Pressure in Liquids (Edexcel IGCSE Physics)

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Katie M

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Katie M

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Pressure in liquids

  • A fluid is either a liquid or a gas

  • When an object is immersed and stationary in a fluid, the fluid will exert pressure, squeezing the object

    • This pressure is exerted evenly across the whole surface of the fluid and in all directions

    • The pressure exerted on objects in fluids creates forces against surfaces

    • These forces act at 90 degrees (at right angles) to the surface

Pressure in a liquid

pressure-&-force, IGCSE & GCSE Physics revision notes

The pressure of a fluid on an object creates a force normal (at right angles) to the surface

Calculating pressure in a liquid

  • The pressure acting on an object in a fluid changes with depth

    • The deeper the object then the higher the pressure exerted upon it and vice versa

  • The equation for the pressure difference, at different depths, in a fluid is given by the equation:

P space equals space h space cross times space rho space cross times space g

  • Where:

    • p = pressure in pascals (Pa)

    • h = height or depth of the fluid column above the object in metres (m)

    • ρ = density of the fluid in kilograms per metre cubed (kg/m3)

    • g = gravitational field strength on Earth in newtons per kilogram (N/kg)

Pressure in a liquid with a density is applied at a depth 

pressure-in-liquids, IGCSE & GCSE Physics revision notes

The force from the pressure of objects in a liquid is exerted evenly across its whole surface

Worked Example

Calculate the depth of water in a swimming pool where a pressure of 20 kPa is exerted. The density of water is 1000 kg/m3 and the gravitational field strength on Earth is 9.8 N/kg.

 

Answer:

Step 1: List the known quantities

  • Pressure, = 20 kPa

  • Density of water, ρ = 1000 kg/m3

  • Gravitational field strength, = 9.8 N/kg

Step 2: List the relevant equation

P space equals space h space cross times space rho space cross times space g

Step 3: Rearrange for height, h

h space equals space fraction numerator P over denominator rho space cross times space g end fraction

Step 4: Convert any units

20 space kPa space equals space 20 space 000 space Pa

Step 5: Substitute in the values

h space equals space fraction numerator 20 space 000 over denominator 1000 space cross times space 9.8 end fraction

h space equals space 2.0408 space equals space 2.0 space straight m

Examiner Tips and Tricks

This pressure equation will be given on your formula sheet, however, make sure you are comfortable with rearranging it for the variable required in the question!

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.