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Decay Equations (Edexcel IGCSE Physics)
Revision Note
Alpha, beta, gamma & neutron emission
Alpha decay
- During alpha decay, an alpha particle is emitted from an unstable nucleus
- A completely new element is formed in the process
Alpha decay usually happens in large unstable nuclei, causing the overall mass and charge of the nucleus to decrease
- An alpha particle is a helium nucleus
- It is made of 2 protons and 2 neutrons
- When the alpha particle is emitted from the unstable nucleus, the mass number and atomic number of the nucleus changes
- The mass number decreases by 4
- The atomic number decreases by 2
- Alpha decay can be represented by the following nuclear equation:
- Where:
- is the initial element X with mass number A and atomic number Z
- is the new element Y
- is an alpha particle
Beta decay
- During beta decay, a neutron changes into a proton and an electron
- The electron is emitted and the proton remains in the nuclei
- A completely new element is formed because the atomic number changes
Beta decay often happens in unstable nuclei that have too many neutrons. The mass number stays the same, but the atomic number increases by one
- A beta particle is a high-speed electron
- It has a mass number of 0
- This is because the electron has a negligible mass, compared to neutrons and protons
- Therefore, the mass number of the decaying nuclei remains the same
- Electrons have an atomic number of -1
- This means that the atomic number of the new nucleus will increase by 1 to balance the overall atomic number before and after the decay
- Beta decay can be represented by the following nuclear equation:
- Where:
- is the initial element X with mass number A and atomic number Z
- is the new element Y
- is a beta particle
Gamma decay
- During gamma decay, a gamma ray is emitted from an unstable nucleus
- This process makes the nucleus less energetic but does not change its structure
Gamma decay does not affect the mass number or the atomic number of the radioactive nucleus, but it does reduce the energy of the nucleus
- The gamma ray that is emitted has a lot of energy, but no mass or charge
- Gamma decay can be represented by the following nuclear equation:
- Where:
- is the element X with mass number A and atomic number Z
- is a gamma ray
- Notice that the mass number and atomic number of the unstable nucleus remains the same during the decay
Neutron emission
- A small number of isotopes can decay by emitting neutrons
- When a nucleus emits a neutron:
- The atomic number (number of protons) does not change
- The mass number (total number of nucleons) decreases by 1
- Neutron emission can be represented by the following nuclear equation:
- Where:
- is the element X with mass number A and atomic number Z
- is a neutron
- Notice that the atomic number remains the same during the decay but the mass number has changed
- This means an isotope of the original element has formed
Examiner Tip
It is easy to forget that an alpha particle is a helium nucleus. The two are interchangeable, so don’t be surprised to see either used in the exam.
You are not expected to know the names of the elements produced during radioactive decays, but you do need to be able to calculate the mass and atomic numbers by making sure they are balanced on either side of the reaction.
Nuclear decay equations
- Radioactive decay events can be shown using nuclear decay equations
- A decay equation is similar to a chemical reaction equation as
- the particles present before the decay are shown before the arrow
- the particles produced in the decay are shown after the arrow
- In a decay equation:
- the sum of the mass numbers before and after the reaction must be the same
- the sum of the atomic numbers before and after the reaction must be the same
- The following decay equation shows polonium-212 undergoing alpha decay
- When a nucleus of polonium-212 decays, a nucleus of lead-208 forms and an alpha particle is emitted
- To check if the equation is balanced:
- mass number: 212 = 208 + 4
- atomic number: 84 = 82 + 2
- The sum of the numbers are the same on each side, so the equation is balanced
Worked example
A nucleus with 84 protons and 126 neutrons undergoes alpha decay. It forms lead, which has the element symbol Pb.
A.
B.
C.
D.
Which of the isotopes of lead pictured is the correct one formed during the decay?
ANSWER: A
Step 1: Calculate the mass number of the original nucleus
- The mass number is equal to the number of protons plus the number of neutrons
- The original nucleus has 84 protons and 126 neutrons
84 + 126 = 210
- The mass number of the original nucleus is 210
Step 2: Calculate the new atomic number
- The alpha particle emitted is made of two protons and two neutrons
- Protons have an atomic number of 1, and neutrons have an atomic number of 0
- Removing two protons and two neutrons will reduce the atomic number by 2
84 – 2 = 82
- The new nucleus has an atomic number of 82
Step 3: Calculate the new mass number
- Protons and neutrons both have a mass number of 1
- Removing two protons and two neutrons will reduce the mass number by 4
210 – 4 = 206
- The new nucleus has a mass number of 206
Worked example
A nucleus with 11 protons and 13 neutrons undergoes beta decay. It forms magnesium, which has the element symbol Mg.
A.
B.
C.
D.
Which is the correct isotope of magnesium formed during the decay?
ANSWER: D
Step 1: Calculate the mass number of the original nucleus
- The mass number is equal to the number of protons plus the number of neutrons
- The original nucleus has 11 protons and 13 neutrons
11 + 13 = 24
- The mass number of the original nucleus is 24
Step 2: Calculate the new atomic number
- During beta decay a neutron changes into a proton and an electron
- The electron is emitted as a beta particle
- The neutron has an atomic number of 0 and the proton has an atomic number of 1
- So the atomic number increases by 1
11 + 1 = 12
- The new nucleus has an atomic number of 12
Step 3: Calculate the new mass number
- Protons and neutrons both have a mass number of 1
- Changing a neutron to a proton will not affect the mass number
- The new nucleus has a mass number of 24 (the same as before)
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