Refractive Index (Cambridge (CIE) IGCSE Physics)

Revision Note

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

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Refractive index as a ratio of speed

Extended tier only

  • The refractive index can be calculated in two different ways:

  1. Using the ratio of speeds

  2. Using the ratio of angles

  • The refractive index is a number that is always larger than 1 and is different for different materials

    • Objects which are more optically dense have a higher refractive index, e.g. n is about 2.4 for diamond

    • Objects which are less optically dense have a lower refractive index, e.g. n is about 1.5 for glass

  • Since the refractive index is a ratio, it has no units

  • The refractive index, n, for the ratio of speeds, is defined as:

The ratio of the speeds of a wave in two different regions

  • The refractive index, n, for the ratio of speeds, is given by the equation:

n space equals space fraction numerator speed space of space light space in space straight a space vacuum over denominator speed space of space light space in space straight a space material end fraction

Refractive index as a ratio of angles

Extended tier only

  • The refractive index, n, for the ratio of angles, is defined as:

The ratio of the sine of the angle of incidence and the sine of the angle of reflection of a wave in two different regions

  • The refractive index, n, for the ratio of angles, is given by the equation:

n space equals space fraction numerator sin space i over denominator sin space r end fraction

  • Where:

    • n = the refractive index of the material

    • i = angle of incidence of the light (°)

    • r = angle of refraction of the light (°)

  • This equation can be rearranged with the help of the formula triangle:

A refractive index formula triangle

Snell triangle (2), IGCSE & GCSE Physics revision notes

Formula triangle for the refractive index in terms of angles

  • See the example of Speed & velocity which explains how to use the formula triangle to rearrange equations

Worked Example

A ray of light enters a glass block of refractive index 1.53 making an angle of 15° with the normal before entering the block.

Calculate the angle it makes with the normal after it enters the glass block.

 

Answer:

Step 1: List the known quantities

  • Refractive index of glass, n = 1.53

  • Angle of incidence, i = 15°

Step 2: Write the equation for refractive index in terms of the ratio of angles

n space equals space fraction numerator sin space i over denominator sin space r end fraction

Step 3: Rearrange the equation and calculate sin (r)

sin space r space equals space fraction numerator sin space i over denominator n end fraction

sin space r space equals space fraction numerator sin space 15 over denominator 1.53 end fraction space

sin space r space equals space 0.1692

Step 4: Find the angle of refraction (r) by using the inverse sin function

r space equals space sin to the power of negative 1 end exponent space left parenthesis 0.1692 right parenthesis space

r space equals space 9.7 space equals space 10 degree

Examiner Tips and Tricks

n space equals space fraction numerator sin space i over denominator sin space r end fraction is also known as Snell's law but you do not need to know this for your exam.

Important: (fraction numerator sin space i space over denominator sin space r end fraction) is not the same as (i over r). Incorrectly cancelling the sin terms is a very common mistake!

When calculating the value of i or r start by calculating the value of sin i or sin r.

You can then use the inverse sin function (sin–1 on most calculators by pressing 'shift' then 'sine') to find the angle.

One way to remember which way around i and r are in the fraction is remembering that 'i' comes before 'r' in the alphabet, and therefore is on the top of the fraction (whilst r is on the bottom).

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Author: Caroline Carroll

Expertise: Physics Subject Lead

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.