Radioactive Decay (Cambridge (CIE) IGCSE Physics)

Revision Note

Ashika

Written by: Ashika

Reviewed by: Caroline Carroll

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Effect of nuclear size on decay

Extended tier only

  • Isotopes of an element may be radioactive due to an excess of neutrons in the nucleus and/or the nucleus being too heavy

Excess of neutrons

  • The most stable nuclei have roughly the same number of protons as neutrons

  • Too many protons in a nucleus means the repulsive force between them is large, causing the neutrons to repel each other

  • So, a nucleus with an imbalance of protons or neutrons is more likely to decay into several smaller nuclei until stable nuclei are obtained

    • With roughly the same number of nucleons in each nucleus

  • An example of this is the isotope of hydrogen–1

    • H-1 is the stable nucleus of hydrogen with 0 neutrons and 1 proton

    • H-2 (deuterium) has one more neutron in the nucleus

    • H-3 (tritium) has 2 neutrons to 1 proton. This is much more unstable than H-1 or H-2

Hydrogen isotopes

Defining Isotopes table

Heavy nucleus

  • If a nucleus is too heavy, this means it has too many protons and neutrons

    • The forces keeping the protons and neutrons together in the nucleus will be weaker

  • An example of this is uranium–238

    • It has a nucleus with 238 protons and neutrons

  • During nuclear decay, the mass number of the element which it decays into is gradually reduced

    • This is done through alpha (α) or beta (β) decay

Uranium–238 decay chain

Uranium Decay Chain

The graph shows the decay chain of uranium-238 through alpha and beta emission

Examiner Tips and Tricks

The notation of C-12 for example, means the element 'carbon' with the mass (or nucleon) number of 12.

Change to a new element

  • A nucleus changes to a different element, during α-decay or β-decay

    • The initial nucleus is often called the parent nucleus

    • The nucleus of the new element produced is often called the daughter nucleus

  • The daughter nucleus is a new element because it has a different proton and/or nucleon number than the original parent nucleus

  • This can be seen on a graph of N (neutron number) against Z (proton number)

    • For example; when Pu-239 decays by alpha to U-235, it loses 2 protons and 2 neutrons

    • U (uranium) is a completely different element from Pu (plutonium)

Graph of neutron number against proton number

WE - NZ Decay Graph

Graph of N against Z for the decay of Pu239

Reducing neutron number

Extended tier only

  • α and β-decay affect the nucleus by

    • increasing its stability

    • reducing the number of excess neutrons

Alpha decay

  • During alpha decay an alpha particle is emitted from an unstable nucleus

  • A completely new element is formed in the process

Alpha decay

Alpha decay diagram, downloadable AS & A Level Physics revision notes

Alpha decay usually happens in large unstable nuclei, causing the overall mass and charge of the nucleus to decrease

  • An alpha particle is a helium nucleus

    • It is made of 2 protons and 2 neutrons

  • When the alpha particle is emitted from the unstable nucleus, the mass number and atomic number of the nucleus changes

    • The mass number decreases by 4

    • The atomic number decreases by 2

  • The charge on the nucleus also decreases by 2

    • This is because protons have a charge of +1 each

Beta decay

  • During beta decay, a neutron changes into a proton and an electron

    • The electron is emitted and the proton remains in the nucleus

  • A completely new element is formed because the atomic number changes

Beta decay

Beta decay

Beta decay often happens in unstable nuclei that have too many neutrons. The mass number stays the same, but the atomic number increases by one

  • A beta particle is a high-speed electron

  • It has a mass number of 0

    • This is because the electron has a negligible mass, compared to neutrons and protons

  • Therefore, the mass number of the decaying nucleus remains the same

  • Electrons have an atomic number of -1

    • This means that the new nuclei will increase their atomic number by 1 so atomic number is conserved before and after the decay

Gamma decay

  • During gamma decay, a gamma ray is emitted from an unstable nucleus

    • This process makes the nucleus less energetic but does not change its structure because gamma radiation has no mass or charge

Gamma decay

Gamma decay, downloadable IGCSE & GCSE Physics revision notes

Gamma decay does not affect the mass number or the atomic number of the radioactive nucleus, but it does reduce the energy of the nucleus

Examiner Tips and Tricks

There is a second form of beta decay during which a proton changes into a neutron. This is called beta-plus decay - you might come across it while revising, but you don't need to know about it for your exam. Only use the information here for your iGCSE.

It is easy to forget that an alpha particle is a helium nucleus, or that a beta particle is an electron. Look out for either wording! 

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Decay equations

Extended tier only

  • Decay equations, use nuclide notation, to show the emission of α-particles, β-particles and γ-radiation

  • A decay equation is similar to a chemical reaction equation

    • The particles present before the decay are shown before the arrow

    • The particles produced in the decay are shown after the arrow

  • During decay equations, the sum of the mass and atomic numbers before the reaction must be the same as the sum of the mass and atomic numbers after the reaction

Alpha decay equation

  • All alpha decay equations have the following form for isotopes X and Y:

straight X presubscript straight Z presuperscript straight A space rightwards arrow space straight Y presubscript straight Z space minus space 2 end presubscript presuperscript straight A space minus space 4 end presuperscript space plus space straight alpha presubscript 2 presuperscript 4

  • The following decay equation shows polonium-212 undergoing alpha decay

    • It forms lead-208 and an alpha particle

    • An alpha particle can also be written as a helium (He) nucleus 

    Po presubscript 84 presuperscript 212 space rightwards arrow space Pb presubscript 82 presuperscript 208 space plus space straight alpha presubscript 2 presuperscript 4

Beta decay equation

  • All beta decay equations have the following form for isotopes X and Y:

straight X presubscript straight Z presuperscript straight A space rightwards arrow space straight Y presubscript straight Z space plus space 1 end presubscript presuperscript straight A space plus space straight beta presubscript negative 1 end presubscript presuperscript 0

Gamma decay equation

  • All gamma decay equations have the following form for isotope X

straight X presubscript straight Z presuperscript straight A space rightwards arrow space straight X presubscript straight Z presuperscript straight A space plus space straight gamma presubscript 0 presuperscript 0

Worked Example

A nucleus with 84 protons and 126 neutrons undergoes alpha decay. It forms lead, which has the element symbol Pb.

A  Pb presubscript 82 presuperscript 206

B  Pb presubscript 82 presuperscript 208

C  Pb presubscript 84 presuperscript 210

D  Pb presubscript 86 presuperscript 214

Which isotope of lead pictured is the correct one formed during the decay?

 

Answer: A

Step 1: Calculate the mass number of the original nucleus

  • The mass number is equal to the number of protons plus the number of neutrons

  • The original nucleus has 84 protons and 126 neutrons

84 space plus space 126 space equals space 210

  • The mass number of the original nucleus is 210

Step 2: Calculate the new atomic number

  • The alpha particle emitted is made of two protons and two neutrons

  • Protons have an atomic number of 1, and neutrons have an atomic number of 0

  • Removing two protons and two neutrons will reduce the atomic number by 2

84 space – space 2 space equals space 82

  • The new nucleus has an atomic number of 82

Step 3: Calculate the new mass number

  • Protons and neutrons both have a mass number of 1

  • Removing two protons and two neutrons will reduce the mass number by 4

210 space – space 4 space equals space 206

  • The new nucleus has a mass number of 206

Worked Example

A nucleus with 11 protons and 13 neutrons undergoes beta decay. It forms magnesium, which has the element symbol Mg.

A  Mg presubscript 9 presuperscript 20

B  Mg presubscript 10 presuperscript 24

C  Mg presubscript 11 presuperscript 23

D  Mg presubscript 12 presuperscript 24

Which is the correct isotope of magnesium formed during the decay?

 

Answer: D

Step 1: Calculate the mass number of the original nucleus

  • The mass number is equal to the number of protons plus the number of neutrons

  • The original nucleus has 11 protons and 13 neutrons

11 space plus space 13 space equals space 24

  • The mass number of the original nucleus is 24

Step 2: Calculate the new atomic number

  • During beta decay a neutron changes into a proton and an electron

  • The electron is emitted as a beta particle

  • The neutron has an atomic number of 0 and the proton has an atomic number of 1

  • So the atomic number increases by 1

11 space plus space 1 space equals space 12

  • The new nucleus has an atomic number of 12

Step 3: Calculate the new mass number

  • Protons and neutrons both have a mass number of 1

  • Changing a neutron to a proton will not affect the mass number

  • The new nucleus has a mass number of 24 (the same as before)

Examiner Tips and Tricks

You are not expected to know the names of the elements produced during radioactive decays, but you do need to be able to calculate the mass and atomic numbers by making sure they are balanced on either side of the reaction.

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Ashika

Author: Ashika

Expertise: Physics Project Lead

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Caroline Carroll

Author: Caroline Carroll

Expertise: Physics Subject Lead

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.