Total Internal Reflection (Cambridge (CIE) IGCSE Physics)

Revision Note

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Did this video help you?

Total internal reflection

  • Total internal reflection (TIR) occurs at the boundary between two media when:

All the incident ray in medium 1 is reflected back into medium 1

  • When light passes between the boundary of an optically dense to a less dense medium and the angles of incidence are small

    • The refracted ray is strong

    • The reflected ray is weak

  • The weak ray is reflected back into the denser medium

    • This means some internal reflection occurs

  • It is not TIR because not all of the ray is reflected, only some of it

Comparing refraction and total internal reflection

total-internal-reflection

Refraction happens when the angle of incidence is smaller and total internal reflection happens when the angle of incidence equals the angle of reflection

Comparing internal reflection and total internal reflection

  • Normal reflection produces a less intense light compared to TIR

    • In TIR the light ray is brighter and more intense

  • Normal reflection occurs independent of the refractive indices of both media

    • For TIR to occur, the incident material must be denser than the second material

Conditions for internal reflection

internal-reflection

Total internal reflection happens with the angle of incidence is bigger than the critical angle

Internal reflection examples

  • Thin film interference is an example of internal reflection

  • An example of this is the shiny side of a CD

Example of internal reflection

9-3-5-thin-film-interference-cd

The colourful pattern observed on a CD is a result of thin film interference

  • Other examples of thin film interference include:

    • Soap bubbles

    • Thin layers of oil on water

  • In these examples, internal reflection occurs at the boundaries between:

    • Air and water

    • Water and oil

  • A spectrum of colours will be seen by the observer due to the rays partially reflected at the boundary

A ray diagram of an example of internal reflection

9-3-5-oil-and-water-example

Light is reflected and transmitted at the boundary from a less dense to a more dense material. Light is transmitted only at the boundary from a more dense to a less dense material. Hence, in this diagram P and Q exist but the third unlabelled ray does not.

Total internal reflection examples

  • Total internal reflection is used to reflect light along optical fibres, meaning they can be used for

    • communications

    • endoscopes

    • decorative lamps

  • Light travelling down an optical fibre is totally internally reflected each time it hits the edge of the fibre

Total internal reflection example: optical fibre

Optical fibres, IGCSE & GCSE Physics revision notes

Optical fibres utilise total internal reflection for communications

  • Prisms are used in a variety of optical instruments, including:

    • Periscopes

    • Binoculars

    • Telescopes

    • Cameras

    • Safety reflectors

  • A periscope is a device that can be used to see over tall objects

    • It consists of two right-angled prisms

    Total internal reflection example: a periscope

Periscope, downloadable IGCSE & GCSE Physics revision notes

Reflection of light through a periscope

  • The light totally internally reflects in both prisms

Examiner Tips and Tricks

If asked to name the phenomena make sure you give the whole name – total internal reflection

Remember: total internal reflection occurs when light travels from a denser material to less dense material and ALL of the light is reflected.

If asked to give an example of a use of total internal reflection, first state the name of the object that causes the reflection (e.g. a right-angled prism) and then name the device in which it is used (e.g. a periscope)

Critical angle

  • At the boundary between a more dense and a less dense medium, as the angle of incidence is increased, the angle of refraction also increases until it gets closer to 90°

  • When the angle of refraction is exactly 90° the light is refracted along the boundary

    • At this point, the angle of incidence is known as the critical angle c

Obtaining total internal reflection examples

total-internal-reflection-new

As the angle of incidence increases it will eventually surplus the critical angle and lead to total internal reflection of the light

  • When the angle of incidence is larger than the critical angle, the refracted ray is now reflected

    • This is total internal reflection

Worked Example

A glass cube is held in contact with a liquid and a light ray is directed at a vertical face of the cube. The angle of incidence at the vertical face is 39° and the angle of refraction is 25° as shown in the diagram. The light ray is totally internally reflected for the first time at X.

Total Internal Reflection Worked Example (1), downloadable AS & A Level Physics revision notes

Complete the diagram to show the path of the ray beyond X to the air and calculate the critical angle for the glass-liquid boundary.

 

Answer:

Total Internal Reflection Worked Example (2), downloadable AS & A Level Physics revision notes

Step 1: Draw the reflected angle at the glass-liquid boundary

  • When a light ray is reflected, the angle of incidence = angle of reflection

  • Therefore, the angle of incidence (or reflection) is 90° – 25° = 65°

Step 2: Draw the refracted angle at the glass-air boundary

  • At the glass-air boundary, the light ray refracts away from the normal

  • Due to the reflection, the light rays are symmetrical to the other side

Step 3: Calculate the critical angle

  • The question states the ray is “totally internally reflected for the first time” meaning that this is the lowest angle at which TIR occurs

  • Therefore, 65° is the critical angle

Examiner Tips and Tricks

If you are asked to explain what is meant by the critical angle in an exam, you can be sure to gain full marks by drawing and labelling the same diagram above (showing the three semi-circular blocks)

Refractive index & critical angle equation

Extended tier only

  • The critical angle, c, of a material, is related to its refractive index, n

  • The relationship between the two quantities is given by the equation:

sin space c space equals space 1 over n

  • This can also be rearranged to calculate the refractive index, n:

n space equals space fraction numerator 1 over denominator sin space c end fraction

  • This equation shows that:

    • The larger the refractive index of a material, the smaller the critical angle

    • Light rays inside a material with a high refractive index are more likely to be totally internally reflected

Worked Example

Opals and diamonds are transparent stones used in jewellery. Jewellers shape the stones so that light is reflected inside. Compare the critical angles of opal and diamond and explain which stone would appear to sparkle more.

The refractive index of opal is about 1.5

The refractive index of diamond is about 2.4

 

Answer:

Step 1: List the known quantities

  • Refractive index of opal, no = 1.5

  • Refractive index of diamond, nd = 2.4

Step 2: Write out the equation relating critical angle and refractive index

sin space c space equals space 1 over n

Step 3: Calculate the critical angle of opal (co)

sin left parenthesis c subscript o right parenthesis space equals space fraction numerator 1 over denominator 1.5 end fraction space equals space 0.6667

c subscript o space equals space sin to the power of negative 1 end exponent space left parenthesis 0.6667 right parenthesis space equals space 41.8 space equals space 42 degree

Step 4: Calculate the critical angle of diamond (cd)

sin left parenthesis c subscript d right parenthesis space equals space fraction numerator 1 over denominator 2.4 end fraction space equals space 0.4167

c subscript d space equals space sin to the power of – 1 end exponent space left parenthesis 0.4167 right parenthesis space equals space 24.6 space equals space 25 degree

Step 5: Compare the two values and write a conclusion

  • Total internal reflection occurs when the angle of incidence of light is larger than the critical angle (i > c)

  • In opal, total internal reflection will occur for angles of incidence between 42° and 90°

  • The critical angle of diamond is lower than the critical angle of opal (co > cd)

  • This means light rays will be totally internally reflected in diamond over a larger range of angles (25° to 90°)

  • Therefore, more total internal reflection will occur in diamond hence it will appear to sparkle more than the opal

Examiner Tips and Tricks

When calculating the value of the critical angle using the above equation:

  • First use the refractive index, n, to find sin(c)

  • Then use the inverse sin function (sin–1) to find the value of c

Optical fibres

Extended tier only

  • Optical fibres have many uses, particularly in telecommunications

  • Endoscopes are used to look within the human body

    • A camera on the end of an optical fibre is placed down the throat and moved into the stomach

    • Light from inside the stomach is captured by the camera, is totally internally reflected along the optical fibre and viewed by doctors through the eyepiece

Total internal reflection example: endoscope

Endoscope, IGCSE & GCSE Physics revision notes

Endoscopes utilise total internal reflection to see inside a patient's body

Total internal reflection using telecommunication

  • Optical fibres can be used to transmit:

    • Home (landline) telephone signals

    • Internet signals

    • Cable television signals

  • In phone calls from landline phones:

    • Electrical signals are converted to light pulses

    • That travel close to the speed of light along optical fibres

    • At the receiving end, the digital signal is converted into sound

Total internal reflection example: landline telephone signal path

1-6-landline-phone-signal-path

Sound from a landline telephone travels through optical fibres to the landline of the person listening

  • Optical fibres are installed:

    • In cables attached to telephone (or telegraph) poles in the street

    • Underground from the service box to the telegraph pole or under the sea

Total internal reflection example: telegraph poles

1-6-telegraph-pole

Fibre optic cables can be found in the phone cables attached between the telephone poles and the street

Last updated:

You've read 0 of your 10 free revision notes

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Author: Caroline Carroll

Expertise: Physics Subject Lead

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.