The Principle of Moments (Edexcel IGCSE Physics (Modular))

Revision Note

Katie M

Author

Katie M

Expertise

Physics

The principle of moments

  • The principle of moments states that:

If an object is balanced, the total clockwise moment about a pivot equals the total anticlockwise moment about that pivot

  • For a balanced object, the moments on both sides of the pivot are equal 

clockwise moment = anticlockwise moment

Clockwise and anticlockwise moments

Clockwise and anticlockwise moments

Imagine holding the beam about the pivot and applying just one of the forces. If the beam moves clockwise then the force applied is clockwise.

  • In the example below, the forces and distances of the objects on the beam are different, but they are arranged in a way that balances the whole system

  • Remember that the moment = force × distance from a pivot

  • The forces should be perpendicular to the distance from the pivot

    • For example, on a horizontal beam, the forces which will cause a moment are those directed upwards or downwards

Using the principle of moments

The clockwise and anticlockwise moments acting on a beam are balanced

  • In the above diagram:

    • Force F subscript 1 causes an anticlockwise moment of F subscript 1 cross times d subscript 1 about the pivot 

    • Force F subscript 2 causes a clockwise moment of F subscript 2 cross times d subscript 2 about the pivot 

    • Force F subscript 3 causes an anticlockwise moment of F subscript 3 cross times d subscript 3 about the pivot

  • Collecting the clockwise and anticlockwise moments:

    • Sum of the clockwise moments = F subscript 2 cross times d subscript 2

    • Sum of the anticlockwise moments = open parentheses F subscript 1 cross times d subscript 1 close parentheses space plus space open parentheses F subscript 3 cross times d subscript 3 close parentheses

  • Using the principle of moments, the beam is balanced when:

Sum of the clockwise moments = Sum of the anticlockwise moments

F subscript 2 space cross times space d subscript 2 space equals space open parentheses F subscript 1 space cross times d subscript 1 close parentheses space plus space open parentheses F subscript 3 space cross times space d subscript 3 close parentheses

Worked Example

A parent and child are at opposite ends of a playground see-saw. The parent weighs 690 N and the child weighs 140 N. The adult sits 0.3 m from the pivot.

Principle of Moments Worked Example GCSE, downloadable IGCSE & GCSE Physics revision notes

Calculate the distance the child must sit from the pivot for the see-saw to be balanced.

Answer:

Step 1: List the known quantities

  • Clockwise force (child), Fchild = 140 N

  • Anticlockwise force (adult), Fadult = 690 N

  • Distance of adult from the pivot, dadult = 0.3 m

Step 2: Write down the relevant equation

  • Moments are calculated using:

Moment = force × distance from pivot

  • For the see-saw to balance, the principle of moments states that

Total clockwise moments = Total anticlockwise moments

Step 3: Calculate the total clockwise moments

  • The clockwise moment is from the child

Moment of child (clockwise) = Fchild × dchild

Moment of child (clockwise) = 140 × dchild

Step 4: Calculate the total anticlockwise moments

  • The anticlockwise moment is from the adult

Moment of adult (anticlockwise) = Fadult × dadult

Moment of adult (anticlockwise) = 690 × 0.3 = 207 N m

 Step 5: Substitute into the principle of moments equation

Moment of child (clockwise) = Moment of adult (anticlockwise)

140 × dchild = 207

Step 6: Rearrange for the distance of the child from the pivot

dchild207 over 140 = 1.5 m

  • The child must sit 1.5 m from the pivot to balance the see-saw

Exam Tip

Make sure that all the distances are in the same units and that you’re considering the correct forces as clockwise or anticlockwise.

In your IGCSE exam, you will only be expected to apply the principle of moments to a situation where an object rotates in one plane (up and down or side to side)

Supporting a beam

  • A light beam is one that can be treated as though it has no mass

  • The supports, therefore, must exert upward forces that balance the downward acting weight of any object placed on the beam

Supporting a Beam (1), downloadable IGCSE & GCSE Physics revision notes

F1 and F2 upwards balance the weight of the beam downwards

  • As the mass in the above diagram is moved from the left-hand side to the right-hand side of the beam, force F1 will decrease and force F2 will increase

Supporting a Beam (2), downloadable IGCSE & GCSE Physics revision notes

F1 decreases F2 increases keep the beam balanced

  • Consider what would happen to the beam if the right-hand support was removed:

    • Force F2 would be 0

    • The weight of the object would produce a moment about the left-hand support, causing the beam to pivot in a clockwise direction

Supporting a Beam (3), downloadable IGCSE & GCSE Physics revision notes

When F2 is removed the beam will rotate by the clockwise moment

  • Therefore, the force F2 must therefore supply an anticlockwise moment about the left-hand support, which balances the moment supplied by the object

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Katie M

Author: Katie M

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.