substitute the known values into the equation and calculate the potential difference

V = 2 × 4 = 8 V

  • Therefore, the voltmeter reads 8 V across the fixed resistor

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