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Resistance (Edexcel IGCSE Physics)
Revision Note
Calculating current, resistance & potential difference
- Resistance is defined as
The opposition of a component to the flow of electric current through it
- Resistance is measured in units of ohms (Ω)
- A resistance of 1 Ω is equivalent to a voltage across a component of 1 V which produces a current of 1 A through it
- The resistance of a component controls the size of the current in a circuit
- For a given voltage across a component:
- The higher the resistance, the lower the current that can flow
- The lower the resistance, the higher the current that can flow
- All electrical components, including wires, have some value of resistance
- Wires are often made from copper because it has a low electrical resistance
- This is why it is known as a good conductor
Comparing current and resistance
A greater resistance means there is a lower current and vice versa
- The current, resistance and potential difference of a component in a circuit are calculated using the equation:
voltage = current × resistance
- Where:
- V = voltage, measured in volts (V)
- I = current, measured in amps (A)
- R = resistance, measured in ohms (Ω)
- This equation can be rearranged with the help of the following formula triangle:
Voltage current resistance formula triangle
Formula triangle for the voltage, current and resistance equation
- Check out this revision note on speed, distance and time if you need a reminder on how to use formula triangles
Worked example
Calculate the voltage across a resistor of resistance 10 Ω if there is a current of 0.3 A through it.
Answer:
Step 1: List the known quantities
- Resistance, R = 10 Ω
- Current, I = 0.3 A
Step 2: Write the equation relating resistance, potential difference and current
Step 3: Substitute in the values
V = 0.3 × 10 = 3 V
Examiner Tip
In exam questions, the resistance of the wires, batteries, ammeters and voltmeters are always assumed to be zero (in the case of voltmeters, they have extremely high resistances so that current does not flow through them, and this has a negligible effect on the overall resistance of the circuit)
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